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A pipe \(0.60 \mathrm{~m}\) long and closed at one end is filled with an unknown gas. The third lowest harmonic frequency for the pipe is \(750 \mathrm{~Hz}\). (a) What is the speed of sound in the unknown gas? (b) What is the fundamental frequency for this pipe when it is filled with the unknown gas?

Short Answer

Expert verified
(a) The speed of sound in the unknown gas is 360 m/s. (b) The fundamental frequency is 150 Hz.

Step by step solution

01

Understanding Pipe and Harmonics

A pipe closed at one end supports only odd harmonics. The third lowest harmonic frequency is equivalent to the 5th harmonic of the pipe (because the 1st, 3rd, 5th, ... harmonics are present). The formula for harmonic frequencies is given by \( f_n = n\cdot\frac{v}{4L} \) where \( n \) is odd, \( v \) is the speed of sound in the gas, and \( L \) is the length of the pipe.
02

Identify Given Information

The length of the pipe \( L = 0.60 \) m and the third lowest harmonic frequency \( f_5 = 750 \) Hz. The harmonic number \( n = 5 \). We will find the speed of sound in the gas \( v \) using these values.
03

Calculate the Speed of Sound

Using the harmonic frequency formula, \( 750 \text{ Hz} = 5\cdot\frac{v}{4\times0.60} \). Solve for \( v \):\[ 750 = \frac{5v}{2.4} \750 \times 2.4 = 5v \v = \frac{1800}{5} \v = 360 \text{ m/s}. \]
04

Determine the Fundamental Frequency

The fundamental frequency (first harmonic) for a pipe closed at one end is given by \( f_1 = \frac{v}{4L} \). Substituting \( v = 360 \text{ m/s} \) and \( L = 0.60 \text{ m} \):\[ f_1 = \frac{360}{4 \times 0.60} = \frac{360}{2.4} = 150 \text{ Hz}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonic Frequencies
When we discuss harmonic frequencies, especially in the context of closed pipes, we're referring to the specific set of frequencies that a system, like a musical instrument or even a column of gas in a pipe, can naturally vibrate at. These frequencies are integral multiples of a fundamental frequency.

In a closed pipe, only odd harmonics are possible, which means the vibrations that can occur are at frequencies like the first, third, fifth, and so on. That's because a closed end forces a node and an open end allows an antinode. What does this mean in real terms?
  • The first harmonic (also called the fundamental frequency) is the lowest frequency at which the system can resonate.
  • The third harmonic is not simply the second vibration. Instead, it corresponds to what would be the third possible standing wave pattern for odd harmonics.
  • The fifth harmonic means we're looking at the fifth pattern for these standing waves.
Understanding these patterns helps us find other properties of sound in the system, like the speed of sound itself, which we’ll explore next.
Speed of Sound
The speed of sound is a fundamental characteristic of a medium and tells us how quickly sound waves travel through it. Sound, which is essentially a wave of pressure passing through a medium like gas, water, or solids, moves at different speeds depending on various conditions.

In this problem, the speed of sound helps us determine the qualities of the gas inside the pipe. Given the known harmonic frequency and length of the pipe, you can use the formula:\[ f_n = n\cdot\frac{v}{4L} \]where:
  • \( v \) is the speed of sound in the gas
  • \( n \) is the harmonic number (remember, odd numbers only)
  • \( L \) is the length of the pipe
In this scenario, solving for the speed of sound \( v \) involves rearranging the formula based on the harmonic frequency (\( 750 \) Hz for the fifth harmonic), giving us a speed of sound at \( 360 \text{ m/s} \). This helps clarify how sound travels in this specific gas and exemplifies the relationship between frequency, speed, and medium.
Fundamental Frequency
The fundamental frequency of a system is the lowest frequency at which the system can naturally resonate. For a pipe closed at one end, this foundational frequency sets the stage for further harmonics. It’s crucial as it forms the baseline for all higher harmonics, especially in music and acoustics.

The formula to determine the fundamental frequency for a closed pipe is:\[ f_1 = \frac{v}{4L} \]where \( v \) is the speed of sound in the medium (360 m/s in this case) and \( L \) is the pipe's length (0.60 m here). Solving this gives us \( 150 \text{ Hz} \) for the fundamental frequency.

This fundamental frequency is not only important in acoustics but also in various technology areas, such as designing wind instruments or understanding sound waves in different mediums. Having a solid grasp of how it works can aid in fields from music creation to sound engineering.

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Most popular questions from this chapter

Pipe \(A,\) which is \(1.20 \mathrm{~m}\) long and open at both ends, oscillates at its third lowest harmonic frequency. It is filled with air for which the speed of sound is \(343 \mathrm{~m} / \mathrm{s}\). Pipe \(B,\) which is closed at one end, oscillates at its second lowest harmonic frequency. This frequency of \(B\) happens to match the frequency of \(A .\) An \(x\) axis extends along the interior of \(B,\) with \(x=0\) at the closed end. (a) How many nodes are along that axis? What are the (b) smallest and (c) second smallest value of \(x\) locating those nodes? (d) What is the fundamental frequency of \(B ?\)

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The A string of a violin is a little too tightly stretched. Beats at 4.00 per second are heard when the string is sounded together with a tuning fork that is oscillating accurately at concert A (440 Hz). What is the period of the violin string oscillation?

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You can estimate your distance from a lightning stroke by counting the seconds between the flash you see and the thunder you later hear. By what integer should you divide the number of seconds to get the distance in kilometers?

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