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Hot water is to be cooled as it flows through the tubes exposed to atmospheric air. Fins are to be attached in order to enhance heat transfer. Would you recommend attaching the fins inside or outside the tubes? Why?

Short Answer

Expert verified
Answer: The fins should be attached on the outside of the tubes to increase the surface area exposed to the atmospheric air, enhancing the heat transfer process through convection and radiation and cooling the hot water more effectively.

Step by step solution

01

Understand the heat transfer process

The main objective is to cool the hot water flowing through the tubes by exposing them to atmospheric air. Heat transfer occurs mainly through convection from the hot water to the cooler tubes' surfaces, followed by radiation and convection to the surrounding air.
02

Analyze fins' purpose

Fins are attached to increase the effective surface area exposed to the surrounding air, which enhances the heat transfer process. They provide a larger area for convection and radiation to occur, thus cooling the hot water faster.
03

Compare heat transfer inside vs. outside tubes

When analyzing the heat transfer process, we need to consider the materials involved, their thermal conductivity, the atmosphere (air), and the surfaces through which heat is being transferred. Since the air's thermal conductivity is lower than the tubes' material (usually metals), attaching the fins inside the tubes would not be significantly helpful because the fins would be surrounded by hot water which has higher thermal conductivity than air. This results in less heat dissipation by convection from the inner tube surface.
04

Recommend where to attach fins

Based on the analysis of heat transfer processes and the impact of adding fins to the tubes, it is recommended to attach the fins on the outside of the tubes. This placement will increase the surface area exposed to the atmospheric air, enhancing the heat transfer process through convection and radiation and cooling the hot water more effectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convective Heat Transfer
Imagine a pot of water boiling on a stove. The hot water at the bottom gets less dense and rises, while the cooler water sinks down to replace it, forming a circular pattern known as convection currents. These currents are a prime example of convective heat transfer, a process where heat is carried away by the movement of fluids—such as water or air.

When you're trying to cool hot water in tubes exposed to air, the goal is to maximize this type of heat transfer. The cooler air absorbs the heat from the hot water, creating air currents that naturally carry the heat away. Fins enhance this process by increasing the surface area that comes into contact with the air, thus allowing more heat to be transferred from the water to the air. The main takeaway here is that convective heat transfer is most efficient when there's a large temperature difference between the fluid within the tubes (hot water) and the surrounding fluid (atmospheric air), and when there is plenty of surface area available for heat to be exchanged.
Thermal Conductivity
In everyday terms, thermal conductivity is a measure of how well a material can conduct heat. It's like comparing a metal spoon and a wooden spoon when both are placed in a pot of hot soup. The metal spoon gets hot quickly because metals typically have high thermal conductivity, meaning heat moves through them easily. Wooden spoons, on the other hand, stay cool longer because wood has low thermal conductivity.

In a heat exchange scenario, understanding thermal conductivity is vital when deciding where to place fins. High thermal conductivity materials—like metals used in tube construction—transfer heat efficiently, making them excellent for removing heat from the water inside. By contrast, the environment outside the tubes, which is primarily air, has low thermal conductivity. It doesn't transfer heat away as effectively as metals do. This is why using fins outside the tubes boosts heat dissipation into the air by expanding the contact area, allowing heat to escape more readily into the less conductive air.
Fins in Heat Exchange
Now, let's talk about fins in heat exchange. Picture a motorcycle engine with its ridged cylinders or a computer's CPU with a finned heatsink clamped on top; these fins are not there for aesthetics but for a very functional purpose: to boost heat dissipation. The idea is to take advantage of their increased surface area to spread out heat faster and more efficiently into the surrounding air.

In the context of cooling hot water in tubes, attaching fins outside the tubes is akin to giving the tubes a larger 'wingspan' to release heat into the air. Fins work marvelously in such setups because they create extra surface room for heat to be emitted via radiation and picked up by air currents in convection. By improving the efficiency of the system, you can ensure the hot water loses its heat rapidly and the system maintains an optimal temperature with improved effectiveness.

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Most popular questions from this chapter

The roof of a house consists of a 15-cm-thick concrete slab \((k=2 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) that is \(15 \mathrm{~m}\) wide and \(20 \mathrm{~m}\) long. The convection heat transfer coefficients on the inner and outer surfaces of the roof are 5 and \(12 \mathrm{~W} / \mathrm{m}^{2}\). \(\mathrm{K}\), respectively. On a clear winter night, the ambient air is reported to be at \(10^{\circ} \mathrm{C}\), while the night sky temperature is \(100 \mathrm{~K}\). The house and the interior surfaces of the wall are maintained at a constant temperature of \(20^{\circ} \mathrm{C}\). The emissivity of both surfaces of the concrete roof is \(0.9\). Considering both radiation and convection heat transfers, determine the rate of heat transfer through the roof, and the inner surface temperature of the roof. If the house is heated by a furnace burning natural gas with an efficiency of 80 percent, and the price of natural gas is \(\$ 1.20 /\) therm ( 1 therm \(=105,500 \mathrm{~kJ}\) of energy content), determine the money lost through the roof that night during a 14-h period.

Consider a window glass consisting of two 4-mmthick glass sheets pressed tightly against each other. Compare the heat transfer rate through this window with that of one consisting of a single 8-mm-thick glass sheet under identical conditions.

Why are the convection and the radiation resistances at a surface in parallel instead of being in series?

Two identical aluminum plates with thickness of \(30 \mathrm{~cm}\) are pressed against each other at an average pressure of \(1 \mathrm{~atm}\). The interface, sandwiched between the two plates, is filled with glycerin. On the left outer surface, it is subjected to a uniform heat flux of \(7800 \mathrm{~W} / \mathrm{m}^{2}\) at a constant temperature of \(50^{\circ} \mathrm{C}\). On the right outer surface, the temperature is maintained constant at \(30^{\circ} \mathrm{C}\). Determine the thermal contact conductance of the glycerin at the interface, if the thermal conductivity of the aluminum plates is \(237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). Discuss whether the value of the thermal contact conductance is reasonable or not.

How does the thermal resistance network associated with a single-layer plane wall differ from the one associated with a five-layer composite wall?

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