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A golfer takes three putts to get the ball into the hole. The first putt displaces the ball 3.66mnorth, the second 1.83msoutheast, and the third 0.91m southwest. What are (a) the magnitude and (b) the direction of the displacement needed to get the ball into the hole on the first putt?

Short Answer

Expert verified
  1. The magnitude of the displacement needed to get the ball into the hole on the first putt is 1.84 m.

  2. The direction of the displacement needed to get the ball into the hole on the first putt is69.3northofeast .

Step by step solution

01

Given data

Displacement in the first putt,a=3.66mnorth

Displacement in the second putt,b=1.83msoutheast

Displacement in the third putt,c=0.91msouthwest

02

Understanding the addition of vectors

The vectors can be added geometrically by placing them head to tail. The vector that connects the tail of first to head of the last vector is the vector sum.

The displacement vector Rcan be written as,

R=a+b+c 鈥 (i)

03

(a) Determination of the magnitude of the displacement

Consider the directions as East is along x axis and North is along y axis. Thus the given vectors a, band ccan be drawn as:

The given vectors can be written in terms of their components as,

a=3.66j^

b=1.83cos(-45)i^+1.83sin(-45)j^

c=0.91cos(-135)i^+0.9sin(-135)j^

Using equation (i), the resultant vector can be obtained as,

r=a+b+c

=0.64i^+1.72j^

The magnitude of the resultant vector is,

|r|=0.652+1.722=1.84m

Thus, the magnitude of the displacement needed to get the ball into the hole on the first putt is 1.84 m.

04

Step 4 (b) Determination of the direction of the displacement vector

The direction of the displacement vector is calculated as:

=tan-1(1.720.65)=69.3

Thus the direction of the displacement needed to get the ball into the hole on the first putt is 63northofeast.

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