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Compute the weight of a \(75 \mathrm{~kg}\) space ranger (a) on Earth, (b) on Mars, where \(g=3.7 \mathrm{~m} / \mathrm{s}^{2},\) and \((\mathrm{c})\) in interplanetary space, where \(g=0 .\) (d) What is the ranger's mass at each location?

Short Answer

Expert verified
Weight: Earth: 735 N; Mars: 277.5 N; Space: 0 N. Mass: 75 kg everywhere.

Step by step solution

01

Identifying the Formula for Weight

The weight of an object is calculated using the formula, \( W = m \cdot g \), where \( W \) is the weight, \( m \) is the mass, and \( g \) is the acceleration due to gravity.
02

Calculate Weight on Earth

The acceleration due to gravity on Earth is approximately \(9.8 \ m/s^2\). The mass of the space ranger is \(75 \ kg\). Thus, the weight \(W\) on Earth is calculated as:\( W = 75 \ kg \cdot 9.8 \ m/s^2 = 735 \ N \) (Newtons).
03

Calculate Weight on Mars

The acceleration due to gravity on Mars is \(3.7 \ m/s^2\). For the same mass, the weight on Mars is:\( W = 75 \ kg \cdot 3.7 \ m/s^2 = 277.5 \ N \) (Newtons).
04

Determine Weight in Interplanetary Space

In interplanetary space, the acceleration due to gravity is \(0\ m/s^2\). Therefore, the weight in space is:\( W = 75 \ kg \cdot 0 \ m/s^2 = 0 \ N \) (Newtons).
05

Finding Mass at Each Location

The mass of an object is intrinsic and does not change with location. Therefore, the mass of the space ranger is the same at each location: 75 kg.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Weight Calculation
When calculating weight, we always start with the formula: \[ W = m \cdot g \]Here, \(W\) represents weight, \(m\) is mass, and \(g\) is the acceleration due to gravity. The weight of an object is directly related to its mass and the gravitational pull at a given location.
- On Earth, for instance, the acceleration due to gravity \(g\) is approximately \(9.8\ m/s^2\). Hence, an object’s weight can be calculated by multiplying its mass by this value.
- On Mars, the gravitational pull is significantly weaker, approximately \(3.7\ m/s^2\), resulting in a lighter weight without altering the object’s mass.
Again, in interplanetary space, with gravity being effectively zero \(0\ m/s^2\), any object would be weightless. This demonstrates how weight can vary drastically, depending on the gravitational force applied.
Mass and Weight
Mass and weight, though related, are distinctly different. Mass refers to the amount of matter in an object and remains the same regardless of location. In our example, the space ranger's mass is consistently 75 kg, whether they are on Earth, Mars, or floating freely in space.
- Mass is intrinsic and does not depend on other factors, it is constant. It's something that doesn't change unless physical matter is added or removed. - Weight is a measure of how much gravitational force acts upon that mass. It varies by the gravitational acceleration present at a given location. This distinction is important because it underscores how weight can change under different gravitational conditions, even though the mass stays constant.
Newton's Laws of Motion
Newton's laws of motion play a crucial role in understanding how objects behave under different circumstances. The first law, often called the law of inertia, explains that an object will remain at rest or in uniform motion unless acted upon by an external force.
This links to how weight is influenced by gravity. An object in space, with negligible gravitational forces, might float, demonstrating Newton's first law, as no net external force acts on it.- The second law establishes a fundamental equation, which expresses the relation between force, mass, and acceleration: \[ F = m \cdot a \] This is similar to our weight calculation formula, but it applies to any force situation, not just gravity.- Newton’s third law, the action-reaction law, might not directly apply to our weight exercise, but it tells us that every interaction involves two forces acting reciprocally on the interacting objects.
Understanding these laws provides a foundation for comprehending how weight changes in different locations, each governed by unique gravitational conditions.

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Most popular questions from this chapter

A nucleus that captures a stray neutron must bring the neutron to a stop within the diameter of the nucleus by means of the strong force. That force, which "glues" the nucleus together, is approximately zero outside the nucleus. Suppose that a stray neutron with an initial speed of \(1.4 \times 10^{7} \mathrm{~m} / \mathrm{s}\) is just barely captured by a nucleus with diameter \(d=1.0 \times 10^{-14} \mathrm{~m} .\) Assuming the strong force on the neutron is constant, find the magnitude of that force. The neutron's mass is \(1.67 \times 10^{-27} \mathrm{~kg}\).

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An \(85 \mathrm{~kg}\) man lowers himself to the ground from a height of \(10.0 \mathrm{~m}\) by holding onto a rope that runs over a frictionless pulley to a \(65 \mathrm{~kg}\) sandbag. With what speed does the man hit the ground if he started from rest?

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