/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 A good baseball pitcher can thro... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A good baseball pitcher can throw a baseball toward home plate at \(85 \mathrm{mi} / \mathrm{h}\) with a spin of \(1800 \mathrm{rev} / \mathrm{min} .\) How many revolutions does the baseball make on its way to home plate? For simplicity, assume that the \(60 \mathrm{ft}\) path is a straight line.

Short Answer

Expert verified
9 revolutions

Step by step solution

01

Convert speed from miles per hour to feet per second

The initial speed given is 85 miles per hour (mph). To convert this to feet per second (ft/s), we use the conversion factors \(1 \, ext{mile} = 5280 \, ext{feet}\) and \(1 \, ext{hour} = 3600 \, ext{seconds}\). So,\[85 \, \text{mph} = 85 \times \frac{5280 \text{ ft}}{1 \text{ mile}} \times \frac{1 \text{ hour}}{3600 \text{ seconds}} \85 \, \text{mph} \equiv \frac{85 \times 5280}{3600} \, \text{ft/s} \approx 124.67 \, \text{ft/s}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Motion
Linear motion refers to the movement of an object along a straight path. In physics, it is often described using parameters such as speed, velocity, and displacement. For our baseball example, the linear motion involves the ball traveling from the pitcher to home plate. This path is specified as a straight line over a distance of 60 feet.

The speed of the baseball is a key factor in understanding its linear motion. Speed is the rate at which an object covers distance, and for the baseball, it's initially provided in miles per hour. To find how fast it covers feet per second—a more useful measure for this problem—we convert the units. Understanding linear motion is essential when calculating how objects move through space in real-world scenarios.
  • Displacement: The distance the baseball travels in a straight line (60 feet in this case).
  • Speed: How fast the baseball is moving along its linear path.
  • Velocity: Similar to speed but with a direction (here, the direction is towards home plate).
Mastering linear motion helps us predict how long a journey will take or how much time remains until an object stops, reaches a point, or needs adjustment.
Rotational Motion
Rotational motion involves objects that spin around an axis. In the context of the baseball problem, rotational motion applies to the spin placed on the ball by the pitcher.

The speed of rotation is expressed in revolutions per minute (rpm), a common unit for describing how fast something spins. For the baseball, this is given as 1800 rpm.

Understanding rotational motion is essential as it affects stability and trajectory. For the baseball, knowing how many spins it completes can impact the way it travels through the air.
  • Axis of Rotation: An imaginary line around which the baseball spins.
  • Angular Velocity: How fast the baseball rotates around its axis. The initial measure is 1800 revolutions per minute.
  • Influence on Trajectory: Rotational motion can alter the path of the baseball, causing curves or changes in direction due to aerodynamic forces (like in a curveball).
By understanding these concepts, one can grasp the relationship between how a baseball spins and its behavior in flight.
Unit Conversion
Unit conversion is a fundamental skill in physics and other sciences, essential for ensuring results are in the correct unit of measurement. In the baseball problem, converting units is necessary to align the speed and distance in comparable terms.

Initially, the speed of the baseball is given in miles per hour (mph). To solve the problem, we convert it to feet per second (ft/s) because the distance is in feet. This requires using the conversion factors:
  • 1 mile = 5280 feet
  • 1 hour = 3600 seconds

Using these factors helps to convert egin{equation} 85 ext{ mph} = rac{85 imes 5280}{3600} ext{ ft/s} ightarrow 124.67 ext{ ft/s}. ewline Conversion ensures consistency in units, making calculations easier and results more understandable. Understanding how and when to convert units is crucial for accurate problem-solving and clear communication in science and mathematics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

During the launch from a board, a diver's angular speed about her center of mass changes from zero to \(6.20 \mathrm{rad} / \mathrm{s}\) in \(220 \mathrm{~ms}\). Her rotational inertia about her center of mass is \(12.0 \mathrm{~kg} \cdot \mathrm{m}^{2} .\) During the launch, what are the magnitudes of (a) her average angular acceleration and (b) the average external torque on her from the board?

The masses and coordinates of four particles are as follows: \(50 \mathrm{~g}, x=2.0 \mathrm{~cm}, y=2.0 \mathrm{~cm} ; 25 \mathrm{~g}, x=0, y=4.0 \mathrm{~cm} ; 25 \mathrm{~g}\) \(x=-3.0 \mathrm{~cm}, \quad y=-3.0 \mathrm{~cm} ; 30 \mathrm{~g}, x=-2.0 \mathrm{~cm}, \quad y=4.0 \mathrm{~cm} .\) are the rotational inertias of this collection about the (a) \(x,\) (b) \(y\), and (c) \(z\) axes? (d) Suppose that we symbolize the answers to (a) and (b) as \(A\) and \(B\), respectively. Then what is the answer to (c) in terms of \(A\) and \(B ?\)

An automobile crankshaft transfers energy from the engine to the axle at the rate of \(100 \mathrm{hp}(=74.6 \mathrm{~kW})\) when rotating at a speed of 1800 rev \(/\) min. What torque (in newton-meters) does the crankshaft deliver?

A gyroscope flywheel of radius \(2.83 \mathrm{~cm}\) is accelerated from rest at \(14.2 \mathrm{rad} / \mathrm{s}^{2}\) until its angular speed is \(2760 \mathrm{rev} / \mathrm{min} .\) (a) What is the tangential acceleration of a point on the rim of the flywheel during this spin-up process? (b) What is the radial acceleration of this point when the flywheel is spinning at full speed? (c) Through what distance does a point on the rim move during the spin-up?

At \(t=0,\) a flywheel has an angular velocity of \(4.7 \mathrm{rad} / \mathrm{s}, \mathrm{a}\) constant angular acceleration of \(-0.25 \mathrm{rad} / \mathrm{s}^{2},\) and a reference line at \(\theta_{0}=0 .\) (a) Through what maximum angle \(\theta_{\max }\) will the reference line turn in the positive direction? What are the (b) first and (c) second times the reference line will be at \(\theta=\frac{1}{2} \theta_{\max } ?\) At what (d) negative time and (e) positive time will the reference line be at \(\theta=10.5\) rad? (f) Graph \(\theta\) versus \(t,\) and indicate your answers.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.