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You are standing at a distance D from an isotropic point source of sound. You walk50.0m toward the source and observe that the intensity of the sound has doubled. Calculate the distanceD.

Short Answer

Expert verified

The distance Dis 171″¾.

Step by step solution

01

The given data

The value of the distance is 171″¾.

02

Determine the concept of the intensity

Using the proportionality between the intensity of sound and distance, we can find the distance D.

Formula:

The intensity of the sound wave is inversely proportional to the square of distance or separation, Iα1r2 (i)

03

Calculate the distance

As given above we can say that

The distance betweenandis. Initially, the observer is at point D and then moves towardsthesource by 50.0m to reach at point d. At point d,the intensity of sound gets doubled.

So, we can write, the intensity and distance relation using equation (i) as:

Ir=dIr=D−d=(D−d)2D2=12

Solve by the quadratic formula:

D−dD=12D=d1−12D=170.77D~171″¾

Hence, the value of distance, D is 171″¾.

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(c) The third lowest frequencyfmin3 that gives minimum signal ?

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