Q18P Question: By examining strangene... [FREE SOLUTION]

91影视

Chapter 44: Q18P (page 1364)

Question: By examining strangeness, determine which of the following decays or reactions proceed via the strong interaction: (a) $K^{0} 鈫� 蟺^{+} + 蟺^{-}$ (b) $蚂^{0} + p 鈫� 危^{+} + n$ (c) $蚂^{0} 鈫� p + 蟺^{-}$ (d) $K^{-} + p 鈫� 蚂^{0} + 蟺^{0}$ .

Short Answer

Expert verified

Strangeness is not conversed.
Strangeness is not conversed.
Strangeness is not conversed.
Strangeness is conversed.

Step by step solution

(a) Strangeness of K0→π++π-.

The strangeness of $K^{0}$ is $+ 1$ and the strangeness of $蟺^{+}$ is 0 and strangeness of $蟺^{-}$ is $0$ .

Thus, strangeness is not conversed.

Hence, it does not proceed via strong interaction.

(b) Strangeness of Λ0+p→∑++n.

The strangeness of $蚂^{0}$ is $- 1$ and $p$ is $0$ and the strangeness $\overset{+}{鈭�}$ of is $1$ and strangeness of $n$ is $0$ .

Thus, strangeness is not conversed.

Hence, it does not proceed via strong interaction.

(c) Strangeness of Λ0→p+π- .

The strangeness of $蚂^{0}$ is $- 1$ and the strangeness of $p$ is $0$ and $蟺^{-}$ is $0$ .

Thus, strangeness is not conversed.

Hence, it does not proceed via strong interaction.

(d) Strangeness of K-+p→Λ0+π0 ..

The strangeness of $K^{-}$ is $- 1$ and $p$ is $0$ and the strangeness of $蚂^{0}$ is $- 1$ and $蟺^{0}$ is $0$ .

Thus, strangeness is conversed.

Hence, it proceed via strong interaction.

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Particle	Charge	Whimsy	Seriousness	Cuteness
A	1	1	-2	-2
B	0	4	3	0
C	1	2	-3	-1
D	-1	-1	0	1
E	-1	0	-4	-2
F	1	0	0	0
G	-1	-1	1	-1
H	3	3	1	0
I	0	6	4	6
J	1	-6	-4	-6

91影视

Question: By examining strangeness, determine which of the following decays or reactions proceed via the strong interaction: (a) $K^{0} 鈫� 蟺^{+} + 蟺^{-}$ (b) $蚂^{0} + p 鈫� 危^{+} + n$ (c) $蚂^{0} 鈫� p + 蟺^{-}$ (d) $K^{-} + p 鈫� 蚂^{0} + 蟺^{0}$ .

Short Answer

Step by step solution

(a) Strangeness of K0→π++π-.

(b) Strangeness of Λ0+p→∑++n.

(c) Strangeness of Λ0→p+π- .

(d) Strangeness of K-+p→Λ0+π0 ..

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Electrostatics

Classical Mechanics

Particle Model of Matter

Nuclear Physics

Electricity

Waves Physics

Study anywhere. Anytime. Across all devices.

91影视

Question: By examining strangeness, determine which of the following decays or reactions proceed via the strong interaction: (a) K0鈫�蟺++蟺- (b) 蚂0+p鈫�危++n(c) 蚂0鈫�p+蟺-(d)K-+p鈫�蚂0+蟺0.

Short Answer

Step by step solution

(a) Strangeness of K0→π++π-.

(b) Strangeness of Λ0+p→∑++n.

(c) Strangeness of Λ0→p+π- .

(d) Strangeness of K-+p→Λ0+π0 ..

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Electrostatics

Classical Mechanics

Particle Model of Matter

Nuclear Physics

Electricity

Waves Physics

Study anywhere. Anytime. Across all devices.

Question: By examining strangeness, determine which of the following decays or reactions proceed via the strong interaction: (a) $K^{0} 鈫� 蟺^{+} + 蟺^{-}$ (b) $蚂^{0} + p 鈫� 危^{+} + n$ (c) $蚂^{0} 鈫� p + 蟺^{-}$ (d) $K^{-} + p 鈫� 蚂^{0} + 蟺^{0}$ .