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Two titanium spheres approach each other head-on with the same speed and collide elastically. After the collision, one of the spheres, whose mass is \(300 \mathrm{~g}\), remains at rest. (a) What is the mass of the other sphere? (b) What is the speed of the two-sphere center of mass if the initial speed of each sphere is \(2.00 \mathrm{~m} / \mathrm{s} ?\)

Short Answer

Expert verified
(a) The mass of the other sphere is 300 g. (b) The center of mass velocity is 0 m/s.

Step by step solution

01

Understand the Problem

We have two titanium spheres colliding elastically. One sphere (mass: 300g) stops after the collision, and we need to find the mass of the other sphere. We also need to find the speed of the center of mass if both spheres initially move towards each other at 2.00 m/s.
02

Setup of Initial Conditions

Let the initial velocity of the 300g sphere be \(v_1 = 2.00\, \mathrm{m/s}\) and that of the other sphere be \(v_2 = -2.00\, \mathrm{m/s}\) (since they are moving towards each other).
03

Use Conservation of Momentum

Since momentum is conserved, the total momentum before the collision equals the total momentum after the collision. Let \(m\) be the mass of the unknown sphere. Before collision: \(0.3 \times v_1 + m \times v_2 = 0.3 \times 2.00 + m \times (-2.00)\)After collision, the 0.3 kg sphere is at rest, so:\(0 \times 0 + m \times v'_2 = 0\)
04

Solution for Mass of Second Sphere

Based on conservation laws, because the 300 g sphere stops, the velocity exchanged should ensure momentum is conserved:\[0.3 \times 2.00 = m \times v_2\], so \(0.6 = m \times 2.00\). Therefore, \(m = 0.300/Kg\)
05

Calculate Center of Mass Velocity

The velocity of the center of mass \(v_{cm}\) can be calculated as:\[v_{cm} = \frac{m_1v_1 + m_2v_2}{m_1 + m_2}\]Substitute known values:\[v_{cm} = \frac{(0.3)(2.00) + (0.3)(-2.00)}{0.3 + 0.3} = 0\]
06

Interpretation of Results

The mass of the second sphere is 300g, and the center of mass velocity is 0 m/s, meaning the center of mass does not move even though both spheres did.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
In any type of collision, the principle of the conservation of momentum is fundamental. Momentum is a vector quantity, meaning it has both magnitude and direction, and for an isolated system (one without external forces), the total momentum remains constant. This principle is particularly evident in elastic collisions like the one described in the exercise.

Consider the formula for momentum: \(p = mv\), where \(m\) is mass and \(v\) is velocity. Before the collision, the total momentum of the system (both titanium spheres) must equal the total momentum after the collision. This is crucial for understanding how one mass remains stationary post-collision; its absence of motion balances out under the conservation of momentum.

By setting up the equation \(m_1v_1 + m_2v_2 = m_1v_1' + m_2v_2'\), and substituting real values into it, you can solve for the unknowns, like the mass of one of the spheres. This equation highlights the beauty of conservation laws by showing the interactions within a system that respects these laws, even in the event of motion and speed changes due to collisions.
Center of Mass
The center of mass of an object or system is a point representing the mean position of the matter in the system. When external forces aren't acting on the system, the center of mass moves in a predictable manner. In the case of collisions, the velocity of the center of mass is of interest, especially when calculating it before and after the impact.

The velocity of the center of mass \((v_{cm})\) can be calculated as:
  • \(v_{cm} = \frac{m_1v_1 + m_2v_2}{m_1 + m_2}\)
This ratio tells us about the system as a whole. For this problem, the equal and opposite velocities of the two spheres indicate that their center of mass stays at rest. This is because the momentum from one sphere directly cancels out the momentum from the other, demonstrating perfect symmetrical motion of the system.

Understanding how to calculate and interpret the motion of the center of mass helps in predicting the system's behavior post-collision, offering insights into more complex interactions seen in physics.
Collision Physics
Collisions are a fundamental concept in physics, illustrating how objects interact through forces and motion. Elastic collisions, such as the one in our exercise, are characterized by the conservation of both momentum and kinetic energy. In these interactions, no kinetic energy is lost, which is a unique property compared to inelastic collisions.

Elastic collisions can be visualized as perfectly "bouncy" interactions, where objects separate with the same speed, just in different directions. This isn’t limited to abstract spheres but extends to real-world applications like billiard balls or gas particles in a container.

In this exercise, we see that understanding the nature of the collision allows us to use fundamental principles to solve for unknown quantities. Each sphere exchanges velocity in an amount that causes the 300 g sphere to stop, emphasizing precision in energy transfer and showcasing the predictability and control within collision dynamics. Hence, grasping collision physics equips students and professionals with the tools necessary to analyze and foresee outcomes in various physical systems.

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