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An automobile crankshaft transfers energy from the engine to the axle at the rate of \(100 \mathrm{hp}(=74.6 \mathrm{~kW})\) when rotating at a speed of 1800 rev \(/\) min. What torque (in newton-meters) does the crankshaft deliver?

Short Answer

Expert verified
The torque is approximately 396.87 N·m.

Step by step solution

01

Understand the Given Information

You are provided with the power transferred by the crankshaft, which is given as 74.6 kW. The rotational speed of the crankshaft is 1800 revolutions per minute (rev/min). Your task is to find the torque it delivers, measured in newton-meters.
02

Convert Power to Watts

The power is given as 74.6 kW. To work in standard units, convert this to watts. Since 1 kW equals 1000 watts, you have:\[P = 74.6 \text{ kW} = 74600 \text{ W}\]
03

Convert Rotational Speed to Radians per Second

The rotational speed needs to be in radians per second. First, convert revolutions per minute to revolutions per second by dividing by 60:\[\text{Revolutions per second} = \frac{1800}{60} = 30 \text{ rev/s}\]Since one revolution equals \(2\pi\) radians, the angular speed \(\omega\) in radians per second is:\[\omega = 30 \times 2\pi = 60\pi \text{ rad/s}\]
04

Use the Power-Torque Relationship

The relationship between power, torque, and angular speed is given by the equation:\[P = \tau \cdot \omega\]where \(P\) is the power in watts, \(\tau\) (tau) is the torque in newton-meters, and \(\omega\) is the angular speed in radians per second.
05

Solve for Torque

Rearrange the power-torque relationship to solve for torque:\[\tau = \frac{P}{\omega}\]Substitute the values you have:\[\tau = \frac{74600\, \text{W}}{60\pi\, \text{rad/s}} \approx 396.87 \text{ N·m}\]
06

State the Final Answer

The torque delivered by the crankshaft is approximately 396.87 newton-meters. Ensure to report the answer with appropriate units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Speed Conversion
When dealing with rotational dynamics, it's important to express the rotational speed in a common unit, such as radians per second, which is universally used in physics problems. To convert from revolutions per minute (rev/min) to radians per second (rad/s), follow these steps:
  • First, convert the speed to revolutions per second by dividing the number of revolutions per minute by 60, since there are 60 seconds in a minute.
  • Next, remember that one full revolution is equal to an angle of \(2\pi\) radians. Thus, multiply the number of revolutions per second by \(2\pi\) to convert into radians per second.
In the exercise, the speed is given as 1800 rev/min. Converting this, we get:\[\omega = \frac{1800}{60} \times 2\pi = 60\pi \text{ rad/s}.\]This conversion is crucial for using it in further calculations, especially when determining torque or working with formulas involving angular motion.
Power-Torque Relationship
Understanding how power and torque relate is key in rotational mechanics. The relationship can be expressed with the formula:\[P = \tau \cdot \omega\]where:
  • \(P\) is the power in watts, essentially the rate of energy transfer or work done per unit time.
  • \(\tau\) is the torque in newton-meters, a measure of the force causing the rotation.
  • \(\omega\) is the angular speed in radians per second.
This equation shows us that power is the product of torque and angular speed.
If you know two of these quantities, you can rearrange the equation to solve for the third. For instance, if power and speed are known, rearrange to find torque:\[\tau = \frac{P}{\omega}.\]This relationship is the foundation for solving the exercise, where knowing the power and speed allows us to compute the torque.
Rotational Dynamics
Rotational dynamics deals with the motion of objects that rotate, emphasizing forces and torques. It's the rotational equivalent of linear dynamics, where Newton's laws apply similarly.
The torque, in rotational dynamics, is a force that causes the object to rotate. This is analogous to the linear force in translational motion.
In this context, torque \(\tau\) is determined by factors such as:
  • The force applied, and
  • The distance from the pivot point to where the force is applied, known as the lever arm.
Torque causes angular acceleration, which changes the rotational speed of an object. Just like in linear dynamics, where force equals mass times acceleration, in rotational systems, the equation is:\[\tau = I \alpha\]where \(I\) is the moment of inertia, and \(\alpha\) is the angular acceleration.
Understanding these principles helps analyze problems involving rotating machines, like the crankshaft in the exercise, and allows for better solutions by applying these laws correctly.

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Most popular questions from this chapter

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