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Reference frame S鈥 is to pass reference frame S at speed v along the common direction of the and x axes, as in Fig. 37-9. An observer who rides along with frame S鈥 is to count off a certain time interval on his wristwatch. The corresponding time interval t is to be measured by an observer in frame S. Figure 37-22 gives tversus speed parameter for a range of values for . The vertical axis scale is set by ta 14.0 s. What is interval t if v = 0.98c?

Short Answer

Expert verified

The time interval for observer is 40s.

Step by step solution

01

Identification of given data

The speed of reference frame S鈥 is v=0.98c

The duration for the reference frame S鈥 is t=8s

The time dilation is used to find the duration for particle before decay from detector.

02

Determination of time interval for observer

The time interval for observer is given as:

t=t1-vc2

Here, cis the speed of light and its value is 3108m/s.

Substitute all the values in equation.

t=8s1-0.98cc2t=40s

Therefore, the time interval for observer is 40 s .

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Most popular questions from this chapter

Question:The mass of a muon is 207 times the electron mass; the average lifetime of muons at rest is 2.20s. In a certain experiment, muons moving through a laboratory are measured to have an average lifetime of 6.90s. For the moving muons, what are (a) , (b) K, and (c) p (in MeV/c)?

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The car-in-the-garage problem. Carman has just purchased the world鈥檚 longest stretch limo, which has a proper length of Lc=30.5鈥尘. In Fig. 37-32a, it is shown parked in front of a garage with a proper length of Lg=6.00鈥尘. The garage has a front door (shown open) and a back door (shown closed).The limo is obviously longer than the garage. Still, Garageman, who owns the garage and knows something about relativistic length contraction, makes a bet with Carman that the limo can fit in the garage with both doors closed. Carman, who dropped his physics course before reaching special relativity, says such a thing, even in principle, is impossible.

To analyze Garageman鈥檚 scheme, an xc axis is attached to the limo, with xc=0 at the rear bumper, and an xg axis is attached to the garage, with xg=0 at the (now open) front door. Then Carman is to drive the limo directly toward the front door at a velocity of 0.9980c(which is, of course, both technically and financially impossible). Carman is stationary in the xcreference frame; Garageman is stationary in the role="math" localid="1663064422721" Xgreference frame.

There are two events to consider. Event 1: When the rear bumper clears the front door, the front door is closed. Let the time of this event be zero to both Carman and Garageman: tg1=tc1=0. The event occurs at xg=xc=0. Figure 37-32b shows event 1 according to the xg reference frame. Event 2: When the front bumper reaches the back door, that door opens. Figure 37-32c shows event 2 according to the xg reference frame.

According to Garageman, (a) what is the length of the limo, and what are the spacetime coordinates (b) xg2 and (c) tg2 of event 2? (d) For how long is the limo temporarily 鈥渢rapped鈥 inside the garage with both doors shut? Now consider the situation from the xc reference frame, in which the garage comes racing past the limo at a velocity of 0.9980c. According to Carman, (e) what is the length of the passing garage, what are the spacetime coordinates (f) Xc2and (g) tc2 of event 2, (h) is the limo ever in the garage with both doors shut, and (i) which event occurs first? (j) Sketch events 1 and 2 as seen by Carman. (k) Are the events causally related; that is, does one of them cause the other? (l) Finally, who wins the bet?

In fig. 37-9, the origins of the two frames coincide at t=t'=0 and the relative speed is 0.950c. Two micrometeorites collide at coordinates x=100km and t=200s according to an observer in frame S. What are the (a) spatial and (b) temporal coordinate of the collision according to an observer in frame S' ?

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