Chapter 19: Problem 7
Suppose \(1.80 \mathrm{~mol}\) of an ideal gas is taken from a volume of \(3.00 \mathrm{~m}^{3}\) to a volume of \(1.50 \mathrm{~m}^{3}\) via an isothermal compression at \(30^{\circ} \mathrm{C}\). (a) How much energy is transferred as heat during the compression, and (b) is the transfer to or from the gas?
Short Answer
Step by step solution
Understand the Isothermal Process
Formula for Work Done in Isothermal Process
Convert Temperature to Kelvin
Plug Values into Work Formula
Calculate Natural Logarithm
Calculate Work Done
Determine Heat Transfer
Direction of Heat Transfer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Law
Understanding this equation is crucial as it bridges macroscopic properties like pressure and volume with the microscopic property of temperature.
- It allows the determination of any one of the variables if the others are known.
- It applies to ideal gases, which are hypothetical gases that perfectly follow this law under all conditions.
Work Done in Thermodynamics
This expression of work is useful because:
- It accounts for changes in volume while keeping temperature constant.
- It provides a means to compute energy exchanges without knowing precise details about pressure changes.
Heat Transfer in Thermodynamics
- This is typical of isothermal processes where the energy balance is tightly connected to external interactions, often observed in ideal gas behaviors.
- The positivity of \( Q \) in this exercise indicated energy being transferred to the gas to maintain temperature.
First Law of Thermodynamics
In an isothermal process for an ideal gas, \( \Delta U = 0 \), meaning all the work done on the system is equal to the heat exchange. This crucial relationship highlights:
- How energy transfers are balanced between work and heat.
- The invariance of internal energy in processes where temperature remains constant.