/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 A positron undergoes a displacem... [FREE SOLUTION] | 91Ó°ÊÓ

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A positron undergoes a displacement \(\Delta \vec{r}=2.0 \hat{\mathrm{i}}-3.0 \hat{\mathrm{j}}+6.0 \hat{\mathrm{k}}\), ending with the position vector \(\vec{r}=3.0 \hat{\mathrm{j}}-4.0 \hat{\mathrm{k}}\), in meters. What was the positron's initial position vector?

Short Answer

Expert verified
The initial position vector is \(-2.0 \hat{\mathrm{i}} + 6.0 \hat{\mathrm{j}} - 10.0 \hat{\mathrm{k}}\).

Step by step solution

01

Understand the Problem

We are given a displacement vector \( \Delta \vec{r} = 2.0 \hat{\mathrm{i}} - 3.0 \hat{\mathrm{j}} + 6.0 \hat{\mathrm{k}} \) and a final position vector \( \vec{r} = 3.0 \hat{\mathrm{j}} - 4.0 \hat{\mathrm{k}} \). We need to find the initial position vector of the positron.
02

Use the Displacement Equation

We know the equation for displacement: \( \Delta \vec{r} = \vec{r} - \vec{r}_0 \), where \( \vec{r}_0 \) is the initial position vector. We can rearrange this to find \( \vec{r}_0 \): \( \vec{r}_0 = \vec{r} - \Delta \vec{r} \).
03

Calculate Each Component

Substitute the given vectors into the equation: \( \vec{r}_0 = (0 \hat{\mathrm{i}} + 3.0 \hat{\mathrm{j}} - 4.0 \hat{\mathrm{k}}) - (2.0 \hat{\mathrm{i}} - 3.0 \hat{\mathrm{j}} + 6.0 \hat{\mathrm{k}}) \).
04

Perform Vector Subtraction

Perform the subtraction for each component:- For \( \hat{\mathrm{i}} \): \( 0 - 2.0 = -2.0 \hat{\mathrm{i}} \)- For \( \hat{\mathrm{j}} \): \( 3.0 - (-3.0) = 3.0 + 3.0 = 6.0 \hat{\mathrm{j}} \)- For \( \hat{\mathrm{k}} \): \( -4.0 - 6.0 = -10.0 \hat{\mathrm{k}} \)
05

Write the Initial Position Vector

Combine the components to write the initial position vector: \( \vec{r}_0 = -2.0 \hat{\mathrm{i}} + 6.0 \hat{\mathrm{j}} - 10.0 \hat{\mathrm{k}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Initial Position Vector
The journey of an object, such as a positron, often begins with an initial position vector. Think of this as the starting point in a three-dimensional space. This vector \( \vec{r}_0 \) serves as a precise location from which any movement or displacement begins.
When we talk about vectors in physics, we refer to directions and magnitudes. The initial position vector gives us the direction and location where the object was present before it began moving. Visualizing the vector as an arrow can help. The tail of the arrow is at the origin, and its head points towards the object's starting position.
  • The vector is expressed in terms of its components along the x, y, and z-axes. For example, \( \vec{r}_0 = -2.0 \hat{\mathrm{i}} + 6.0 \hat{\mathrm{j}} - 10.0 \hat{\mathrm{k}} \) states the initial positions along three perpendicular axes.
  • Each component represents how far along each axis the object is from the origin.
From the exercise, we can see how understanding the initial position vector is crucial to solving for other elements like displacement.
Final Position Vector in Space
The final position vector is where the object's journey ends after accounting for any displacement. If the journey of the positron starts from the initial position, the final position vector \( \vec{r} \) represents its stopping point.
This vector captures the endpoint and is equally as critical as the initial vector in understanding the object's trajectory. Like the initial position vector, the final position vector tells us where the object is in three-dimensional space, but it represents the destination instead.
  • It is defined similarly to \( \vec{r}_0 \), with components along the x, y, and z-axes. For our positron, we have \( \vec{r} = 0 \hat{\mathrm{i}} + 3.0 \hat{\mathrm{j}} - 4.0 \hat{\mathrm{k}} \).
  • This tells us the positron's position relative to the origin at the end of its journey.
Understanding these vectors allows us to chart the entire path the object takes from its initial to its final position.
Delving into Vector Subtraction
Vector subtraction is a fundamental operation in physics and mathematics, crucial for understanding how two points are related in vector space. It helps determine changes between two vectors – such as positions. In our exercise, this is used to find the initial position vector when the final position is known.
The vector subtraction operation occurs component-wise, meaning each dimension of the vector is handled separately:
  • For the \( \hat{\mathrm{i}} \) component, you subtract the initial from the final: \( 0 - 2.0 = -2.0 \hat{\mathrm{i}} \).
  • For the \( \hat{\mathrm{j}} \) component, \( 3.0 - (-3.0) = 6.0 \hat{\mathrm{j}} \) involves adding instead of subtracting because of the double negative.
  • Finally, \( \hat{\mathrm{k}} \) component involves the result of \( -4.0 - 6.0 = -10.0 \hat{\mathrm{k}} \).
This component-wise subtraction results in the overall vector, \( \vec{r}_0 = -2.0 \hat{\mathrm{i}} + 6.0 \hat{\mathrm{j}} - 10.0 \hat{\mathrm{k}} \), a result depicting the vector differences between the final and displaced vectors. Understanding vector subtraction in relation to initial and final positions enables us to solve problems involving trajectories and displacements effectively.

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Most popular questions from this chapter

A lowly high diver pushes off horizontally with a speed of \(2.00 \mathrm{~m} / \mathrm{s}\) from the platform edge \(10.0 \mathrm{~m}\) above the surface of the water. (a) At what horizontal distance from the edge is the diver \(0.800 \mathrm{~s}\) after pushing off? (b) At what vertical distance above the surface of the water is the diver just then? (c) At what horizontal distance from the edge does the diver strike the water?

Oasis \(A\) is \(90 \mathrm{~km}\) due west of oasis \(B .\) A desert camel leaves \(A\) and takes \(50 \mathrm{~h}\) to walk \(75 \mathrm{~km}\) at \(37^{\circ}\) north of due east. Next it takes \(35 \mathrm{~h}\) to walk \(65 \mathrm{~km}\) due south. Then it rests for \(5.0 \mathrm{~h}\). What are the (a) magnitude and (b) direction of the camel's displacement relative to \(A\) at the resting point? From the time the camel leaves \(A\) until the end of the rest period, what are the (c) magnitude and (d) direction of its average velocity and (e) its average speed? The camel's last drink was at \(A ;\) it must be at \(B\) no more than \(120 \mathrm{~h}\) later for its next drink. If it is to reach \(B\) just in time, what must be the (f) magnitude and (g) direction of its average velocity after the rest period?

A boat is traveling upstream in the positive direction of an \(x\) axis at \(14 \mathrm{~km} / \mathrm{h}\) with respect to the water of a river. The water is flowing at \(9.0 \mathrm{~km} / \mathrm{h}\) with respect to the ground. What are the (a) magnitude and (b) direction of the boat's velocity with respect to the ground? A child on the boat walks from front to rear at \(6.0\) \(\mathrm{km} / \mathrm{h}\) with respect to the boat. What are the (c) magnitude and (d) direction of the child's velocity with respect to the ground?

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A dart is thrown horizontally with an initial speed of \(10 \mathrm{~m} / \mathrm{s}\) toward point \(P\), the bull's-eye on a dart board. It hits at point \(Q\) on the rim, vertically below \(P, 0.19 \mathrm{~s}\) later. (a) What is the distance \(P Q ?\) (b) How far away from the dart board is the dart released?

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