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A sound wave travels out uniformly in all directions from a point source. (a) Justify the following expression for the displacement of the transmitting medium at any distance r from the source S(r,t)=brsink(r−vt): where b is a constant. Consider the speed, direction of propagation,periodicity, and intensity of the wave. (b) What is the dimensionof the constant ?

Short Answer

Expert verified

a. The expression for the displacement of the transmitting medium at any distance from the source is:S(r,t)=brsink(r−vt)

b. The dimension of the constant is length squared.

Step by step solution

01

The given data

The sound waves travel uniformly in all directions from the point source

02

Understanding the concept of the intensity

Use the concept of variation of intensity with distance. The intensity of the sound from an isotropic point source decreases with the square of the distance from the source. The intensity is proportional to the square of the amplitude.

Formulae:

Formula for the intensity in terms of power and area or in terms of displacement square, I=Ps4Ï€r2orI=CSm2 (i)

03

Calculate justifying the expression

The intensity at a distance from a point source that emits sound waves of power Psequally in all directionsusing equation (i) is given as:

I=Ps4πr2………………………………(1)

The intensity is proportional to the square of displacement amplitudeSm. Hence,

I=CSm2………………………………(2)

Where C is the proportionality constant

Comparing both theequation (1) and equation (2), we get

CSm2=Ps4Ï€r2Sm=Ps4Ï€r2C=Ps4Ï€C(1r)...............................(a)

The displacement amplitude is inversely proportional to the distance from the source.

The sound wave travels uniformly in all directions from the source. These waves are sinusoidal of radius of the sphere in the phase. The angular frequency and angular wave number of the wave are and respectively, then the term is sin(kr−Ӭt).Let

b=Ps4Ï€C..........................(b)

Thus, the displacement of the wave using equations (a) and (b)is given by:

S(r,t)=Ps4πC(1r)sin(kr−Ӭt)=brsin(kr−Ӭt)

The expression for wave number is

k=2πλ

S(r,t)=brsink(krk−Ӭkt)=brsink(r−vt)

Since, Ó¬k=v

Hence it is proved.

04

b) Calculate the dimensions of constant b

The displacements of the waveand the distance from the sourceboth have dimensions of length. The trigonometric function is dimensionless. Hence, the dimensions ofis length squared. From equation (a) and equation (b), the dimension of the constant is given as:

b=S(r,t)r[b]=[L2]

Hence, the dimension of the constant b is length squared.

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