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A plane brick wall \((k=0.7 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is \(10 \mathrm{~cm}\) thick. The thermal resistance of this wall per unit of wall area is (a) \(0.143 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (b) \(0.250 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (c) \(0.327 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (d) \(0.448 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (e) \(0.524 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\)

Short Answer

Expert verified
Answer: (a) 0.143 m²K/W

Step by step solution

01

Convert wall thickness to meters

As the wall thickness is given in centimeters, we should convert it to meters: $$ 10\,\text{cm} \times \frac{1\,\text{m}}{100\,\text{cm}} = 0.1\,\text{m} $$
02

Use the formula to find thermal resistance per unit area

We will use the formula R/A = L/k. In our case, L = 0.1 m and k = 0.7 W/mK. $$ \frac{R}{A} = \frac{0.1\,\text{m}}{0.7\,\text{W/mK}} = 0.1428... \,\text{m}^2 \cdot \text{K/W} $$
03

Compare the result with the options

Our result, 0.1428 m²K/W, is closest to option (a) 0.143 m²K/W. So the correct answer is: (a) \(0.143 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is the process of energy moving from one body or substance to another due to a temperature difference. This fundamental physical concept is crucial in many aspects of science and engineering. There are three primary modes through which heat can be transferred: conduction, convection, and radiation. Each operates differently in various scenarios.
  • **Conduction** involves heat transfer through a material without the movement of the material itself. It happens when atoms or molecules within a substance exchange energy with neighboring particles.
  • **Convection** occurs in fluids (liquids and gases) and is due to the movement of the fluid itself. It often involves the bulk movement of molecules within fluids.
  • **Radiation** doesn't require a medium and involves heat transfer through electromagnetic waves.
Understanding heat transfer is vital for designing thermal systems, like insulation, heating, and cooling technologies. It also helps scientists and engineers develop better methods to conserve energy and improve efficiency in industrial processes.
Conduction
Conduction describes the way heat is transferred through solid materials by direct contact of their particles. This process primarily occurs in metals and ionic solids, where atoms are densely packed, allowing easy transfer of vibrational energy.
In conduction:
  • The transfer of heat happens from the "hotter" region to the "cooler" region within the material.
  • The rate of heat transfer depends on the thermal conductivity of the material, denoted as **k**.
  • The higher the thermal conductivity, the more efficiently heat can pass through a material.
For example, a brick wall has a specific thermal conductivity, which determines how well it can conduct heat. Using the formula for thermal resistance, \( R = \frac{L}{k} \), where \( L \) is the thickness of the wall, we can calculate how much resistance the wall provides against heat transfer. This understanding can inform choices about building materials to optimize for energy efficiency.
Plane Wall Theory
The plane wall theory simplifies the analysis of heat conduction in flat surfaces, such as walls or slabs, where the thickness is small compared to its other dimensions. This theory assumes that heat transfer through the wall occurs in one dimension, making calculations more straightforward.
Key ideas of plane wall theory:
  • Assumes a steady state, so the temperature doesn't change with time.
  • Considers conduction as the primary mode of heat transfer, with effects like convection and radiation being negligible at the wall's surfaces.
  • Typically uses Fourier’s Law of Heat Conduction, which links the thermal conductivity, temperature gradient, and heat transfer rate.
Applying plane wall theory helps engineers calculate thermal resistance, which is a measure of a material's resistance to conductive heat flow. This is critical for designing effective insulation in building walls, ensuring comfort inside while minimizing energy loss. The derived formula for thermal resistance per unit area from the plane wall theory, \( \frac{R}{A} = \frac{L}{k} \), is used to find the correct answer in our given exercise, highlighting its practical utility.

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Most popular questions from this chapter

Circular fins of uniform cross section, with diameter of \(10 \mathrm{~mm}\) and length of \(50 \mathrm{~mm}\), are attached to a wall with surface temperature of \(350^{\circ} \mathrm{C}\). The fins are made of material with thermal conductivity of \(240 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and they are exposed to an ambient air condition of \(25^{\circ} \mathrm{C}\) and the convection heat transfer coefficient is \(250 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Determine the heat transfer rate and plot the temperature variation of a single fin for the following boundary conditions: (a) Infinitely long fin (b) Adiabatic fin tip (c) Fin with tip temperature of \(250^{\circ} \mathrm{C}\) (d) Convection from the fin tip

Chilled water enters a thin-shelled 5-cm-diameter, 150-mlong pipe at \(7^{\circ} \mathrm{C}\) at a rate of \(0.98 \mathrm{~kg} / \mathrm{s}\) and leaves at \(8^{\circ} \mathrm{C}\). The pipe is exposed to ambient air at \(30^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(9 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). If the pipe is to be insulated with glass wool insulation \((k=0.05 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) in order to decrease the temperature rise of water to \(0.25^{\circ} \mathrm{C}\), determine the required thickness of the insulation.

Hot water is to be cooled as it flows through the tubes exposed to atmospheric air. Fins are to be attached in order to enhance heat transfer. Would you recommend attaching the fins inside or outside the tubes? Why?

Using cylindrical samples of the same material, devise an experiment to determine the thermal contact resistance. Cylindrical samples are available at any length, and the thermal conductivity of the material is known.

A 4-mm-diameter and 10-cm-long aluminum fin \((k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is attached to a surface. If the heat transfer coefficient is \(12 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine the percent error in the rate of heat transfer from the fin when the infinitely long fin assumption is used instead of the adiabatic fin tip assumption.

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