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One of the harmonic frequencies of tube \(A\) with two open ends is \(325 \mathrm{~Hz}\). The next-highest harmonic frequency is \(390 \mathrm{~Hz}\). (a) What harmonic frequency is next highest after the harmonic frequency \(195 \mathrm{~Hz}\) (b) What is the number of this next-highest harmonic? One of the harmonic frequencies of tube \(B\) with only one open end is \(1080 \mathrm{~Hz}\). The next-highest harmonic frequency is \(1320 \mathrm{~Hz}\). (c) What harmonic frequency is next highest after the harmonic frequency \(600 \mathrm{~Hz}\) ? (d) What is the number of this nexthighest harmonic?

Short Answer

Expert verified
(a) 260 Hz (b) 4th harmonic (c) 840 Hz (d) 7th harmonic.

Step by step solution

01

Understanding Harmonic Frequencies

For tube A with two open ends, the harmonic frequencies are determined as integer multiples of the fundamental frequency, \(f_n = n \times f_1\), where \(n\) is the harmonic number.
02

Calculate Fundamental Frequency for Tube A

Given harmonics \(325\, \mathrm{Hz}\) and \(390\, \mathrm{Hz}\), find the difference: \(390 - 325 = 65\, \mathrm{Hz}\). This is the fundamental frequency \(f_1\).
03

Determine Next Highest Harmonic Frequency After 195 Hz for Tube A

First, determine the harmonic number for \(195\, \mathrm{Hz}\): \(195\div65 = 3\). The next harmonic after 3rd is \(f_4 = 4 \times 65 = 260\, \mathrm{Hz}\).
04

Determine Number of Next-Highest Harmonic for Tube A

Since \(f_4 = 260\, \mathrm{Hz}\), the number associated with this is the 4th harmonic.
05

Understanding Harmonics in Tube B

For tube B with one open end, the harmonic frequencies are odd multiples of the fundamental frequency, \(f_n = (2n-1) \times f_{1}\), where \(n\) is the harmonic number.
06

Calculate Fundamental Frequency for Tube B

Given \(f_3 = 1080\, \mathrm{Hz}\) and \(f_4 = 1320\, \mathrm{Hz}\), \(1320-1080 = 240\, \mathrm{Hz}\). So, \(f_1' = 240/2 = 120\, \mathrm{Hz}\).
07

Determine Next Highest Harmonic Frequency After 600 Hz for Tube B

Find harmonic number for 600 Hz: \(600 = (2n-1)\times 120\). Solve to get \(n=3\). The next one is \(n=4\): \( (2(4)-1) \times 120 = 840\, \mathrm{Hz}\).
08

Determine Number of Next-Highest Harmonic for Tube B

The 840 Hz harmonic corresponds to \(n = 4\), which makes it the 7th harmonic (since open tube harmonics are odd-numbered harmonics).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Open-end Tube Harmonics
In the fascinating world of acoustics, understanding how harmonics form in tubes is key. An open-end tube can vibrate at frequencies that are integer multiples of its fundamental frequency. These are called harmonics.

An open-end tube will resonate at multiple frequencies, but these are spread in a predictable pattern. Each harmonic frequency corresponds to a "harmonic number." This is an integer that indicates its order in the harmonic series.

Open-end tube harmonics are relatively straightforward since both ends of the tube must have a displacement node of the wave (a point where no motion occurs). This means that the tube supports a full or half wavelength at different harmonic frequencies. As resonances form at integer multiples, the first harmonic, second harmonic, and so forth are simply increasing frequencies based on the tube's fundamental frequency.

The ability to calculate and predict these harmonics leads to an understanding of musical sound production in instruments like flutes and organ pipes, which rely on open-end tube principles.
Fundamental Frequency
The fundamental frequency is the lowest frequency at which a system can resonate, and in the case of a tube, it forms the basis for all other harmonic frequencies. This fundamental frequency is often represented by the symbol \(f_1\). For a tube open at both ends, the harmonic frequencies are simply integer multiples of this fundamental frequency. For tube A, which is open at both ends, the problem gives harmonic frequencies of 325 Hz and 390 Hz. The step shows that to find the fundamental frequency, you take the difference between these consecutive harmonic frequencies: 65 Hz. This becomes your fundamental frequency, \(f_1\).

This frequency determines how high or low the resultant sound will be. Any harmonic frequency in this system can be found using the formula \(f_n = n \times f_1\), where \(n\) is the harmonic number. Understanding this concept is crucial when dealing with acoustical resonance, as all possible harmonics are derived from this fundamental tone.
Harmonic Number Determination
Determining which harmonic number is associated with a certain frequency is an important skill in analyzing sound waves in tube systems. In an open-end tube, harmonics are integer multiples of the fundamental frequency, with the sequence starting from 1. Usually, the aim is to identify the actual harmonic number, \(n\), corresponding to a particular frequency.

To find the harmonic number for a given frequency \(f\), use the formula \(n = \frac{f}{f_1}\). For Tube A, given that 195 Hz is a frequency mentioned in the problem, calculate as follows: \(195 \div 65 = 3\). Thus, 195 Hz is the 3rd harmonic.

This concept also extends to tube B, which is closed at one end. It only resonates at odd harmonics. For example, the formula for harmonic number determination changes slightly: \(f_n = (2n-1) \times f_1\). If you have a frequency and fundamental frequency, you rearrange this to solve for \(n\).

Understanding how to accurately determine these numbers is useful when analyzing waves in musical instruments and in other fields requiring wave mechanics.

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Most popular questions from this chapter

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