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At 20°C, a rod is exactly20.05 c³¾long on a steel ruler. Both the rod and the ruler are placed in an oven at270°C, where the rod now measures20.11 c³¾on the same ruler. What is the coefficient of linear expansion for the material of which the rod is made?

Short Answer

Expert verified

Coefficient of linear expansion for the given material is23×10−6/° C

Step by step solution

01

The given data

  1. Initial temperature before expansion,T1=20°C
  2. Final temperature after expansion,T2=270°C
  3. The linear coefficient of expansion,α=11×10−6/° C
  4. Initial length before the expansion,L1=20.05 c³¾
  5. Final length after the expansion,L2=20.11 c³¾
02

Understanding the concept of thermal expansion

When an object's temperature changes, it expands and grows larger, a process known as thermal expansion. If the temperature of a metal rod of length L is raised by an amountΔT, its length is found to be increased by the amountΔL=LαΔTwhere,αis the coefficient of linear expansion of the material.

Formula:

The linear expansion of a body, Δ³¢=³¢Î±Î”°Õ …(¾±)

where, αis the coefficient of linear expansion of body.

03

Calculation of coefficient of linear expansion

The change in length for the section of the steel ruler between its20.05cmmark and20.11cm mark is given using equation (i) as:

Δ³¢=(20.11 c³¾)(11×10−6 /° C)(270°C−20°C)=0.0551 c³¾

Thus, the actual change in length for the rod is given as:

ΔL=(20.11−20.05)cm+0.055 c³¾=0.115 c³¾

The coefficient of thermal expansion for the material of which the rod is made using equation (i) is given as:

α=Δ³¢L⋅Δ°Õ=0.115 c³¾20.05 c³¾â‹…(270−20)° C=23×10−6/° C

Hence, the value of the coefficient of linear expansion is23×10−6/° C

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