91影视

Strike-slip $AC=22.0m$and dip-slip$AD=17.0\mathrm{m}$

The inclination angle of the fault plane to the horizontal is$蠒=52掳$

The vector addition theorem can be used to find the net displacement and its vertical component can be found by using trigonometry and the information given in the figure.

Formula:

$\stackrel{鈫�}{AD}=\stackrel{鈫�}{AD}+\stackrel{鈫�}{AD}鈥�鈥�鈥�\left(\mathrm{i}\right)$

$s\mathrm{in}蠒=\frac{\mathrm{opposite}\mathrm{side}}{\mathrm{hypotenuse}}鈥�鈥�鈥�.\left(\mathrm{ii}\right)$

$\stackrel{鈫�}{AB}$and$\stackrel{鈫�}{AD}$ are the horizontal and vertical component of$\stackrel{鈫�}{AB}$

According to the triangle vector addition law,

$\stackrel{鈫�}{AB}=\stackrel{鈫�}{AC}+\stackrel{鈫�}{AD}$

$$\begin{gathered} A{B}^2=A{C}^2+A{D}^2 \\ AB=\sqrt{A{C}^2+A{D}^2} \\ =\sqrt{{22}^3+{17}^2} \\ =27.8\mathrm{m} \end{gathered}$$

Hence, the magnitude of net displacement is 27.8 m

Now the fault is inclined at an angle$蠒$ to the horizontal, hence, the vertical component of$\stackrel{鈫�}{AB}$ is the opposite side of that angle$蠒$

The vertical component of $\stackrel{鈫�}{AB}$,

$$\begin{gathered} A{B}_v=AD\sin 蠒 \\ =17\sin 52 \\ =13.4\mathrm{m} \end{gathered}$$

Therefore, the vertical component of$\stackrel{鈫�}{AB}=13.4\mathrm{m}$ .