/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 Two blocks, of masses \(M=2.0 \m... [FREE SOLUTION] | 91Ó°ÊÓ

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Two blocks, of masses \(M=2.0 \mathrm{~kg}\) and \(2 M,\) are connected to a spring of spring constant \(k=200 \mathrm{~N} / \mathrm{m}\) that has one end fixed, as shown in Fig. \(8-69 .\) The horizontal surface and the pulley are frictionless, and the pulley has negligible mass. The blocks are released from rest with the spring relaxed. (a) What is the combined kinetic energy of the two blocks when the hanging block has fallen \(0.090 \mathrm{~m} ?\) (b) What is the kinetic energy of the hanging block when it has fallen that \(0.090 \mathrm{~m} ?\) (c) What maximum distance does the hanging block fall before momentarily stopping?

Short Answer

Expert verified
(a) 2.718 J, (b) 1.812 J, (c) 0.784 m

Step by step solution

01

Analyze the System

We have two blocks, one resting on a horizontal surface and another hanging. Block on the table has mass \(M = 2.0\,\mathrm{kg}\) and the hanging block has mass \(2M = 4.0\,\mathrm{kg}\). Both are connected via a spring of spring constant \(k = 200\,\mathrm{N/m}\). The hanging block is allowed to fall, stretching the spring.
02

Use Conservation of Energy for (a)

Initially, both blocks are at rest, so mechanical energy is conserved. The potential energy lost by the hanging block equals the kinetic energy of the system plus the potential energy in the spring when the block has fallen \(0.090\,\mathrm{m}\).Initial energy = \(U_i = Mgh + 0 = 4.0\cdot9.8\cdot0.090\,\mathrm{J}\).Final energy = \(K_f + U_f = \frac{1}{2}k(0.090)^2\,\mathrm{J}\).Solve for \(K_f\):\[K_f = U_i - U_f = 3.528 - 0.810 = 2.718\,\mathrm{J}.\]
03

Calculate Kinetic Energy for Block (b)

The hanging block has mass \(2M\) and contributes individually to part of the kinetic energy. The kinetic energy of the hanging block \(K_m\) can be determined using the velocity relations between both blocks' centers of mass (same magnitude) and ratios of kinetic energies. Given velocities are equal in magnitude through the pulley system, \(K_m = \frac{1}{3}\cdot2.718\,\mathrm{J} = 1.812\, \mathrm{J}\).
04

Calculate Maximum Distance Fallen for (c)

The maximum distance the block falls before stopping occurs when all kinetic energy is converted into spring potential energy.The initial gravitational potential energy becomes the spring potential energy:\[\frac{1}{2}k x^2 = 2Mgh.\]Substitute and solve \[100x^2 = 4.0\cdot9.8\cdot x\]where \(x\) is the maximum fall distance, solve the quadratic\[x = 0.784\,\mathrm{m}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Dynamics
Spring dynamics play a significant role in systems involving mass and springs. To understand these dynamics, it's essential to grasp how a spring behaves under force or deformation. Hooke’s Law is the cornerstone of spring dynamics. It describes the force exerted by a spring when it is compressed or stretched. According to Hooke’s Law, the force required to compress or extend a spring is proportional to the distance it is stretched. The formula is given by
  • F = -kx
where
  • F is the force exerted by the spring in newtons (N),
  • k is the spring constant in newtons per meter (N/m),
  • and x is the displacement from the spring's equilibrium position in meters (m).
The negative sign indicates that the spring's force is always in the opposite direction to the displacement. Springs store potential energy when they are either compressed or elongated, which is known as spring potential energy. This potential energy can be calculated by the formula
  • \[ U = \frac{1}{2} k x^2 \]
This energy becomes significant in systems where both gravitational and spring potential energies come into play, such as the block-spring system described in this exercise.
Kinetic Energy Calculation
Kinetic energy represents the energy of motion. Whenever an object moves, it carries kinetic energy, defined by the formula
  • \[ K = \frac{1}{2} mv^2 \]
where
  • m is the mass of the object in kilograms (kg),
  • and v is its velocity in meters per second (m/s).
In a system involving multiple objects, such as our blocks connected via a spring, the total kinetic energy of the system is the sum of the kinetic energies of all moving parts. The exercise you conducted required calculating the total kinetic energy when the hanging block fell a certain distance and determining the kinetic energy possessed specifically by the hanging block. When working with such systems, it's crucial to consider
  • the constraints imposed by connections like strings or springs, and
  • use conservation laws to distribute the total energy correctly among the components during analysis.
Gravitational Potential Energy
Gravitational potential energy is the energy stored due to an object's position in a gravitational field. This is particularly relevant to systems where vertical motion is involved, such as a block falling under gravity's influence. The formula for gravitational potential energy is
  • \[ U = mgh \]
where
  • m is the object's mass in kilograms (kg),
  • g is the acceleration due to gravity (approximately 9.8 m/s² on Earth),
  • and h is the height of the object above a reference point in meters (m).
In this exercise, the decrease in gravitational potential energy as the block descends is what drives the transformation into kinetic energy and, partly, into spring potential energy. Gravitational potential energy helps to describe why objects may accelerate as they fall and how this potential energy is crucially converted into other forms of energy during the process. Such conversions underpin the principle of conservation of energy, an indispensable tool in solving physics problems.

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Most popular questions from this chapter

110 A \(5.0 \mathrm{~kg}\) block is projected at \(5.0 \mathrm{~m} / \mathrm{s}\) up a plane that is inclined at \(30^{\circ}\) with the horizontal. How far up along the plane does the block go (a) if the plane is frictionless and (b) if the coefficient of kinetic friction between the block and the plane is \(0.40 ?\) (c) In the latter case, what is the increase in thermal energy of block and plane during the block's ascent? (d) If the block then slides back down against the frictional force, what is the block's speed when it reaches the original projection point?

A boy is initially seated on the top of a hemispherical ice mound of radius \(R=13.8 \mathrm{~m} . \mathrm{He}\) begins to slide down the ice, with a negligible initial speed (Fig. 8-47). Approximate the ice as being frictionless. At what height does the boy lose contact with the ice?

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