/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 A vinyl record is played by rota... [FREE SOLUTION] | 91Ó°ÊÓ

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A vinyl record is played by rotating the record so that an approximately circular groove in the vinyl slides under a stylus. Bumps in the groove run into the stylus, causing it to oscillate. The equipment converts those oscillations to electrical signals and then to sound. Suppose that a record turns at the rate of \(33 \frac{1}{3}\) rev \(/ \mathrm{min}\), the groove being played is at a radius of \(10.0 \mathrm{~cm},\) and the bumps in the groove are uniformly separated by \(1.75 \mathrm{~mm} .\) At what rate (hits per second) do the bumps hit the stylus?

Short Answer

Expert verified
Bumps hit the stylus at a rate of approximately 199 hits per second.

Step by step solution

01

Convert Units

First, we need to convert the given revolutions per minute (rpm) to revolutions per second (rps) to find how many times the record completes a full circle in one second. Since there are 60 seconds in a minute, we have:\[ \frac{33 \frac{1}{3} \text{ rev}}{1 \text{ min}} = \frac{33.33 \text{ rev}}{60 \text{ s}} = 0.5555 \text{ rps} \]
02

Calculate Linear Velocity

Convert the rotational velocity (in revolutions per second) to linear velocity (in cm/s) at the given radius of 10 cm. The circumference of the circle formed by the radius is the distance traveled in one revolution:\[ \text{Circumference} = 2\pi \times 10 \text{ cm} = 62.83 \text{ cm} \] Thus, the linear velocity is:\[ v = 0.5555 \text{ rps} \times 62.83 \text{ cm/rev} = 34.91 \text{ cm/s} \]
03

Convert Groove Separation Units

The separation between the bumps is given in millimeters. Convert this to centimeters since our velocity is in cm/s:\[ 1.75 \text{ mm} = 0.175 \text{ cm} \]
04

Calculate Hits per Second

Now, we determine the rate at which bumps hit the stylus. This is simply the linear velocity divided by the separation distance:\[ \text{Hits per second} = \frac{34.91 \text{ cm/s}}{0.175 \text{ cm}} = 199.49 \]
05

Round the Answer

Finally, we round the number of hits per second to a reasonable precision. Therefore, the bumps hit the stylus approximately 199 times per second.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Linear Velocity
Linear velocity is an important concept when dealing with objects in circular motion, like a rotating vinyl record. It is the speed at which a point on the edge of the rotating object moves through space. Imagine you're sitting on the outer edge of a spinning record; the speed you move around the circle is your linear velocity.

Calculating linear velocity involves a simple multiplication of the rotational speed and the circumference of the circle formed by the rotation. This is because, for every revolution, the point has to travel the entire circumference of the circle. If you know the rotational speed in revolutions per second (rps), and the circumference is found using the formula \(2\pi r\), where \(r\) is the radius, your linear velocity \(v\) can be determined by:
  • Calculating the circumference: \(2\pi \times 10\, \text{cm} = 62.83\, \text{cm}\)
  • Multiplying by the rotational speed: \(0.5555\, \text{rps} \times 62.83\, \text{cm/rev} = 34.91\, \text{cm/s}\)
Essentially, linear velocity is a bridge between rotational motion and the linear world, helping us understand how fast objects in circular motion actually move through space.
Unit Conversion Essentials
Unit conversion is a fundamental skill in physics, enabling us to solve problems by ensuring consistency in the units we use throughout our calculations. In context, when dealing with measurements like rev/min and mm, attention to unit conversion allows us to express values on a common scale, making calculations accurate and comprehensible.

To convert revolutions per minute (rpm) to revolutions per second (rps), you divide by the number of seconds in a minute:\[ \frac{33\frac{1}{3} \text{ rev}}{1 \text{ min}} = \frac{33.33\, \text{rev}}{60\, \text{s}} = 0.5555\, \text{rps} \]

Similarly, for converting millimeters to centimeters, which is vital when our linear velocity is in cm/s, simply divide by 10 since there are 10 millimeters in a centimeter:\[ 1.75\, \text{mm} = 0.175\, \text{cm} \]
  • These conversions ensure all components in the calculation use the same unit system.
  • This consistency prevents errors and helps in achieving accurate results.
Circular Motion Explained
Circular motion occurs when an object moves along the circumference of a circle. It's a type of motion where an object rotates around a fixed point or axis, just like the stylus moving over the grooves of a vinyl record.

In this rotation, several components come into play:
  • Rotational speed: Indicates how many full rotations are completed in a certain time, usually in revolutions per minute or second.
  • Radius: The distance from the center of the circle to any point on its perimeter. In our problem, this is the radius of the groove being played.
  • Circumference: The total length around the circle, calculated as \(2\pi r\).
For the vinyl record, each groove's bump hitting the stylus forms part of this circular motion. Understanding the dynamics of circular motion is crucial in analyzing how quickly these bumps hit the stylus and ultimately understanding rotational dynamics in real-world applications.

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Most popular questions from this chapter

Four identical particles of mass \(0.50 \mathrm{~kg}\) each are placed at the vertices of a \(2.0 \mathrm{~m} \times 2.0 \mathrm{~m}\) square and held there by four massless rods, which form the sides of the square. What is the rotational inertia of this rigid body about an axis that (a) passes through the midpoints of opposite sides and lies in the plane of the square, (b) passes through the midpoint of one of the sides and is perpendicular to the plane of the square, and (c) lies in the plane of the square and passes through two diagonally opposite particles?

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