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(a) What is the volume occupied by \(1.00\) mol of an ideal gas at standard conditions \(-\) that is, \(1.00 \mathrm{~atm}\left(=1.01 \times 10^{5} \mathrm{~Pa}\right)\) and 273 K? (b) Show that the number of molecules per cubic centimeter (the Loschmidt number) at standard conditions is \(2.69 \times 10^{9}\).

Short Answer

Expert verified
(a) 2.24 脳 10鈦宦 m鲁; (b) 2.69 脳 10鹿鈦 molecules/cm鲁.

Step by step solution

01

Understanding Ideal Gas Law

The Volume of an ideal gas at standard temperature and pressure (STP) can be found using the Ideal Gas Law formula: \(PV = nRT\). Here, \(P\) is the pressure, \(V\) is the volume, \(n\) is the mole of gas, \(R\) is the ideal gas constant, and \(T\) is the temperature in Kelvin.
02

Setting Known Values

We substitute the known values into the Ideal Gas Law equation. Given \(n = 1.00\, \text{mol}\), \(T = 273\, \text{K}\), \(P = 1.01 \times 10^{5} \, \text{Pa}\), and \(R = 8.314 \, \text{Jmol}^{-1}\text{K}^{-1}\), the formula becomes \((1.01 \times 10^{5})V = 1.00 \times 8.314 \times 273\).
03

Solving for Volume

Rearrange the equation to solve for \(V\): \[ V = \frac{nRT}{P} = \frac{1.00 \times 8.314 \times 273}{1.01 \times 10^{5}} \approx 2.24 \times 10^{-2} \, \text{m}^3 \]. This volume corresponds to the volume occupied by 1 mol of gas at STP.
04

Converting Volume to Cubic Centimeters

To find the number of molecules per cubic centimeter, convert \(2.24 \times 10^{-2} \, \text{m}^3\) to cubic centimeters. Since \(1\, \text{m}^3 = 10^6\, \text{cm}^3\), then \(2.24 \times 10^{-2} \, \text{m}^3 = 2.24 \times 10^{4} \, \text{cm}^3\).
05

Calculating Loschmidt Number

The Loschmidt number is the number of molecules in one cubic centimeter of an ideal gas at STP. This can be calculated by dividing Avogadro鈥檚 number by the volume in cubic centimeters. Avogadro鈥檚 number is \(6.022 \times 10^{23}\). Therefore, the Loschmidt number is \(\frac{6.022 \times 10^{23}}{2.24 \times 10^{4}} \approx 2.69 \times 10^{19}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Avogadro's Number
Avogadro's Number is a fundamental concept in chemistry that represents the number of atoms or molecules in one mole of a substance. This number is not just a random figure; it is precisely defined as - 6.022 x 10^{23} particles per mole. This immense figure helps bridge macroscopic measurements that we can weigh and observe with the microscopic scale of atoms and molecules. Imagine a large group of similarly sized objects like peas. If you counted them individually, it would take ages. Avogadro鈥檚 number saves us this laborious work by linking the count of atoms/molecules to the weight of their total mass. In practical terms, when we use Avogadro's Number in equations such as in gas volume calculations, it allows us to determine how dense or sparse a gas is under varying conditions. This becomes particularly useful when calculating the Loschmidt number, which is the number of molecules per cubic centimeter at standard conditions.
Standard Temperature and Pressure (STP)
Standard Temperature and Pressure (STP) is a crucial concept for conducting gas volume calculations in chemistry. It provides a common ground or reference point for discussing gas properties. The standard conditions are defined as: - A temperature of 273 K (Kelvin), which corresponds to 0掳C, the freezing point of water. - A pressure of 1 atm (atmosphere), which is equivalent to 1.01 x 10^{5} Pa (Pascals). STP simplifies calculations because the behavior of gases is more predictable at these conditions. Under STP, one mole of an ideal gas occupies a volume of around 22.4 liters or 0.0224 cubic meters. These standardized conditions allow scientists and students to compare different experiments and theoretical calculations without discrepancies arising from variations in environmental conditions like temperature and pressure.
Gas Volume Calculations
Gas Volume Calculations allow us to predict and understand how gases behave under different conditions. By using the Ideal Gas Law, expressed as:\[ PV = nRT \]where:- \( P \) is the pressure,- \( V \) is the volume,- \( n \) is the number of moles of gas,- \( R \) is the ideal gas constant (8.314 J mol^{-1} K^{-1}),- \( T \) is the temperature in Kelvin.We can calculate the volume that a given amount of gas will occupy under specific conditions. For example, using the Ideal Gas Law at STP conditions allows us to determine the volume of 1 mole of gas, found to be approximately 0.0224 cubic meters or 22.4 liters.In our original exercise, the calculations proceeded to convert this volume into cubic centimeters and use Avogadro's number to find the Loschmidt number 鈥 the number of molecules per cubic centimeter. Thus, through systematic calculations, we derived the Loschmidt number as 2.69 x 10^{19}, emphasizing how interconnected these concepts are in understanding gas behaviors.

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Most popular questions from this chapter

In a certain particle accelerator, protons travel around a circular path of diameter \(23.0 \mathrm{~m}\) in an evacuated chamber, whose residual gas is at \(295 \mathrm{~K}\) and \(1.00 \times 10^{-6}\) torr pressure. (a) Calculate the number of gas molecules per cubic centimeter at this pressure. (b) What is the mean free path of the gas molecules if the molecular diameter is \(2.00 \times 10^{-8} \mathrm{~cm} ?\)

Determine the average value of the translational kinetic energy of the molecules of an ideal gas at (a) \(0.00^{\circ} \mathrm{C}\) and \((\mathrm{b}) 100^{\circ} \mathrm{C}\). What is the translational kinetic energy per mole of an ideal gas at (c) \(0.00^{\circ} \mathrm{C}\) and (d) \(100^{\circ} \mathrm{C} ?\)

When \(1.0 \mathrm{~mol}\) of oxygen \(\left(\mathrm{O}_{2}\right)\) gas is heated at constant pressure starting at \(0^{\circ} \mathrm{C}\), how much energy must be added to the gas as heat to double its volume? (The molecules rotate but do not oscillate.)

Oxygen \(\left(\mathrm{O}_{2}\right)\) gas at \(273 \mathrm{~K}\) and \(1.0 \mathrm{~atm}\) is confined to a cubical container \(10 \mathrm{~cm}\) on a side. Calculate \(\Delta U_{g} / K_{\text {avg }}\), where \(\Delta U_{g}\) is the change in the gravitational potential energy of an oxygen molecule falling the height of the box and \(K_{\text {avg }}\) is the molecule's average translational kinetic energy

The envelope and basket of a hot-air balloon have a combined weight of \(2.45 \mathrm{kN}\), and the envelope has a capacity (volume) of \(2.18 \times 10^{3} \mathrm{~m}^{3}\). When it is fully inflated, what should be the temperature of the enclosed air to give the balloon a lifting capacity (force) of \(2.67 \mathrm{kN}\) (in addition to the balloon's weight)? Assume that the surrounding air, at \(20.0^{\circ} \mathrm{C}\), has a weight per unit volume of \(11.9 \mathrm{~N} / \mathrm{m}^{3}\) and a molecular mass of \(0.028 \mathrm{~kg} / \mathrm{mol}\), and is at a pressure of \(1.0 \mathrm{~atm}\).

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