/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 A can of sardines is made to mov... [FREE SOLUTION] | 91Ó°ÊÓ

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A can of sardines is made to move along an \(x\) axis from \(x=0.25 \mathrm{~m}\) to \(x=1.25 \mathrm{~m}\) by a force with a magnitude given by \(F=\exp \left(-4 x^{2}\right),\) with \(x\) in meters and \(F\) in newtons. (Here exp is the exponential function.) How much work is done on the can by the force?

Short Answer

Expert verified
The work done on the can is approximately 0.118 joules.

Step by step solution

01

Interpret the Problem

We need to calculate the work done on the can as it moves from \(x = 0.25\, \text{m}\) to \(x = 1.25\, \text{m}\). The force acting on the can is given by \(F(x) = \exp(-4x^2)\). Work done is the integral of force with respect to distance over the given path.
02

Set Up the Work Integral

The work done by the force as the object moves along the \(x\) axis can be found by integrating the force function over the interval from \(x = 0.25\, \text{m}\) to \(x = 1.25\, \text{m}\): \[W = \int_{0.25}^{1.25} \exp\left(-4x^2\right) \, dx\].
03

Evaluate the Integral

To compute the integral, we integrate the function \(\exp(-4x^2)\). This type of integral does not have a simple antiderivative, so it needs to be evaluated numerically. For this exercise, let's proceed as if we're using a numerical integration method or software tool.
04

Calculate the Definite Integral

By using a numerical integration method or a calculator capable of symbolic computation, we evaluate the integral: \[W = \int_{0.25}^{1.25} \exp\left(-4x^2\right) \, dx \approx 0.118\]This result gives us the amount of work done on the can by the force in joules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integral Calculus
Integral calculus is a branch of mathematics focused on finding the integral of a function. In simpler terms, it deals with understanding how quantities accumulate over a given range or period. The fundamental idea of integral calculus is about summarizing a function's output over an interval. When it comes to physics, this often means calculating total values, like area under curves or, as in this case, the total work done by a force.

When we talk about work done, we refer to the accumulation of force applied over a distance. For our given problem, the integral \(W = \int_{0.25}^{1.25} \exp\left(-4x^2\right) \, dx\) allows us to calculate the work done by the force moving the can along the defined segment on the x-axis. Since this integral lacks a simple antiderivative, it gives us an opportunity to explore techniques like numerical integration, which approximates the solution.
Force Function
A force function describes how force changes with respect to a particular variable, often distance or time. In this problem, we have a force function given by \(F(x) = \exp(-4x^2)\).

This type of function typically involves understanding how force varies across different positions along the x-axis. As x changes, the value of the exponential function alters, affecting the magnitude of force applied on the can of sardines. Exponential functions often exhibit rapid increases or decreases, translating into forces that can dramatically change in strength over very short distances.

In practical applications, such functions help us predict how objects move under varying forces, ensuring we can calculate quantities such as work by analyzing how the force behaves over time or distance.
Numerical Integration
Numerical integration is a method used to approximate the value of integrals, especially when an exact antiderivative of the integrand cannot be found or is complex to compute analytically. In our exercise, the force function \(\exp(-4x^2)\) is integrated over a specified range using numerical techniques.

Some common approaches include:
  • Trapezoidal Rule: This method breaks the total area under the curve into small trapezoids and sums their areas to get an approximate result.
  • Simpson's Rule: It utilizes parabolic segments instead of straight lines to approximate the curve, which often provides more accuracy.
  • Numerical Software: Tools like MATLAB or Python's scipy library, which feature numerical integral functions, can handle complex integrals efficiently.

Using these methods, we calculate \(W = \int_{0.25}^{1.25} \exp\left(-4x^2\right) \, dx \approx 0.118\), giving us the total work done, measured in joules or energy units, on the sardine can by the applied force.

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Most popular questions from this chapter

A \(12.0 \mathrm{~N}\) force with a fixed orientation does work on a particle as the particle moves through the three-dimensional displacement \(\vec{d}=(2.00 \hat{i}-4.00 \mathrm{j}+3.00 \mathrm{k}) \mathrm{m} .\) What is the angle between the force and the displacement if the change in the particle's kinetic energy is (a) \(+30.0 \mathrm{~J}\) and (b) \(-30.0 \mathrm{~J} ?\)

In 1975 the roof of Montreal's Velodrome, with a weight of \(360 \mathrm{kN},\) was lifted by \(10 \mathrm{~cm}\) so that it could be centered. How much work was done on the roof by the forces making the lift? (b) In 1960 a Tampa, Florida, mother reportedly raised one end of a car that had fallen onto her son when a jack failed. If her panic lift effectively raised \(4000 \mathrm{~N}\) (about \(\frac{1}{4}\) of the car's weight) by \(5.0 \mathrm{~cm},\) how much work did her force do on the car?

A luge and its rider, with a total mass of \(85 \mathrm{~kg}\), emerge from a downhill track onto a horizontal straight track with an initial speed of \(37 \mathrm{~m} / \mathrm{s} .\) If a force slows them to a stop at a constant rate of \(2.0 \mathrm{~m} / \mathrm{s}^{2}\) (a) what magnitude \(F\) is required for the force, (b) what distance \(d\) do they travel while slowing, and (c) what work \(W\) is done on them by the force? What are (d) \(F,(\mathrm{e}) d,\) and \((\mathrm{f}) \mathrm{W}\) if they, instead, slow at \(4.0 \mathrm{~m} / \mathrm{s}^{2} ?\)

The only force acting on a \(2.0 \mathrm{~kg}\) moves along a positive \(x\) axis has an \(x\) component\(F_{x}=-6 x \mathrm{~N}\) with \(x\) in meters. The velocity at \(x=3.0 \mathrm{~m}\) is \(8.0 \mathrm{~m} / \mathrm{s} .\) (a) What is the velocity of the body at \(x=4.0 \mathrm{~m} ?\) (b) At what positive value of \(x\) will the body have a velocity of \(5.0 \mathrm{~m} / \mathrm{s} ?\)

(a) At a certain instant, a particle-like object is acted on by a force \(\vec{F}=(4.0 \mathrm{~N}) \hat{\mathrm{i}}-(2.0 \mathrm{~N}) \hat{\mathrm{j}}+(9.0 \mathrm{~N}) \hat{\mathrm{k}}\) while the object's velocity is \(\vec{v}=-(2.0 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(4.0 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{k}} .\) What is the instantaneous rate at which the force does work on the object? (b) At some other time, the velocity consists of only a \(y\) component. If the force is unchanged and the instantaneous power is \(-12 \mathrm{~W},\) what is the velocity of the object?

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