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A golf ball is launched at an angle of \(20^{\circ}\) to the horizontal, with a speed of \(60 \mathrm{~m} / \mathrm{s}\) and a rotation rate of \(90 \mathrm{rad} / \mathrm{s} .\) Neglecting air drag, determine the number of revolutions the ball makes by the time it reaches maximum height.

Short Answer

Expert verified
The golf ball makes approximately 30 revolutions by the time it reaches maximum height.

Step by step solution

01

Determine Time to Maximum Height

First, we need to calculate the time it takes for the golf ball to reach its maximum height. We consider only the vertical motion. The initial vertical component of velocity is given by \(v_{0y} = v_0 \sin(\theta)\), where \(v_0 = 60 \, \text{m/s}\) is the initial speed and \(\theta = 20^\circ\) is the launch angle. We use the equation for the vertical motion: \(v_{y} = v_{0y} - g \cdot t\), where \(v_y = 0\) at the maximum height, and \(g = 9.81 \, \text{m/s}^2\) is the acceleration due to gravity.
02

Solve for Vertical Time

Set \(v_{y} = 0\) to find the time \(t\) to reach maximum height: \(0 = 60 \sin(20^{\circ}) - 9.81 \cdot t\). Solve this equation for \(t\):\[ t = \frac{60 \sin(20^{\circ})}{9.81} \approx 2.09 \, \text{s}. \]
03

Calculate Total Rotations

The rotation rate of the golf ball is given as \(90 \, \text{rad/s}\). To find the number of radians the golf ball rotates through, multiply the rotation rate by the time to maximum height: \(\text{radians} = 90 \, \text{rad/s} \times 2.09 \, \text{s}\).
04

Convert Radians to Revolutions

To find the total number of revolutions, divide the total radians by \(2\pi\) (since one revolution is \(2\pi\) radians):\[ \text{revolutions} = \frac{90 \times 2.09}{2\pi} \approx 29.92. \]
05

Round to Nearest Whole Number

Since the number of revolutions should be a whole number, round 29.92 to 30 revolutions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Motion
In the study of projectile motion, vertical motion is analyzed separately from horizontal motion. For a projectile launched at an angle, the vertical motion is affected by gravity, while the horizontal motion typically isn't, assuming air resistance is negligible.

The initial vertical velocity of a projectile can be calculated using the formula: - \(v_{0y} = v_0 \sin(\theta)\) - Where \(v_0\) is the initial velocity and \(\theta\) is the launch angle.

At the maximum height of a projectile's path, its vertical velocity becomes zero due to gravity's deceleration effect.

The time it takes to reach this maximum height is found using the equation of motion:- \(v_{y} = v_{0y} - g \cdot t\) - Here, \(g\) is the acceleration due to gravity, approximately \(9.81 \, \text{m/s}^2\). At maximum height, you set \(v_y = 0\) and solve for time \(t\) to find how long it takes to reach this peak. This is crucial for any further calculations related to projectile motion.
Rotation Rate
Rotation rate refers to how fast an object spins around a fixed axis. In circular motion, rotation rate is commonly measured in radians per second (rad/s). Radians are a natural unit of angular measure and there are \(2\pi\) radians in a complete circle.

For a golf ball launched with a rotation rate of \(90 \, \mathrm{rad/s}\), this tells us that every second, the ball turns through 90 radians.

The rotation rate comes into play when calculating how the ball spins over time. If we know the time taken to reach maximum height from the vertical motion analysis, the total number of radians rotated can be computed with:- \(\text{total radians} = \text{rotation rate} \times \text{time}\).

It's important to note that while rotation doesn't affect the trajectory in this simplified analysis, it can impact other factors like aerodynamics by altering surface contact with air.
Maximum Height
Maximum height in projectile motion is the highest point in the projectile's flight path. To find it, use the concept of vertical motion where vertical velocity at the peak is zero.

This maximum point is crucial to understand as it gives insights into the time of flight and how long the projectile is airborne before gravity pulls it back.

Calculating the maximum height involves using the initial vertical velocity and gravitational deceleration, from which the required time can be derived:\[ t = \frac{v_{0y}}{g} \]

Knowing the time to reach this height can then be essential to solve other aspects like the number of rotations the object makes in this time frame.
Radians to Revolutions
Understanding radians to revolutions is essential when dealing with rotational motion. One complete revolution is equivalent to \(2\pi\) radians. This conversion is critical when you want to express angular motion in more intuitive terms like revolutions.

For example, if you find that an object rotates by a certain number of radians during a given time, converting this to revolutions helps in visualizing the rotation in complete circles.

To convert radians to revolutions:- Use the formula: \(\text{revolutions} = \frac{\text{total radians}}{2\pi}\)

Rounding the resulting decimal to the nearest whole number gives a practical count, which is often needed in mechanical problems or physics exercises to communicate rotations distinctly.

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