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Question: From the knowledge that Cv , the molar specific heat at constant volume, for a gas in a container is 5.0 R , calculate the ratio of the speed of sound in that gas to the rms speed of the molecules, for gas temperature T. (Hint: See Problem 91.)

Short Answer

Expert verified

Answer

The ratio of the speed of sound in the gas to the rms speed of the molecules of the gas, for the given temperature, T is 0.63.

Step by step solution

01

Step 1: Given

  1. The molar-specific heat of the gas, when the volume is kept constant, is CV=5.0R.
  2. Hint: See Problem 19-91.
02

Determining the concept

By using the equation for the speed of sound in gas from problems 19-91 and using Equations 19-34 and 19-49, find the ratio of speed of sound in the gas to the rms speed of the molecules, for a given temperature .

Formulae are as follow:

  1. The speed of sound in the gas is,

vs=RTM

  1. Therms speed of the molecules is,

vrms=3RTM

  1. The molar specific heat at constant pressure is,

Cp=CV+R

where,=Cp/CV, Ris the gas constant, Tis the temperature, vis velocity and M is the molar mass.

03

Determining the ratio of speed of sound in the gas to the rms speed of the molecules, for the given temperature  T

From problem 19-91, the speed of sound in the gas is,

vs=RTM.1

Where, =Cp/CV, R is the gas constant, T is the temperature, and M is the molar mass.

From Equation 19-34, therms speed of the molecules is given by,

vrms=3RTM19-34

From Eq. (1) and (19-34), the ratio of speed of sound in the gas to the rms speed of the molecules, for gas temperature T is,

vsvrms=RTM3RTMvsvrms=32

But,=Cp/CV ,

Putting in Eq. (2),

vsvrms=Cp/CV3vsvrms=Cp3CV.3

But, from Eq. (19-49),

Cp=CV+R.19-49

Putting in Eq. (3),

vsvrms=CV+R3CV=5.0R+R35.0R=6.015=0.63

Hence, the ratio of speed of sound in the gas to the rms speed of the molecules, for the given temperature T is, 0.63 .

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Most popular questions from this chapter

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