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Question: The temperature and pressure in the Sun’s atmosphere are 2.00×106Kand 0.0300 paCalculate the rms speed of free electrons (mass 9.11×10-31kg) there, assuming they are an ideal gas.

Short Answer

Expert verified

Answer

The rms speed of free electrons is9.53×106ms .

Step by step solution

01

Given

T=2.00×106K,p=0.0300Pa,m=9.11×10-31kg

02

Determine the concept

Find the RMS speed using the formula for root-mean-square speed. MS speed is defined as the square root of the mean of the square of speeds of all molecules.

Formula is as follow:

v=3RTM

Here, M is mass, Tis temperature, v is velocity and R is universal gas constant.

03

Determine the rms speed of free electrons 

The rms speed of electrons is,

v=3RTMM=mNAandR=kNAv=3kNATmNA∴v=3kTm

Substitute the values and solve as:

∴v=31.38×10-232.00×1069.11×10-31v=9.533×106v=9.53×106ms

Hence, the rms speed of free electrons is v=9.53×106ms.

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Most popular questions from this chapter

A hydrogen molecule (diameter 1.0×10-8cm), travelling at the rms speed, escapes from a 4000 K furnace into a chamber containing coldargon atoms (diameter) at a density of.

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Mean free path=1πd2 N/V

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