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A proton (mass \(m=1.67 \times 10^{-27} \mathrm{~kg}\) ) is being accelerated along a straight line at \(3.6 \times 10^{15} \mathrm{~m} / \mathrm{s}^{2}\) in a machine. If the proton has an initial speed of \(2.4 \times 10^{7} \mathrm{~m} / \mathrm{s}\) and travels \(3.5 \mathrm{~cm},\) what then is (a) its speed and (b) the increase in its kinetic energy?

Short Answer

Expert verified
(a) The speed is approximately \(2.877 \times 10^7 \ m/s\). (b) The increase in kinetic energy is \(2.10 \times 10^{-13} \ J\).

Step by step solution

01

Convert Units

First, we need to convert the distance traveled from centimeters to meters, because the SI units for speed and acceleration are in meters per second. The distance traveled is 3.5 cm, which is equivalent to 0.035 meters.
02

Use Kinematic Equation for Speed

We use the kinematic equation to find the final speed: \( v^2 = u^2 + 2as \), where \( u = 2.4 \times 10^7 \ m/s \) is the initial speed, \( a = 3.6 \times 10^{15} \ m/s^2 \) is the acceleration, and \( s = 0.035 \ m \) is the distance traveled. Solving for \( v \):\[ v^2 = (2.4 \times 10^7)^2 + 2 \times 3.6 \times 10^{15} \times 0.035 \]\[ v^2 = 5.76 \times 10^{14} + 2.52 \times 10^{14} \]\[ v^2 = 8.28 \times 10^{14} \]\[ v = \sqrt{8.28 \times 10^{14}} \approx 2.877 \times 10^7 \ m/s \]
03

Calculate Initial Kinetic Energy

The kinetic energy at the initial speed \( u \) is given by \( KE_i = \frac{1}{2}mu^2 \). Substituting the given values:\[ KE_i = \frac{1}{2} \times 1.67 \times 10^{-27} \times (2.4 \times 10^7)^2 \]\[ KE_i = 0.5 \times 1.67 \times 10^{-27} \times 5.76 \times 10^{14} \]\[ KE_i = 4.81 \times 10^{-13} \ J \]
04

Calculate Final Kinetic Energy

Now, find the kinetic energy at the final speed \( v \): \( KE_f = \frac{1}{2}mv^2 \). Using the computed final speed:\[ KE_f = \frac{1}{2} \times 1.67 \times 10^{-27} \times (2.877 \times 10^7)^2 \]\[ KE_f = 0.5 \times 1.67 \times 10^{-27} \times 8.28 \times 10^{14} \]\[ KE_f = 6.91 \times 10^{-13} \ J \]
05

Compute Increase in Kinetic Energy

Finally, the increase in kinetic energy \( \Delta KE \) is the difference between the final and initial kinetic energy: \[ \Delta KE = KE_f - KE_i \]\[ \Delta KE = 6.91 \times 10^{-13} - 4.81 \times 10^{-13} \]\[ \Delta KE = 2.10 \times 10^{-13} \ J \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton Acceleration
Acceleration is a fundamental concept in physics that describes how the velocity of an object changes over time. When we talk about proton acceleration, we're referring to how fast a proton's speed increases.
In this exercise, a proton is being accelerated at a rate of \(3.6 \times 10^{15} \text{ m/s}^2\). This is an incredibly high acceleration rate, much greater than what we experience in everyday life. This kind of acceleration is typically found in scientific experiments and particle accelerators, where particles like protons are sped up to extremely high velocities in a controlled environment.
  • High acceleration means the proton will reach a very high speed in a short period of time.
  • Acceleration is defined as the change in velocity divided by the time taken for that change.
Understanding how acceleration works is key to analyzing the motion of particles like protons, especially in fields such as nuclear physics and medical imaging.
Kinetic Energy
Kinetic energy is the energy possessed by an object due to its motion. For objects with mass, like a proton, the kinetic energy can be calculated using the formula: \( KE = \frac{1}{2}mv^2 \), where \( m \) is the mass and \( v \) is the velocity.
In this exercise, both initial and final kinetic energies of the proton have been calculated. The kinetic energy changes as the proton speeds up due to acceleration.
  • The initial kinetic energy \( KE_i \) was calculated using the initial velocity \( u \).
  • The final kinetic energy \( KE_f \) was determined using the final velocity \( v \), which was found through kinematic equations.
  • The difference between \( KE_f \) and \( KE_i \) gives us the increase in kinetic energy, which measures how much the energy has grown as the proton accelerated.
Understanding kinetic energy is crucial for various applications, including evaluating the energy transformations in particle accelerators and ensuring the designs are efficient and safe.
Kinematic Calculations
Kinematic calculations are used to determine various parameters of motion, such as velocity, acceleration, and displacement, without considering the forces that cause this motion. These calculations are based on a set of equations that describe motion in a straight line.
In this context, the exercise uses the kinematic equation \( v^2 = u^2 + 2as \) to find the final speed of the proton. Here's a brief breakdown:
  • \( u \) represents the initial velocity, \( a \) is the acceleration, and \( s \) is the distance traveled.
  • By substituting the known values into the equation, one can solve for the final velocity \( v \).
This type of problem emphasizes the importance of unit consistency (like converting centimeters to meters) and correct substitution into the formula. Mastery of kinematic calculations allows students and professionals to predict the future position and speed of objects moving in space, which can be applied in engineering, navigation, and various scientific research areas.

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Most popular questions from this chapter

A coin slides over a frictionless plane and across an \(x y\) coordinate system from the origin to a point with \(x y\) coordinates \((3.0 \mathrm{~m}, 4.0 \mathrm{~m})\) while a constant force acts on it. The force has magnitude \(2.0 \mathrm{~N}\) and is directed at a counterclockwise angle of \(100^{\circ}\) from the positive direction of the \(x\) axis. How much work is done by the force on the coin during the displacement?

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A cord is used to vertically lower an initially stationary block of mass \(M\) at a constant downward acceleration of \(g / 4\). When the block has fallen a distance \(d\), find (a) the work done by the cord's force on the block, (b) the work done by the gravitational force on the block, (c) the kinetic energy of the block, and (d) the speed of the block.

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