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A \(0.15 \mathrm{~kg}\) ball hits a wall with a velocity of \((5.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(6.50\) \(\mathrm{m} / \mathrm{s}) \hat{\mathrm{j}}+(4.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{k}}\). It rebounds from the wall with a velocity of \((2.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(3.50 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}+(-3.20 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{k}}\). What are (a) the change in the ball's momentum, (b) the impulse on the ball, and (c) the impulse on the wall?

Short Answer

Expert verified
The change in momentum and impulse on the ball is \((-0.45 \ \hat{\mathbf{i}} - 0.45 \ \hat{\mathbf{j}} - 1.08 \ \hat{\mathbf{k}}) \ \text{kg m/s}\), and the impulse on the wall is \((0.45 \ \hat{\mathbf{i}} + 0.45 \ \hat{\mathbf{j}} + 1.08 \ \hat{\mathbf{k}}) \ \text{kg m/s}\).

Step by step solution

01

Understand the Problem

We have a ball that hits a wall and rebounds. We need to find the change in the ball's momentum, the impulse on the ball, and the impulse on the wall. Remember that the impulse on an object is equal to the change in its momentum.
02

Calculate Initial Velocity Vector

The initial velocity of the ball is given as \((5.00 \ \text{m/s}) \hat{\mathbf{i}} + (6.50 \ \text{m/s}) \hat{\mathbf{j}} + (4.00 \ \text{m/s}) \hat{\mathbf{k}}\). We need this vector to compute the momentum before impact.
03

Calculate Initial Momentum

Initial momentum \( \mathbf{p}_i \) is calculated by multiplying the mass \( m = 0.15 \ \text{kg} \) by the initial velocity vector: \( \mathbf{p}_i = m \mathbf{v}_i = 0.15 \cdot (5.00 \ \hat{\mathbf{i}} + 6.50 \ \hat{\mathbf{j}} + 4.00 \ \hat{\mathbf{k}}) \).Evaluating, \( \mathbf{p}_i = (0.75 \ \hat{\mathbf{i}} + 0.975 \ \hat{\mathbf{j}} + 0.60 \ \hat{\mathbf{k}}) \ \text{kg m/s} \).
04

Calculate Final Velocity Vector

The final velocity of the ball is given as \((2.00 \ \text{m/s}) \hat{\mathbf{i}} + (3.50 \ \text{m/s}) \hat{\mathbf{j}} + (-3.20 \ \text{m/s}) \hat{\mathbf{k}}\). We need this vector to compute the momentum after impact.
05

Calculate Final Momentum

Final momentum \( \mathbf{p}_f \) is calculated by multiplying the mass \( m = 0.15 \ \text{kg} \) by the final velocity vector: \( \mathbf{p}_f = m \mathbf{v}_f = 0.15 \cdot (2.00 \ \hat{\mathbf{i}} + 3.50 \ \hat{\mathbf{j}} + (-3.20) \ \hat{\mathbf{k}}) \).Evaluating, \( \mathbf{p}_f = (0.30 \ \hat{\mathbf{i}} + 0.525 \ \hat{\mathbf{j}} - 0.480 \ \hat{\mathbf{k}}) \ \text{kg m/s} \).
06

Calculate Change in Momentum

The change in momentum \( \Delta \mathbf{p} \) is calculated as the final momentum minus the initial momentum:\[ \Delta \mathbf{p} = \mathbf{p}_f - \mathbf{p}_i = (0.30 \ \hat{\mathbf{i}} + 0.525 \ \hat{\mathbf{j}} - 0.480 \ \hat{\mathbf{k}}) - (0.75 \ \hat{\mathbf{i}} + 0.975 \ \hat{\mathbf{j}} + 0.60 \ \hat{\mathbf{k}}) \]Simplifying, \( \Delta \mathbf{p} = (-0.45 \ \hat{\mathbf{i}} - 0.45 \ \hat{\mathbf{j}} - 1.08 \ \hat{\mathbf{k}}) \ \text{kg m/s} \).
07

Relate Impulse to Momentum Change

The impulse \( \mathbf{J} \) on an object is equal to its change in momentum. Therefore, the impulse on the ball \( \mathbf{J}_{\text{ball}} \) is \( \Delta \mathbf{p} \): \( \mathbf{J}_{\text{ball}} = (-0.45 \ \hat{\mathbf{i}} - 0.45 \ \hat{\mathbf{j}} - 1.08 \ \hat{\mathbf{k}}) \ \text{kg m/s} \).
08

Determine Impulse on the Wall

By the law of conservation of momentum and Newton's third law, the impulse on the wall is equal in magnitude and opposite in direction to the impulse on the ball. Therefore, \( \mathbf{J}_{\text{wall}} = (0.45 \ \hat{\mathbf{i}} + 0.45 \ \hat{\mathbf{j}} + 1.08 \ \hat{\mathbf{k}}) \ \text{kg m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
When studying the motion of objects, the conservation of momentum is a key principle. It states that in a closed system, the total momentum before an event is equal to the total momentum after the event. This concept is essential in physics, especially when analyzing collisions or interactions between objects.

In the context of the problem, a ball strikes a wall and rebounds. When it does, its momentum changes. However, if we consider the ball and the wall as one system, then the total momentum of this system remains conserved. This means that the momentum lost by the ball is gained by the wall.
  • The ball's initial and final momenta are different due to its change in velocity upon bouncing.
  • The wall exerts a force to change the ball's momentum, following the conservation principle.
Newton's Third Law
Newton's Third Law states, "For every action, there is an equal and opposite reaction." This principle provides a foundation for understanding interactions, such as the one between the ball and the wall in our problem.

When the ball hits the wall, it exerts a force on the wall. According to Newton's Third Law, the wall must exert an equal force in the opposite direction on the ball. This is why the ball rebounds. Notably, this action-reaction pair explains why the impulse on the ball and the impulse on the wall are equal in magnitude but opposite in direction.
  • The action force is the ball striking the wall.
  • The reaction force is the wall pushing back on the ball, causing it to rebound.
Vector Calculations
Vector calculations are essential in physics to accurately determine quantities like velocity and momentum that have both magnitude and direction. In this problem, both initial and final velocities of the ball are given as vectors in three dimensions: \[v_i = (5.00 \, ext{m/s}) \hat{\mathrm{i}} + (6.50 \, ext{m/s}) \hat{\mathrm{j}} + (4.00 \, ext{m/s}) \hat{\mathrm{k}} \]\[v_f = (2.00 \, ext{m/s}) \hat{\mathrm{i}} + (3.50 \, ext{m/s}) \hat{\mathrm{j}} + (-3.20 \, ext{m/s}) \hat{\mathrm{k}} \]

By multiplying these velocity vectors with the ball's mass, we calculate the momentum as vectors in each direction. Subtracting these vectors provides us the change in momentum, which is crucial for finding the impulse. Mastering calculations with vectors allows one to handle real-world scenarios where multiple directions are involved.
  • Velocity vectors identify how fast and in which direction the ball moves.
  • Momentum vectors result from multiplying velocity vectors by mass.
Physics Problem Solving
Solving physics problems effectively involves understanding the underlying principles, identifying relevant information, and applying mathematical formulas correctly. To tackle the given problem, one needs to:
  • Recognize that impulse and momentum change are interconnected.
  • Use the given vectors for initial and final velocities to compute momentum.
  • Apply Newton's laws and the conservation rules to form connections between different physical quantities.
Breaking the problem into steps helps manage complex calculations easily. Each step should build upon the previous one to arrive at the solution. Developing a systematic approach not only aids in solving current problems but also prepares students for future complex problems.

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