/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q83P The temperature of a Pyrex disk ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The temperature of a Pyrex disk is changed from10.0°°ä³Ù´Ç60.0°°ä. Its initial radius is8.00cm; its initial thickness is0.500cm. Take these data as being exact.What is the change in the volume of the disk?

Short Answer

Expert verified

The change in volume of disk is 4.83×10−8m3.

Step by step solution

01

Identification of given data

i) Initial radius isR=8.00cmor0.08m

ii) Initial thickness ist=0.500cmor0.005m

iii) Initial temperature isT1=10.0°C

iv) Final temperature isT2=60.0°C .

02

Understanding the concept of thermal and volume expansion

When an object is heated or cooled, its length changes by an amount proportional to the original length and the temperature change.This process is called the linear expansion of the given substance. But when the expansion takes place along all the three dimensions of the substance, then the expansion is referred to as volume expansion. The coefficient of volume expansion is related to the linear coefficient.

Formulae:

Area of the disk,A=Ï€R2 …(¾±)

whereR is the radius of the disk.

Volume of a body,V=A×t…(¾±¾±)

whereA is the area of the disk andt is the thickness of the disk.

Coefficient of volume expansion due to thermal radiationβ=ΔVV×ΔT,…(¾±¾±¾±)

where V is initial volume,ΔTis change in temperature andΔVis change in volume.

03

Determining the change in volume of disk

Using equation (i) and the value of inner radius, the area of the disk is found to be

A=π×0.082m2=0.02010m2

Now, using this value of area and formula of equation (ii), we can get the volume of the body as

V=0.02010m2×0.005m=1.0053×10−4m3

Now coefficient of volume expansion can be found using the value of the coefficient of linear expansion as

β=3×α=3×3.2×10−6/°°ä=9.6×10−6/°C

Now, using equation (iii) and the given values, we get the change in volume as

9.6×10−6/0C=ΔV1.0053×10−4m3×(600C−100C)ΔV=(9.6×10−6×1.0053×10−4×50)m3=482.544×10−10m3=4.83×10−8m3

Hence, the volume change is.4.83×10−8m3

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Evaporative cooling of beverages. A cold beverage can be kept cold even on a warm day if it is slipped into a porous ceramic container that has been soaked in water. Assume that energy lost to evaporation matches the net energy gained via the radiation exchange through the top and side surfaces. The container and beverage have temperature T=15°°ä, the environment has temperature Tenv=32°°ä , and the container is a cylinder with radius r=2.2cm and height 10cm . Approximate the emissivity asε=1, and neglect other energy exchanges. At what rate is the container losing water mass?

The initial length L, change in temperature â–³T, and change in length â–³Lof four rods are given in the following table. Rank the rods according to their coefficients of thermal expansion, greatest first.

Rod L (m) △T(C°) △L(m)
abcd 2124 1020105 4×10-44×10-48×10-44×10-4

When the temperature of a metal cylinder is raised from0.0oCto100oC, its length increases by 0.23%

(a) Find the percent change in density.

(b) What is the metal? Use Table.

In a certain solar house, energy from the Sun is stored in barrels filled with water. In a particular winter stretch of five cloudy days,1.00×106kcalis needed to maintain the inside of the house at22.0° C. Assuming that the water in the barrels is at50.0º°äand that the water has a density of1.00×103kgm3, what volume of water is required?

Find the change in volume of an aluminum sphere with an initial radius of 10 cmwhen the sphere is heated from0.0oCto100.0oC.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.