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On August \(10,1972,\) a large meteorite skipped across the atmosphere above the western United States and western Canada, much like a stone skipped across water. The accompanying fireball was so bright that it could be seen in the daytime sky and was brighter than the usual meteorite trail. The meteorite's mass was about \(4 \times 10^{6} \mathrm{~kg}\) : its speed was about \(15 \mathrm{~km} / \mathrm{s}\). Had it entered the atmosphere vertically, it would have hit Earth's surface with about the same speed. (a) Calculate the meteorite's loss of kinetic energy (in joules) that would have been associated with the vertical impact. (b) Express the energy as a multiple of the explosive energy of 1 megaton of \(\mathrm{TNT}\), which is \(4.2 \times 10^{15} \mathrm{~J}\). (c) The energy associated with the atomic bomb explosion over Hiroshima was equivalent to 13 kilotons of TNT. To how many Hiroshima bombs would the meteorite impact have been equivalent?

Short Answer

Expert verified
The vertical impact would release about 0.107 megatons of TNT or be equivalent to about 8.24 Hiroshima bombs.

Step by step solution

01

Kinetic Energy Formula

The formula to calculate the kinetic energy (KE) of an object in motion is given by \( KE = \frac{1}{2}mv^2 \), where \( m \) is the mass and \( v \) is the velocity. For the meteorite, \( m = 4 \times 10^6 \mathrm{~kg} \) and \( v = 15 \mathrm{~km/s} = 15000 \mathrm{~m/s} \).
02

Calculate Kinetic Energy

Apply the values into the kinetic energy formula: \( KE = \frac{1}{2} \times 4 \times 10^6 \times (15000)^2 \). After calculating, \( KE = 4.5 \times 10^{14} \mathrm{~J} \).
03

Express KE as Multiple of Megatons of TNT

1 megaton of TNT is equivalent to \(4.2 \times 10^{15} \mathrm{~J}\). To find how many megatons of TNT are equivalent to the meteorite's energy, divide the kinetic energy by this value: \( \frac{4.5 \times 10^{14}}{4.2 \times 10^{15}} \approx 0.107 \) megatons of TNT.
04

Calculate Equivalent Hiroshima Bombs

The energy of the Hiroshima bomb was equivalent to 13 kilotons of TNT, where 1 kiloton of TNT equals \(4.2 \times 10^{12} \mathrm{~J}\). Therefore, 13 kilotons equals \( 13 \times 4.2 \times 10^{12} = 5.46 \times 10^{13} \mathrm{~J} \). To find the equivalent number of Hiroshima bombs, divide the meteorite's energy by the energy of one Hiroshima bomb: \( \frac{4.5 \times 10^{14}}{5.46 \times 10^{13}} \approx 8.24 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Meteorite Impact
Meteorites are fragments of asteroids or comets that have entered Earth's atmosphere. When they collide with Earth, they can cause significant damage due to their mass and high velocity. In our exercise, we examine a meteorite with a mass of \(4 \times 10^6 \text{ kg}\) and a velocity of \(15 \text{ km/s}\). As it travels through the atmosphere, it converts its kinetic energy into heat and light, accounting for the bright fireball observed during such events. If this meteorite had struck Earth's surface directly, its kinetic energy on impact would have been immense, equivalent to the energy produced by a large nuclear explosion.

The meteorite's velocity is a crucial factor in determining its impact energy. Higher velocity means greater kinetic energy, which increases the potential for destruction. Thankfully, many meteorites either explode in the atmosphere due to pressure or lose velocity as they travel, reducing the impact on the surface. However, understanding the potential impact is essential for assessing risks from celestial objects.
Energy Conversion
Energy conversion in physics often involves changing one form of energy into another. In the case of a meteorite impact, kinetic energy is primarily converted into thermal energy, creating a bright fireball. Kinetic energy can be expressed as \( KE = \frac{1}{2}mv^2 \), where \( m \) is the mass and \( v \) is the velocity.

For a deeper understanding, consider how the kinetic energy changes during a vertical impact. As the meteorite with mass \( 4 \times 10^6 \text{ kg} \) travels at \( 15000 \text{ m/s} \), its kinetic energy is calculated using the formula to be \( 4.5 \times 10^{14} \text{ J} \). This immense energy is due to the meteorite’s mass and high speed.

Once the meteorite enters the atmosphere, various factors like air resistance and pressure begin to convert this kinetic energy into other forms, primarily heat. This results in the spectacular light and, if it impacts, a ground shock that could cause significant damage.
Explosive Energy Equivalence
The energy equivalence of a meteorite impact in terms of explosive energy provides an intuitive way to grasp the immense energy involved. In this problem, we express the meteorite's kinetic energy in terms of megatons of TNT.

One megaton of TNT is defined as \(4.2 \times 10^{15} \text{ J}\). By dividing the meteorite's energy \( 4.5 \times 10^{14} \text{ J} \) by this value, we find it equates to about \(0.107\) megatons of TNT. This comparison allows us to appreciate the scale of energy that a celestial object would release upon impact with Earth.

Additionally, comparing this energy to the atomic bomb dropped on Hiroshima, which had an energy equivalent of \(13\) kilotons of TNT, or \(5.46 \times 10^{13} \text{ J}\), offers another perspective. Performing this comparison, the meteorite's impact would be equivalent to about \(8.24\) Hiroshima bombs. These comparisons highlight the potential destructive power of meteor impacts and underscore the importance of monitoring near-Earth objects.

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