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Because of the cosmological expansion, a particular emission from a distant galaxy has a wavelength that is 2 times the wavelength that emission would have in a laboratory. Assuming that Hubble鈥檚 law holds and that we can apply Doppler-shift calculations, what was the distance (ly)to that galaxy when the light was emitted?

Short Answer

Expert verified

The distance to the galaxy when the light was emitted was.2.751010鈥塴测

Step by step solution

01

Given data

Detected wavelength is twice that of emitted wavelength.

02

Step 2:Hubble's law and astrophysical doppler shift

According to Hubble's law, galaxies at a distancer from Earth is moving away from Earth at a velocity as:

v=Hr ..... (I)

Here,His the Hubble's constant with value

H=21.8mm/sly

According to astrophysical Doppler shift, the change in wavelength of an emission of wavelength if the source is moving away with a velocity v is

螖位=惫位c ..... (II)

Here,cis the speed of light in vacuum with value

c=3108ms

03

Step 3:Determinethe distance of the source galaxy

From equations (I) and (II)

Hr=cr=cH

The detected wavelength is twice the emitted wavelength, that is .=2 Substitute the values in the above equation to get

r=3108ms221.8mmsly=2.75107(1鈥塴测)(1鈥尘1000鈥尘m1鈥尘)(11鈥尘m)=2.751010鈥塴测

Thus, the distance is.2.751010鈥塴测

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