91Ó°ÊÓ

We can use the concept of the Doppler Effect. We use the equation of the Doppler Effect to find the frequency heard by the uncle and girl when the air is still. When air is moving, we find the relative speeds of the uncle and the girl with air and using those speeds, we can find the frequencies heard by them.

Formula:

The frequency received by the observer according to Doppler’s Effect,

$\mathit{f}\mathbf{\text{'}}\mathbf{=}\left(\frac{VÂ\pm V_l}{VÂ\pm V_s}\right)\mathit{f}$ …(¾±)

Here the source is moving away from the uncle, so we can write the frequency using equation as:

$\begin{array}{rcl}f\text{'}& =& 500Hz×\left(\frac{343m/s+0}{343m/s+10m/s}\right)\\ & =& 485.6Hz\end{array}$

Hence, the frequency heard by the uncle when air is still is 485.6Hz.

Here the girl is moving withthetrain. Hence, the relative speed ofthegirl with respect tothetrain is zero, so she will hear the same frequency. The girl will hear the frequency:

$\begin{array}{rcl}f\text{'}& =& f\\ & =& 500.0Hz\end{array}$

Hence, the frequency heard by the girl is 500.0Hz

Here, the speed of the train relative to air is V_t = 20m/s and the relative speed of the uncle with air is V_u = 10m/s so we can write the frequency using equation (i) as:

$\begin{array}{rcl}f\text{'}& =& 500Hz×\left(\frac{343m/s+10m/s}{343m/s+20m/s}\right)\\ & =& 486Hz\end{array}$

Hence, the frequency heard by the uncle is 486Hz

Here the girl is moving with the train, so the relative speed of girl with respect to air is V_g = 20m/s, and the speed of the train with air is also V_t = 20m/s Hence there is no relative motion between the girl andthe train, so the girl will hear the frequency:

$\begin{array}{rcl}f\text{'}& =& f\\ & =& 500.0Hz\end{array}$

Hence, the frequency heard by the girl is 500.0Hz.