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At 20C, a rod is exactly20.05鈥塩尘long on a steel ruler. Both the rod and the ruler are placed in an oven at270C, where the rod now measures20.11鈥塩尘on the same ruler. What is the coefficient of linear expansion for the material of which the rod is made?

Short Answer

Expert verified

Coefficient of linear expansion for the given material is23106/鈥塁

Step by step solution

01

The given data

  1. Initial temperature before expansion,T1=20C
  2. Final temperature after expansion,T2=270C
  3. The linear coefficient of expansion,=11106/鈥塁
  4. Initial length before the expansion,L1=20.05鈥塩尘
  5. Final length after the expansion,L2=20.11鈥塩尘
02

Understanding the concept of thermal expansion

When an object's temperature changes, it expands and grows larger, a process known as thermal expansion. If the temperature of a metal rod of length L is raised by an amountT, its length is found to be increased by the amountL=LTwhere,is the coefficient of linear expansion of the material.

Formula:

The linear expansion of a body, 螖尝=尝伪螖罢 鈥(颈)

where, is the coefficient of linear expansion of body.

03

Calculation of coefficient of linear expansion

The change in length for the section of the steel ruler between its20.05cmmark and20.11cm mark is given using equation (i) as:

螖尝=(20.11鈥塩尘)(11106/鈥塁)(270C20C)=0.0551鈥塩尘

Thus, the actual change in length for the rod is given as:

L=(20.1120.05)cm+0.055鈥塩尘=0.115鈥塩尘

The coefficient of thermal expansion for the material of which the rod is made using equation (i) is given as:

=螖尝L螖罢=0.115鈥塩尘20.05鈥塩尘(27020)鈥塁=23106/鈥塁

Hence, the value of the coefficient of linear expansion is23106/鈥塁

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