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For a certain driven scrics \(R L C\) circuit, the maximum generator emf is \(125 \mathrm{~V}\) and the maximum current is \(3.20 \mathrm{~A}\). If the current leads the generator emf by \(0.982\) rad, what are the (a) impedance and (b) resistance of the circuit? (c) Is the circuit predominantly capacitive or inductive?

Short Answer

Expert verified
(a) Impedance is 39.06 Ω, (b) Resistance is 21.66 Ω, (c) The circuit is predominantly capacitive.

Step by step solution

01

Understanding the Given Data

We are given the maximum generator emf \( E = 125\,\mathrm{V} \), maximum current \( I = 3.20\,\mathrm{A} \), and the phase angle \( \phi = 0.982\,\mathrm{rad} \). We are to find the impedance \( Z \), resistance \( R \), and determine if the circuit is predominantly capacitive or inductive.
02

Calculate the Impedance Z

The impedance \( Z \) in an AC circuit is given by the formula \( Z = \frac{E}{I} \). Substituting the given values, we have:\[Z = \frac{125\,\mathrm{V}}{3.20\,\mathrm{A}} = 39.06\,\Omega.\]
03

Determine the Resistance R

The resistance \( R \) in an \( RLC \) circuit is related to impedance \( Z \) and the phase angle \( \phi \). It can be calculated using \( R = Z \cos(\phi) \). Substituting the known values:\[R = 39.06\,\Omega \times \cos(0.982\,\mathrm{rad}) = 21.66\,\Omega.\]
04

Determine the Circuit Type

In an \( RLC \) circuit, if the current leads the voltage (as given by a positive phase angle), the circuit is predominantly capacitive. Thus, here the circuit is predominantly capacitive since the current leads the emf by \( 0.982 \) rad.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impedance Calculation
To understand impedance in an RLC circuit, we first need to know its definition. Impedance, represented as \( Z \), is the total opposition that a circuit offers to the flow of alternating current (AC). Impedance is measured in ohms (\(\Omega\)), and it combines both resistance (R) and reactance (X) in the circuit.

Impedance is distinct from simple resistance because it takes into account both the resistive elements and the frequency-dependent elements like capacitors and inductors.

When calculating the impedance in an RLC circuit, the formula \( Z = \frac{E}{I} \) is used, where \( E \) is the maximum emf (electromotive force) and \( I \) is the maximum current in the circuit.

For the given exercise, substituting the known values \( E = 125 \, \mathrm{V} \) and \( I = 3.20 \, \mathrm{A} \) into the impedance formula gives us an impedance of \( Z = 39.06 \Omega \).
This value indicates how much the circuit opposition influences the AC flow.
Phase Angle
The phase angle in an RLC circuit is crucial for determining the behavior of the circuit. It is often denoted by \( \phi \) and measured in radians. The phase angle represents the difference in phase between the current and the voltage sine waves.

In our context, a positive phase angle of \(0.982\) radians means that the current leads the voltage. This directly affects both impedance and resistance calculations, as it helps in determining whether a circuit is predominantly capacitive or inductive.

The relation between impedance \( Z \), resistance \( R \), and phase angle \( \phi \) is \( R = Z \cos(\phi) \).
Here, knowing the phase angle allowed us to compute the resistance \( R \) as \( 21.66 \Omega \), influenced by the phase angle's value.
Understanding these relationships helps decode the characteristics of alternating current circuits.
Capacitive and Inductive Circuits
To determine the nature of an RLC circuit, whether it is predominantly capacitive or inductive, we look at the phase relationship between the voltage and current.

A circuit is said to be predominantly capacitive if the current leads the voltage, as in the step-by-step solution. This is denoted by a positive phase angle, meaning the capacitive reactance is greater than the inductive reactance. In contrast, if the voltage leads the current, the circuit is predominantly inductive, indicated by a negative phase angle.

For the given problem, the current leads the generator emf by \(0.982\) radians, which confirms that the circuit is primarily capacitive.

This knowledge allows us to predict the response of the circuit to changes in frequency, which is vital in designing and analyzing circuits in electronics and communications.

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Most popular questions from this chapter

In an oscillating \(L C\) circuit with \(L=50 \mathrm{mH}\) and \(C=\) 4.0 \(\mu \mathrm{F}\), the current is initially a maximum. How long will it take before the capacitor is fully charged for the first time?

In an oscillating \(L C\) circuit, \(L=25.0 \mathrm{mH}\) and \(C=7.80 \mu \mathrm{F}\). At time \(t=0\) the current is \(9.20 \mathrm{~mA}\), the charge on the capacitor is \(3.80 \mu \mathrm{C}\), and the capacitor is charging. What are (a) the total energy in the circuit, (b) the maximum charge on the capacitor, and (c) the maximum current? (d) If the charge on the capacitor is given by \(q=Q \cos (\omega t+\phi)\), what is the phase angle \(\phi ?(\mathrm{e})\) Suppose the data are the same, except that the capacitor is discharging at \(t=0\). What then is \(\phi\) ?

What is the maximum value of an ac voltage whose rms value is \(100 \mathrm{~V} ?\)

An ac generator provides emf to a resistive load in a remote factory over a two-cable transmission line. At the factory a step-down transformer reduces the voltage from its (rms) transmission value \(V_{t}\) to a much lower value that is safe and convenient for use in the factory. The transmission line resistance is \(0.30 \Omega /\) cable, and the power of the generator is 250 \(\mathrm{kW}\). If \(V_{t}=80 \mathrm{kV}\), what are (a) the voltage decrease \(\Delta V\) along the transmission line and (b) the rate \(P_{d}\) at which energy is dissipated in the line as thermal energy? If \(V_{t}=8.0 \mathrm{kV}\), what are (c) \(\Delta V\) and (d) \(P_{d}\) ? If \(V_{t}=0.80 \mathrm{kV}\), what are (e) \(\Delta V\) and (f) \(P_{d} ?\)

A \(1.50 \mu \mathrm{F}\) capacitor has a capacitive reactance of \(12.0 \Omega\). (a) What must be its operating frequency? (b) What will be the capacitive reactance if the frequency is doubled?

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