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91Ó°ÊÓ

Consider thedecay Âì0→p+π−withtheÂì0 at rest. (a) Calculate the disintegration energy. What is the kinetic energy of (b) the proton and (c) the pion?

Short Answer

Expert verified

(a) The disintegration energy is.37.7 M±ð±¹

(b) The kinetic energy of proton is.5.35 M±ð±¹

(c) The kinetic energy of pion is.32.4 M±ð±¹

Step by step solution

01

(a) Evaluate disintegration energy.

The given reaction is written as:

Âì0→p+π−

Solve the disintegration energy as follows:

Q=Δmc2=(mÂì0-mp-mÏ€-)c2

Substitute the values from the standard data.

Q=(1115.6-938.3-139.6) Mev=37.7 Mev

Thus, the disintegration energy is.37.7 Mev

02

(b) Evaluate the kinetic energy of proton. 

Solve the kinetic energy of proton in the given reaction as follows;

Kp=(EÂì-Ep)2-EÏ€22EÂì

Substitute the values from the standard data

Kp=(1115.6-938.3)2-(139.6)22(1115.6) M±ð±¹=5.35 M±ð±¹

Thus, the kinetic energy of proton is .5.35 Mev

03

(c) Evaluate the kinetic energy of pion.

Solve the kinetic energy of proton in the given reaction as follows;

KÏ€=Q-Kp=(37.7-5.35) M±ð±¹=32.4​ M±ð±¹

Thus, the kinetic energy of pion is.32.4 Mev

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Most popular questions from this chapter

Suppose that the matter (stars, gas, dust) of a particular galaxy, of total mass M, is distributed uniformly throughout a sphere of radius.A star of mass Ris revolving about the center of the galaxy in a circular orbit of radius.r<R

(a) Show that the orbital speedv of the star is given by

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And therefore that the star’s period Tof revolution is

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(b) Next suppose that the galaxy’s mass is concentrated near the galactic center, within a sphere of radius less than . What expression then gives the star’s orbital period?

  1. Question: By examining strangeness, determine which of the following decays or reactions proceed via the strong interaction: (a) K0→π++Ï€- (b) Âì0+p→Σ++n(c) Âì0→p+Ï€-(d)K-+p→Âì0+Ï€0.

Which conservation law is violated in each of these proposed reactions and decays? (Assume that the products have zero orbital angular momentum.)

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