/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 117 A \(20 \mathrm{~kg}\) block on a... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(20 \mathrm{~kg}\) block on a horizontal surface is attached to a horizontal spring of spring constant \(k=4.0 \mathrm{kN} / \mathrm{m} .\) The block is pulled to the right so that the spring is stretched \(10 \mathrm{~cm}\) beyond its relaxed length, and the block is then released from rest. The frictional force between the sliding block and the surface has a magnitude of \(80 \mathrm{~N}\). (a) What is the kinetic energy of the block when it has moved \(2.0 \mathrm{~cm}\) from its point of release? (b) What is the kinetic energy of the block when it first slides back through the point at which the spring is relaxed? (c) What is the maximum kinetic energy attained by the block as it slides from its point of release to the point at which the spring is relaxed?

Short Answer

Expert verified
(a) 5.6 J, (b) 12 J, (c) 12 J.

Step by step solution

01

Calculate Initial Elastic Potential Energy

The initial elastic potential energy stored in the spring can be calculated using the formula for elastic potential energy: \[ U_i = \frac{1}{2} k x^2 \] where \(k = 4000 \ \text{N/m}\) and \(x = 0.1 \ \text{m}\). Substituting the values, we get:\[ U_i = \frac{1}{2} \times 4000 \times (0.1)^2 = 20 \ \text{J} \]
02

Calculate Work Done by Friction

The work done by friction as the block moves the initial 2.0 cm is given by:\[ W_f = - f_d \times d \]where \(f_d = 80 \ \text{N}\) and \(d = 0.02 \ \text{m}\).Thus, \[ W_f = -80 \times 0.02 = -1.6 \ \text{J} \]
03

Apply Work-Energy Principle for 2 cm Movement

The work-energy principle states that the change in kinetic energy is the sum of work done by conservative and non-conservative forces:\[ \Delta K = (U_f + K_f) - U_i = W_f + U_f \] Here, \(U_f\) is the final potential energy when spring is compressed 8cm \([0.1-0.02] \text{m} =0.08 \text{m})\):\[ U_f = \frac{1}{2} \times 4000 \times (0.08)^2 = 12.8 \text{J} \]Substituting into the energy equation:\[ 0 + K_f - 20 = -1.6 + 12.8 \]\[ K_f = 5.6 \ \text{J} \] The kinetic energy of the block when it has moved 2.0 cm is 5.6 J.
04

Calculate Kinetic Energy at Relaxed Spring Point (b)

At the point the spring is relaxed again (0 cm from the equilibrium), the only work done is by friction; the spring's potential energy is zero. So:\[ \Delta K = -W_f \] The friction has done work over 10 cm from initial release to the relaxed point:\[ W_f = -80 \times 0.10 = -8 \ \text{J} \] The total energy change is:\[ 0 + K_f - 20 = -8 \] \[ K_f = 12 \ \text{J} \]The kinetic energy as it first passes the relaxed point is 12 J.
05

Determine Maximum Kinetic Energy (c)

The maximum kinetic energy occurs just before the work done by friction reduces to zero potential energy at a half-compressed point during oscillation. So:\[ K_{max} = U_i + W_{total} \]From the energetic confines, all initial potential energy is converted:\[ K_{max} = 20 - 8 = 12 \ \text{J} \]Maximum kinetic energy attained as it slides is 12 J.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elastic Potential Energy
When a spring is stretched or compressed from its natural position, it stores energy in the form of elastic potential energy. This energy is what allows the spring to do work when released. The formula for calculating elastic potential energy is given by:
  • \[ U = \frac{1}{2} k x^2 \]
where:
  • \( k \) is the spring constant (in N/m), and
  • \( x \) is the displacement from the spring's equilibrium position (in meters).
The spring constant is a measure of the stiffness of the spring; the larger it is, the more force is required to stretch or compress the spring. For instance, if a spring with a spring constant \( k = 4000 \, \text{N/m} \) is stretched by 10 cm \((0.1 \, \text{m})\), the initial elastic potential energy can be calculated as:
  • \[ U_i = \frac{1}{2} \times 4000 \times (0.1)^2 = 20 \, \text{J} \]
This stored energy is what will transform into kinetic energy or work done against friction as the spring returns to its relaxed state.
Work-Energy Principle
The work-energy principle is a fundamental concept in physics that relates the work done on an object to its change in kinetic energy. It states that the total work done by all the forces acting on an object equals the change in its kinetic energy:
  • \[ \Delta K = W \]
Here, \( \Delta K \) represents the change in kinetic energy, while \( W \) signifies the work done by all forces (both conservative and non-conservative). In the context of the spring-block system:
  • The spring does work through its potential energy, converting it to kinetic energy as it tries to return to its equilibrium length.
  • Friction is a non-conservative force that does negative work, reducing the system's total mechanical energy.
When the block connected to the spring moves from its stretched position, the kinetic energy gained is less than the potential energy due to the work done against friction. For example, if the friction performed work of -1.6 J over the initial 2 cm, and the potential energy decreased by 7.2 J, the new kinetic energy of the block was 5.6 J. This principle helps predict the energy and speed of the block at different positions of its journey.
Frictional Force
Friction is a resistive force that acts opposite to the direction of motion between two surfaces in contact. It plays a crucial role in energy transformations within systems. In our exercise, the frictional force between the block and the surface affects how the energy is converted and propagated through the block’s oscillation.The work done by friction, which is a non-conservative force, can be expressed as:
  • \[ W_f = - f_d \times d \]
where:
  • \( f_d \) is the magnitude of the frictional force (80 N in this instance), and
  • \( d \) is the distance over which the force acts (in meters).
This work results in a loss of mechanical energy from the system, usually transforming it into thermal energy. As the block moves toward its equilibrium point from its initial stretched position, the friction performs work against the block’s motion. If the block travels 10 cm (0.1 m) back to its initial point of release, the work done by friction is 8 J. This loss is crucial in understanding how the energy from the spring translates to kinetic energy in the presence of friction. It's essential for analyzing real-world scenarios as it highlights the limitations of energy conservation in practical systems.

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Most popular questions from this chapter

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