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Four long straight wires are perpendicular to the page, and their cross sections form a square of edge length \(a=8.50 \mathrm{~cm} .\) Each wire carries \(15.0\) \(\mathrm{A}\), and all the currents are out of the page. In unit-vector notation, what is the net magnetic force per meter of wire length on wire \(1 ?\)

Short Answer

Expert verified
The net magnetic force per meter on wire 1 is in unit-vector form.

Step by step solution

01

Identify the forces involved

We need to calculate the magnetic forces exerted on wire 1 due to the other three wires. Since they form a square, each wire interacts with wire 1 through the magnetic field generated by its own current.
02

Use the formula for magnetic force between parallel currents

The force per unit length between two parallel current-carrying wires is given by the formula \( F/L = \frac{\mu_0 I_1 I_2}{2\pi d} \), where \( \mu_0 \) is the permeability of free space, \( I_1 \) and \( I_2 \) are the currents, and \( d \) is the distance between the wires.
03

Calculate the force from wire 2 on wire 1

Wire 2 is adjacent to wire 1, at a distance \( a = 8.5 \) cm. Using the formula, \[ F_{2-on-1}/L = \frac{(4\pi \times 10^{-7} \, \text{T}\cdot \text{m/A}) \times (15.0 \, \text{A})^2}{2\pi \times 0.085 \, \text{m}} \]The force direction is repulsive (as both currents are in the same direction), so it acts to the left of wire 1.
04

Calculate the force from wire 4 on wire 1

Wire 4 is also adjacent to wire 1, at the distance of \( a = 8.5 \) cm. Using the same formula as in Step 3, since the situation is symmetric,\[ F_{4-on-1}/L = \frac{(4\pi \times 10^{-7} \, \text{T}\cdot \text{m/A}) \times (15.0 \, \text{A})^2}{2\pi \times 0.085 \, \text{m}} \]Again, this force is repulsive and acts downward on wire 1.
05

Calculate the force from wire 3 on wire 1

Wire 3 is diagonally opposite to wire 1 at a distance \( \sqrt{2}a \). Using the same formula again, \[ F_{3-on-1}/L = \frac{(4\pi \times 10^{-7} \, \text{T}\cdot \text{m/A}) \times (15.0 \, \text{A})^2}{2\pi \times \sqrt{2} \times 0.085 \, \text{m}} \]The force direction is also repulsive, acting at a 45-degree angle between left and downward.
06

Calculate net force on wire 1

The forces from wire 2 and wire 4 add directly, both acting in perpendicular directions (x and y axes). The force from wire 3 needs to be broken down into components: - The x-component is \[ F_{3-on-1-x}/L = F_{3-on-1}/L \cdot \cos(45^{\circ}) \]- The y-component is \[ F_{3-on-1-y}/L = F_{3-on-1}/L \cdot \sin(45^{\circ}) \]By symmetry, these components will reduce the net effects on the x and y-axis. Sum all contributions in x and y to derive the net force.
07

Simplify and summarize net force

Calculate the net force in unit-vector notation by combining the perpendicular components calculated from all contributing forces. For x and y directions, you'll find: \( F_x = F_{2-on-1}/L + F_{3-on-1-x}/L \) \( F_y = F_{4-on-1}/L + F_{3-on-1-y}/L \)After plugging and solving, express the solution in unit-vector notation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Biot-Savart Law
The Biot-Savart Law is essential in determining the magnetic field generated by a current-carrying conductor. It's critical to understand this concept when dealing with magnetic forces between wires. The law states that the magnetic field \( \mathbf{dB} \) generated at a point by a current element is proportional to the current \( I \),the length of the current element \( \mathbf{dl} \), and inversely proportional to the square of the distance \( r^2 \) from the current element to the point. The field produced is perpendicular to both the direction of current and the position vector \( \mathbf{r} \).Biot-Savart Law can be mathematically expressed as:\[ \mathbf{dB} = \frac{\mu_0}{4\pi} \frac{I \, \mathbf{dl} \times \mathbf{r}}{r^3} \]where \( \mu_0 \) is the permeability of free space. The cross-product encapsulates the perpendicular nature of magnetic forces. Understanding the vector nature of forces at play helps in calculating the direction and magnitude of the net force on wire 1. Every segment of current generates a magnetic field, which can then influence other nearby wires.
Electromagnetism
Electromagnetism is the study of the magnetic fields that arise when an electric current flows through a conductor. It's a foundational concept explaining many phenomena in everyday life, such as how electronic devices function. In the exercise, the interaction between the magnetic fields produced by four wires illustrates fundamental electromagnetism principles. Electromagnetic forces can be attractive or repulsive depending on the direction of the current flow in wires:
  • If currents flow in the same direction, they attract each other.
  • If currents flow in opposite directions, they repel each other.
In this scenario, all currents are directed out towards the reader, generating magnetic fields around each wire. The resulting forces between the wires determine the overall net magnetic force acting on wire 1. To compute these forces, one must consider the direction and magnitude relationships defined by electromagnetic laws.
Vector Analysis
Vector analysis involves understanding quantities described by both magnitude and direction. In physics, this is crucial for calculating forces in multiple dimensions. When dealing with electromagnetic forces, like those in the exercise, vector analysis is imperative:
  • Forces can be broken down into components along the x and y axes.
  • These components allow simpler calculation of resultant forces.
The forces from wire 2 and wire 4 on wire 1 are perpendicular, making this analysis straightforward. However, the force from wire 3 is diagonal, necessitating a breakdown into orthogonal components using trigonometric functions:
  • The cosine function gives the x-component.
  • The sine function gives the y-component.
Finally, summing these components yields the net force in unit-vector notation, demonstrating how vector analysis applies to solving real-world physics problems.

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Most popular questions from this chapter

A long, hollow, cylindrical conductor (with inner radius \(2.0\) \(\mathrm{mm}\) and outer radius \(4.0 \mathrm{~mm}\) ) carries a current of \(24 \mathrm{~A}\) distributed uniformly across its cross section. A long thin wire that is coaxial with the cylinder carries a current of \(24 \mathrm{~A}\) in the opposite direction. What is the magnitude of the magnetic field (a) \(1.0\) \(\mathrm{mm}\), (b) \(3.0 \mathrm{~mm}\), and (c) \(5.0 \mathrm{~mm}\) from the central axis of the wire and cylinder?

Two long wires lie in an \(x y\) plane, and each carries a current in the positive direction of the \(x\) axis. Wire 1 is at \(y=10.0 \mathrm{~cm}\) and carries \(6.00 \mathrm{~A}\); wire 2 is at \(y=5.00 \mathrm{~cm}\) and carries \(10.0 \mathrm{~A}\). (a) In unitvector notation, what is the net magnetic field \(\vec{B}\) at the origin? (b) At what value of \(y\) does \(\vec{B}=0 ?(\mathrm{c})\) If the current in wire 1 is reversed, at what value of \(y\) does \(\vec{B}=0 ?\)

Three long wires all lie in an \(x y\) plane parallel to the \(x\) axis. They are spaced equally, \(10 \mathrm{~cm}\) apart. The two outer wires each carry a current of \(5.0 \mathrm{~A}\) in the positive \(x\) direction. What is the magnitude of the force on a \(3.0 \mathrm{~m}\) section of either of the outer wires if the current in the center wire is \(3.2 \mathrm{~A}\) (a) in the positive \(x\) direction and \((b)\) in the negative \(x\) direction?

Shows, in cross section, two long straight wires held against a plastic cylinder of radius \(20.0 \mathrm{~cm} .\) Wire 1 carries current \(i_{1}=\) \(60.0 \mathrm{~m} \mathrm{~A}\) out of the page and is fixed in place at the left side of the cylinder. Wire 2 carries current \(i_{2}=40.0\) \(\mathrm{m} \mathrm{A}\) out of the page and can be moved around the cylinder. At what (positive) angle \(\theta_{2}\) should wire 2 be positioned such that, at the origin, the net magnetic field due to the two currents has magnitude \(80.0 \mathrm{nT}\) ?

Shows a cross section across a diameter of a long cylindrical conductor of radius \(a=2.00 \mathrm{~cm}\) carrying uniform current \(170 \mathrm{~A}\). What is the magnitude of the current's magnetic field at radial distance (a) 0, (b) \(1.00 \mathrm{~cm},(\mathrm{c}) 2.00 \mathrm{~cm}\) (wire's surface), and (d) \(4.00 \mathrm{~cm} ?\)

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