91Ó°ÊÓ

Radius of wheel is,$\mathrm{R}=30\text{cm}=0.30\text{m}.$

Angular velocity of wheel is,$\mathrm{Ó\neg }=2.5\text{ }\frac{\text{rev}}{\text{s}}$

Length of an arrow is,$\mathrm{L}=20\text{cm}=0.20\text{ }\text{m}.$

Find the time in which the arrow should be passed through the wheel using its relation with the number of revolutions and angular velocity of the wheel. Using time, find the minimum speed of the arrow.

Formula:

$\begin{array}{l}\mathrm{t}=\frac{\text{No}.\text{ofrevolutions}}{\mathrm{Ó\neg }}\\ \mathrm{v}=\frac{\mathrm{x}}{\mathrm{t}}\end{array}$

As the arrow is shot, it should go through the space between the spokes. If it is aimed at one of the spokes, it should be aimed in such way that it will pass through the wheel in time equal to

$\mathrm{t}=\frac{\mathrm{No}.\mathrm{of}\mathrm{revolutions}}{\mathrm{Ó\neg }}$

Since the wheel has 8 spokes substitute the values and solve as:

$\begin{array}{c}\mathrm{t}=\frac{\frac{1}{8}\text{ r±ð±¹}}{2.5\text{ }\frac{\text{rev}}{\text{s}}}\\ =0.05\text{ s}\end{array}$

Minimum speed of the arrow is obtained as follows:

$\begin{array}{c}{\mathrm{v}}_{\min }=\frac{\mathrm{L}}{\mathrm{t}}\\ =\frac{0.20}{0.05}\\ =4.0\text{ }\frac{\text{m}}{\text{s}}\end{array}$

Therefore, minimum speed of the arrow is $4.0\text{ }\frac{\text{m}}{\text{s}}$.

Since minimum speed of the arrow is independent of the position of the arrow, it doesn’t matter where between the axle and rim of the wheel the arrow is aimed.