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Consider transient heat conduction in a plane wall with variable heat generation and constant thermal conductivity. The nodal network of the medium consists of nodes \(0,1,2,3\), and 4 with a uniform nodal spacing of \(\Delta x\). The wall is initially at a specified temperature. The temperature at the right boundary (node 4) is specified. Using the energy balance approach, obtain the explicit finite difference formulation of the boundary node 0 for the case of combined convection, radiation, and heat flux at the left boundary with an emissivity of \(\varepsilon\), convection coefficient of \(h\), ambient temperature of \(T_{\infty}\), surrounding temperature of \(T_{\text {surr }}\), and uniform heat flux of \(\dot{q}_{0}\) toward the wall. Also, obtain the finite difference formulation for the total amount of heat transfer at the right boundary for the first 20 time steps.

Short Answer

Expert verified
Answer: The main approach used to solve this problem is the energy balance method, which involves writing an energy balance equation for Node 0, expressing the heat transfer terms, rearranging the equation to obtain the finite difference equation for Node 0, and then calculating the total heat transfer at the right boundary for the first 20 time steps.

Step by step solution

01

Write the energy balance equation for Node 0

The energy balance equation for Node 0 can be written as: Energy balance: \(q_{\text{in}} - q_{\text{out}} = \textrm{Accumulated energy} + \textrm{Generated energy}\) For Node 0, the energy balance equation can be written as: \[\dot{q}_{0} + q_{\text{conv}} + q_{\text{rad}} - q_{\text{cond}} = \rho c_{p} V\frac{\Delta T_{i}}{\Delta t} + g\], Where \(i=0\) and \(g\) is the heat generation.
02

Write the expressions for heat transfer and accumulated energy

Express the heat transfer terms as follows: 1. Conduction heat transfer: \[q_{\text{cond}} = k\frac{T_{1} - T_{0}}{\Delta x}\], 2. Convection heat transfer: \[q_{\text{conv}} = h(T_{0} - T_{\infty})\], 3. Radiation heat transfer: \[q_{\text{rad}} = \varepsilon \sigma_{SB}(T_{0}^4 - T_{\text{surr}}^4)\], 4. Accumulated energy in Node 0: \[\textrm{Accumulated energy} = \rho c_{p} V\frac{\Delta T_{i}}{\Delta t}\], with \(i=0\).
03

Substitute heat transfer terms in the energy balance equation

Now, replace the heat transfer terms in the energy balance equation: \[\dot{q}_{0} + h(T_{0} - T_{\infty}) + \varepsilon \sigma_SB(T_0^4 - T_{\text{surr}}^4) - k\frac{T_{1} - T_{0}}{\Delta x} = \rho c_p V\frac{\Delta T_0}{\Delta t} + g\]
04

Rearrange the equation to get the finite difference equation for Node 0

Rearrange the equation to get the finite difference equation for \(\Delta T_0\): \[\Delta T_0 = \frac{\Delta t}{\rho c_p V}(k\frac{T_{1} - T_{0}}{\Delta x} - h(T_{0} - T_{\infty}) - \varepsilon \sigma_SB(T_0^4 - T_{\text{surr}}^4) - \dot{q}_{0} + g)\]
05

Calculate the total heat transfer at the right boundary for the first 20 time steps

For the first 20 time steps (n=1 to 20): 1. Calculate the updated \(\Delta T_0\) using the given boundary conditions and the finite difference equation obtained in Step 4, 2. Update the temperature values for all nodes, 3. Calculate the heat transfer at the right boundary (Node 4) for each time step using the updated temperature values, 4. Sum up the heat transfer for each time step to obtain the total heat transfer at the right boundary for the first 20 time steps. By following the above steps, the explicit finite difference formulation for Node 0 and the heat transfer for the first 20 time steps at the right boundary can be determined.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transient Heat Conduction
In the realm of heat conduction, transient heat conduction refers to the phenomenon where temperature varies with both time and position within a medium. This is different from steady-state heat conduction, where temperatures are only dependent on position and do not change over time. Transient heat conduction is crucial in engineering applications because it allows us to understand temperature changes within a material over time.

In our exercise, we consider a plane wall system with an initial uniform temperature throughout. The wall undergoes transient heat conduction due to its exposure to various heat transfer mechanisms like convection and radiation. These mechanisms cause the temperature at specific points (nodes) to vary as time progresses, necessitating a time-dependent analysis.

By addressing and calculating the temperature change at each time step across specific nodes, engineers can predict how systems respond to various thermal conditions over time. This time-dependent analysis tells us a lot about the material's thermal behavior, allowing for better design and material selection in engineering projects.
Energy Balance Equation
The energy balance equation is at the heart of understanding heat conduction in materials. It’s an expression that ensures that the net energy entering a node equals the energy stored plus energy generated within that node. This equation forms the basis of the explicit finite difference method, allowing for the computation of temperature changes at discrete time intervals.

In the specific context of our exercise for Node 0, the energy balance equation incorporates several heat transfer terms. These include the heat flux entering the node, heat lost through conduction and convection, as well as radiation losses. By summing all these forms of energy, we derive an equation that equates the left side (energy inputs and outputs) and the right side (energy accumulation and generation).

Understanding the energy balance equation is critical because it helps predict how temperature fields adjust over time. By solving it, one predicts the temperature distribution, revealing how effective different heat management strategies are. This technique is fundamental to maintaining safe and efficient operating conditions in various engineering settings.
Heat Transfer Mechanisms
Heat transfer mechanisms describe how heat energy moves from one area to another within the plane wall system. In the explicit finite difference method, we address three main heat transfer types: conduction, convection, and radiation.

- **Conduction** is the transfer of heat through the material itself. In the exercise, it is calculated between adjacent nodes, depending on their temperature difference and the thermal conductivity of the material. - **Convection** is the heat transfer due to the motion of a fluid like air or water over the surface. It typically involves a heat transfer coefficient and the temperature difference between the solid surface and the surrounding fluid. - **Radiation** is energy transfer through electromagnetic waves, usually significant at higher temperatures. In the given plane wall, it involves the emissivity, Stefan-Boltzmann constant, and the temperature difference raised to the fourth power.

By accurately modeling these heat transfer mechanisms, engineers ensure that materials are subjected to the intended thermal loads. Proper modeling allows for the optimization of heat management strategies over time.
Boundary Conditions
Boundary conditions specify how the system interacts with its surroundings and are critical in solving heat conduction problems. They dictate the temperature or heat flux at specific boundaries, affecting how heat flows within the material.

In our exercise, Node 0 and Node 4 are influenced by specific boundary conditions: - **Node 0 (left boundary):** It experiences combined effects of convection, radiation, and a uniform heat flux. Each of these aspects adds complexity to the energy balance equation by introducing different forms of heat exchange with the environment. - **Node 4 (right boundary):** This node has a specified temperature, meaning it either gains or loses heat to maintain that temperature, influencing the interior nodes based on the given conditions.

Addressing boundary conditions correctly is crucial for realistic simulations of thermal behavior. Accurate boundary conditions ensure that the calculations reflect true physical processes, allowing reliable predictions of the system's thermal responses in real-world applications.

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Most popular questions from this chapter

The wall of a heat exchanger separates hot water at \(T_{A}=90^{\circ} \mathrm{C}\) from cold water at \(T_{B}=10^{\circ} \mathrm{C}\). To extend the heat transfer area, two-dimensional ridges are machined on the cold side of the wall, as shown in Fig. P5-76. This geometry causes non-uniform thermal stresses, which may become critical for crack initiation along the lines between two ridges. To predict thermal stresses, the temperature field inside the wall must be determined. Convection coefficients are high enough so that the surface temperature is equal to that of the water on each side of the wall. (a) Identify the smallest section of the wall that can be analyzed in order to find the temperature field in the whole wall. (b) For the domain found in part \((a)\), construct a twodimensional grid with \(\Delta x=\Delta y=5 \mathrm{~mm}\) and write the matrix equation \(A T=C\) (elements of matrices \(A\) and \(C\) must be numbers). Do not solve for \(T\). (c) A thermocouple mounted at point \(M\) reads \(46.9^{\circ} \mathrm{C}\). Determine the other unknown temperatures in the grid defined in part (b).

Consider steady one-dimensional heat conduction in a plane wall with variable heat generation and constant thermal conductivity. The nodal network of the medium consists of nodes \(0,1,2,3\), and 4 with a uniform nodal spacing of \(\Delta x\). Using the finite difference form of the first derivative (not the energy balance approach), obtain the finite difference formulation of the boundary nodes for the case of uniform heat flux \(q_{0}\) at the left boundary (node 0 ) and convection at the right boundary (node 4) with a convection coefficient of \(h\) and an ambient temperature of \(T_{\infty}\).

Using EES (or other) software, solve these systems of algebraic equations. (a) $$ \begin{aligned} 3 x_{1}+2 x_{2}-x_{3}+x_{4} &=6 \\ x_{1}+2 x_{2}-x_{4} &=-3 \\ -2 x_{1}+x_{2}+3 x_{3}+x_{4} &=2 \\ 3 x_{2}+x_{3}-4 x_{4} &=-6 \end{aligned} $$ (b) $$ \begin{aligned} 3 x_{1}+x_{2}^{2}+2 x_{3} &=8 \\ -x_{1}^{2}+3 x_{2}+2 x_{3} &=-6.293 \\ 2 x_{1}-x_{2}^{4}+4 x_{3} &=-12 \end{aligned} $$

A common annoyance in cars in winter months is the formation of fog on the glass surfaces that blocks the view. A practical way of solving this problem is to blow hot air or to attach electric resistance heaters to the inner surfaces. Consider the rear window of a car that consists of a \(0.4\)-cm-thick glass \(\left(k=0.84 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\right.\) and \(\left.\alpha=0.39 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)\). Strip heater wires of negligible thickness are attached to the inner surface of the glass, \(4 \mathrm{~cm}\) apart. Each wire generates heat at a rate of \(25 \mathrm{~W} / \mathrm{m}\) length. Initially the entire car, including its windows, is at the outdoor temperature of \(T_{o}=-3^{\circ} \mathrm{C}\). The heat transfer coefficients at the inner and outer surfaces of the glass can be taken to be \(h_{i}=6\) and \(h_{o}=20 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), respectively. Using the explicit finite difference method with a mesh size of \(\Delta x=\) \(0.2 \mathrm{~cm}\) along the thickness and \(\Delta y=1 \mathrm{~cm}\) in the direction normal to the heater wires, determine the temperature distribution throughout the glass \(15 \mathrm{~min}\) after the strip heaters are turned on. Also, determine the temperature distribution when steady conditions are reached.

Consider a medium in which the finite difference formulation of a general interior node is given in its simplest form as $$ T_{\text {node }}=\left(T_{\text {left }}+T_{\text {top }}+T_{\text {right }}+T_{\text {bottom }}\right) / 4 $$ (a) Is heat transfer in this medium steady or transient? (b) Is heat transfer one-, two-, or three-dimensional? (c) Is there heat generation in the medium? (d) Is the nodal spacing constant or variable? (e) Is the thermal conductivity of the medium constant or variable?

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