/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 89 A \(1400 \mathrm{~kg}\) jet engi... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(1400 \mathrm{~kg}\) jet engine is fastened to the fuselage of a passenger jet by just three bolts (this is the usual practice). Assume that each bolt supports one-third of the load. (a) Calculate the force on each bolt as the plane waits in line for clearance to take off. (b) During flight, the plane encounters turbulence, which suddenly imparts an upward vertical acceleration of \(2.6 \mathrm{~m} / \mathrm{s}^{2}\) to the plane. Calculate the force on each bolt now.

Short Answer

Expert verified
(a) 4573.33 N (b) 5740 N

Step by step solution

01

Understand the problem setup

We are given a 1400 kg jet engine attached to a fuselage by three bolts. Each bolt shares an equal part of the load. The first part involves calculating the force on each bolt while the plane is stationary and the second part while the plane experiences an upward acceleration.
02

Calculate the weight of the engine

The weight of the engine can be calculated using the formula: \[ \text{Weight } (W) = m \cdot g \]where \(m\) is the mass of the engine (1400 kg) and \(g\) is the acceleration due to gravity (approximately 9.8 m/s²). Thus, \[ W = 1400 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 13720 \, \text{N} \]
03

Calculate the force on each bolt while stationary

Since there are three bolts, each supporting one-third of the total weight, the force on each bolt is:\[ F = \frac{W}{3} = \frac{13720 \, \text{N}}{3} = 4573.33 \, \text{N}\]
04

Calculate the total effective force during turbulence

When the plane is in turbulence with an upward acceleration of 2.6 m/s², the effective gravitational force on the engine is increased. Use Newton's second law to find the total force:\[ F_\text{total} = m \cdot (g + a) \]where \(a\) is the upward acceleration (2.6 m/s²). So, \[ F_\text{total} = 1400 \, \text{kg} \times (9.8 + 2.6) \, \text{m/s}^2 = 17220 \, \text{N} \]
05

Calculate the force on each bolt during turbulence

Again, divide the total effective force by the number of bolts to find the force on each bolt:\[ F = \frac{F_\text{total}}{3} = \frac{17220 \, \text{N}}{3} = 5740 \, \text{N} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force Calculation
In the realm of physics, calculating forces is fundamental, especially in solving real-world problems like those seen in mechanical engineering applications. Forces are vectors, meaning they have both magnitude and direction. To calculate the force acting on an object, we rely on Newton's Second Law, which states that Force (\( F \)) is equal to mass (\( m \)) multiplied by acceleration (\( a \)). The formula is expressed as:
    \( F = m \cdot a \)

For the problem at hand, this principle enables us to comprehend how much force each bolt withstands when stabilizing a jet engine. Initially, when the plane is stationary, the only force at work is the weight of the engine, calculated using the gravitational pull (\( g \)) of about \( 9.8 \) m/s². In such cases, we determine the force shared equally among the three bolts attaching the jet engine.
During flight, if the aircraft experiences additional acceleration due to turbulence, the effective gravitational force changes. Hence, re-calculating the force on each bolt under these new conditions involves accounting for additional upward acceleration acting on the aircraft.
Acceleration
Acceleration refers to the rate at which an object changes its velocity. In mechanical engineering, understanding acceleration is vital because it directly influences the forces that need to be computed and managed in structural designs.
  • Acceleration is not only due to gravity; it can also be imparted by other factors – like external forces causing upward motion.
  • It is measured in meters per second squared (m/s²).

In the given problem, an upward acceleration of \(2.6 \text{ m/s}^2\) is introduced during the aircraft's flight. This additional acceleration impacts the force experienced by each bolt. To calculate this new force, we integrate the extra acceleration into Newton's Second Law, adding it to the gravitational acceleration to find the new effective force exerted on the engine, hence the bolts.
Mechanical Engineering
Mechanical engineering is an expansive field focused on designing, constructing, and using machines. It involves principles of physics and mathematics to maintain safety and efficiency. In aircraft design, engineers must predict and mitigate forces to ensure the airplane's stability.
  • Rigorous calculations like force and acceleration measurements are integral to maintaining the structural integrity of aircraft parts.
  • Designers consider the entire lifespan of an airplane, which requires understanding how forces like turbulence affect each component.

In this scenario, understanding the force distribution on bolts allows engineers to decide on materials and designs that can endure such forces over time. This exercise displays the meticulous nature of engineering calculations and the necessity for precision in handling potentially extreme conditions.
Aircraft Design
Aircraft design requires balancing a multitude of forces and engineering principles to ensure safety, reliability, and performance efficiency. Designers not only create structures that must perform well under nominal conditions but also under less predictable scenarios, like turbulence.
  • Jets must withstand both static gravitational forces when stationary and dynamic forces when in motion.
  • The bolt system described in this exercise emphasizes redundancy and safety by distributing forces evenly.

Calculating forces experienced by key components, such as engine bolts, enables engineers to anticipate potential failures and design accordingly. Evaluating different load scenarios provides insights into the potential 'weak points' that need reinforcing or redesigning as needed. This thoughtful approach is what ensures aircraft not only take off and fly smoothly but also land safely.

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Most popular questions from this chapter

Compute the initial upward acceleration of a rocket of mass \(1.3 \times 10^{4} \mathrm{~kg}\) if the initial upward force produced by its engine (the thrust) is \(2.6 \times 10^{5} \mathrm{~N}\). Do not neglect the gravitational force on the rocket.

A block with a weight of \(3.0 \mathrm{~N}\) is at rest on a horizontal surface. A \(1.0 \mathrm{~N}\) upward force is applied to the block by means of an attached vertical string. What are the (a) magnitude and (b) direction of the force of the block on the horizontal surface?

A firefighter who weighs \(712 \mathrm{~N}\) slides down a vertical pole with an acceleration of \(3.00 \mathrm{~m} / \mathrm{s}^{2},\) directed downward. What are the (a) magnitude and (b) direction (up or down) of the vertical force on the firefighter from the pole and the (c) magnitude and (d) direction of the vertical force on the pole from the firefighter?

A \(2.0 \mathrm{~kg}\) particle moves along an \(x\) axis, being propelled by a variable force directed along that axis. Its position is given by \(x=3.0 \mathrm{~m}+(4.0 \mathrm{~m} / \mathrm{s}) t+c t^{2}-\left(2.0 \mathrm{~m} / \mathrm{s}^{3}\right) t^{3},\) with \(x\) in meters and \(t\) in seconds. The factor \(c\) is a constant. At \(t=3.0 \mathrm{~s},\) the force on the particle has a magnitude of \(36 \mathrm{~N}\) and is in the negative direction of the axis. What is \(c ?\)

A \(52 \mathrm{~kg}\) circus performer is to slide down a rope that will break if the tension exceeds \(425 \mathrm{~N}\). (a) What happens if the performer hangs stationary on the rope? (b) At what magnitude of acceleration does the performer just avoid breaking the rope?

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