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What is the maximum value of an ac voltage whose rms value is \(100 \mathrm{~V} ?\)

Short Answer

Expert verified
The maximum AC voltage is approximately 141.4 V.

Step by step solution

01

Understand the Relationship between RMS and Maximum Value

The root mean square (RMS) value of an AC voltage is a measure of the effective voltage. The relationship between the RMS voltage (\(V_{rms}\)) and the maximum or peak voltage (\(V_{max}\)) for a sinusoidal signal is given by the formula:\[V_{max} = V_{rms} \times \sqrt{2}\] for sinusoidal AC signals.
02

Substitute Known Values into the Formula

Substitute the given RMS value into the formula. Here, \(V_{rms} = 100 \mathrm{~V}\):\[V_{max} = 100 \times \sqrt{2}\]
03

Calculate the Maximum Value

Compute the expression \(100 \times \sqrt{2}\). The square root of 2 is approximately 1.414, so:\[V_{max} = 100 \times 1.414 = 141.4 \mathrm{~V}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

RMS Voltage
RMS voltage stands for Root Mean Square voltage. It is a measure used to quantify the effective value of an alternating current (AC) signal. Unlike direct current (DC) which has a constant signal, AC voltage oscillates over time, typically following a sinusoidal pattern. Because of this fluctuation, it can be tricky to ascertain the "strength" or "level" of the voltage. RMS voltage provides a standard measurement that represents the equivalent DC value which would deliver the same power. - It gives us a way to harness AC signals effectively, without needing to consider their time-varying nature. - For a sinusoidal AC signal, RMS voltage is approximately 0.707 times the peak voltage. - For most household electronics, the RMS value of 120 V or 230 V (depending on your country) reflects the usable voltage as you plug in appliances. RMS is particularly important because it helps in designing electrical systems to ensure they handle the actual power delivered by AC signals, which leads to efficient and safe operations.
Peak Voltage
Peak voltage (\(V_{max}\)) of an AC signal is the maximum instantaneous value it reaches during a cycle. Understanding peak voltage is essential for various applications, such as designing circuits and ensuring they are capable of handling certain voltages.- In a sinusoidal waveform, peak voltage occurs at the topmost point of the wave.- Peak voltage is usually higher than the RMS voltage, due to the fluctuations in the signal.The relationship between RMS voltage and peak voltage is a key concept when working with AC signals. The equation \(V_{max} = V_{rms} \times \sqrt{2}\) shows how peak voltage relates to RMS voltage for sinusoidal signals. This relationship is fundamental because it allows us to easily calculate one measure if we know the other.Engineers and technicians use peak voltage when determining the insulation levels of electrical components and the maximum ratings of electronic devices.
Sinusoidal Signal
A sinusoidal signal is a smooth, periodic oscillation that is commonly found in AC circuits. This type of signal is characterized by its wave-like shape, which can be described using a mathematical sine function. - Sinusoidal signals are significant in electronics and electrical engineering because many natural and man-made phenomena exhibit sinusoidal behavior. - These signals are easy to analyze and can be manipulated mathematically to understand electrical behaviors better. In AC voltage, the sinusoidal waveform represents how the voltage varies over time. Its peak corresponds to the maximum strength of the voltage, while the RMS measure provides an average value reflecting its power capacity. Understanding sinusoidal signals helps in designing circuits and systems that can efficiently handle AC signals, leading to optimized electrical designs that perform safely and reliably.

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Most popular questions from this chapter

An oscillating \(L C\) circuit consisting of a \(1.0 \mathrm{nF}\) capacitor and a \(3.0 \mathrm{mH}\) coil has a maximum voltage of \(3.0 \mathrm{~V}\). What are (a) the maximum charge on the capacitor, (b) the maximum current through the circuit, and (c) the maximum energy stored in the magnetic field of the coil?

A single-loop circuit consists of a \(7.20 \Omega\) resistor, a \(12.0 \mathrm{H}\) inductor, and a \(3.20 \mu \mathrm{F}\) capacitor. Initially the capacitor has a charge of \(6.20 \mu \mathrm{C}\) and the current is zero. Calculate the charge on the capacitor \(N\) complete cycles later for (a) \(N=5\), (b) \(N=10\), and (c) \(N=100\).

A \(1.50 \mu \mathrm{F}\) capacitor has a capacitive reactance of \(12.0 \Omega\). (a) What must be its operating frequency? (b) What will be the capacitive reactance if the frequency is doubled?

A generator with an adjustable frequency of oscillation is wired in series to an inductor of \(L=2.50 \mathrm{mH}\) and a capacitor of \(C=3.00 \mu \mathrm{F}\). At what frequency does the generator produce the largest possible current amplitude in the circuit?

In a series oscillating \(R L C\) circuit, \(R=16.0 \Omega, C=31.2\) \(\mu \mathrm{F}, L=9.20 \mathrm{mH}\), and \(\mathscr{E}_{m}=\mathscr{8}_{m} \sin \omega_{d} t\) with \(\mathscr{E}_{m}=45.0 \mathrm{~V}\) and \(\omega_{d}=3000 \mathrm{rad} / \mathrm{s}\). For time \(t=0.442 \mathrm{~ms}\) find \((\mathrm{a})\) the rate \(P_{g}\) at which cnergy is being supplied by the generator, (b) the rate \(P_{C}\) at which the energy in the capacitor is changing, (c) the rate \(P_{L}\) at which the energy in the inductor is changing, and (d) the rate \(P_{R}\) at which energy is being dissipated in the resistor. (e) Is the sum of \(P_{C}, P_{t}\), and \(P_{R}\) greater than, less than, or equal to \(P_{g}\) ?

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