/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q27P Tarzan, who weighs 688 N , swing... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Tarzan, who weighs 688 N , swings from a cliff at the end of a vine 18 m long (Figure). From the top of the cliff to the bottom of the swing, he descends by 3.2 m . The vine will break if the force on it exceeds 950 N . (a) Does the vine break? (b) If no, what is the greatest force on it during the swing? If yes, at what angle with the vertical does it break?

Short Answer

Expert verified
  1. No,thevine does not break.
  2. The greatest force acting on the vine is T=933N

Step by step solution

01

Given          

  1. The weight of Tarzon is,W=68s
  2. The length of the vine is,l=18m
  3. The vertical distance covered from the top of the cliff to the bottom of the swing is,h=3.2m
  4. The maximum limit of the force in the vine is,T=950N
02

Determining the concept

Use the concept of energy conservation law and find the velocity at the lowest point. At the cliff, there is potential energy, and it is converted to kinetic energy during the swing. Use Newton’s second law and find the greatest tension in the vine. According to the law of energy conservation, energy can neither be created, nor be destroyed.

Formulae:

W=mgU=mghK=12mv2

where, K is kinetic energy, Uis potential energy, m is mass, v is velocity, g is an acceleration due to gravity, his height and W is work done.

03

(a) Determining if thevine break

The weight of Tarzan is,

W=mg

According to the energy conservation law, the potential energy is converted to the kinetic energy duringtheswing, and finally, the velocity at the lowest point,

mgh=12mv2gh=12v2v2=2gh

Examine the tension in the string at the lowest point. If it isn’t breaking, then it has greatest tension.

The free body diagram is shown at the lowest point. The centripetal force and tension are acting in upward direction and weight in downward direction. Use the sign convention according to the motion of the body. According to Newton’s second law,

T-mg=mv2r

Here,

r=l=18mT=mv2l+mgT=mv2l+gT=m2ghl+gT=mg2hl+1T=688N2×3.2m18m+1T=933N

Therefore, no, the vine does not break. The maximum limit of the force in the vine is T=950N but here the maximum tension in the vine at the lowest pointis T=933N. It is less than the maximum limit.

04

(b) Determining thegreatest force acting on it during the swing if vine don’t break and the angle with the vertical if it breaks

The maximum force in the vine at the lowest point is,

T=933N

Hence,the greatest force acting on the vine is,T=933N

Therefore, the maximum tension in the vine at the lowest point can be found by using Newton’s second law and energy conservation law.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A conservative force F(x)acts on a 2.0 kgparticle that moves along an x axis. The potential energy U(x)associated with F(x)is graphed in Fig. 8-63. When the particle is at x=2.0m, its velocity is -1.5ms. What are the (a) magnitude and (b) direction of F(x)at this position? Between what positions on the (c) left and (d) right does the particle move? (e) What is the particle’s speed at x=7.0 m?

(a) In Problem 4, what initial speed must be given the ball so that it reaches the vertically upward position with zero speed? What then is its speed at

(b) The lowest point and

(c)The point on the right at which the ball is level with the initial point?

(d) If the ball’s mass were doubled, would the answers to (a) through (c) increase, decrease, or remain the same?

A boy is initially seated on the top of a hemispherical ice mound of radius R = 13.8 m. He begins to slide down the ice, with a negligible initial speed (Figure). Approximate the ice as being frictionless. At what height does the boy lose contact with the ice?

The cable of the 1800 kgelevator cabin Figure snaps when the cab is at rest at the first floor, where the cab bottom is a distance d = 3.7 m above a spring of spring constant k = 0.15 MN/m . A safety device clamps the cab against guide rails so that a constant frictional force of 4.4 kNopposes the cab’s motion. (a) Find the speed of the cab just before it hits the spring. (b) Find the maximum distance xthat the spring is compressed (the frictional force still acts during this compression). (c) Find the distance that the cab will bounce back up the shaft. (d) Using conservation of energy, find the approximate total distance that the cab will move before coming to rest. (Assume that the frictional force on the cab is negligible when the cab is stationary.)

During a rockslide, a 520 kgrock slides from rest down a hillside that islong and 300 mhigh. The coefficient of kinetic friction between the rock and the hill surface is 0.25. (a) If the gravitational potential energy Uof the rock–Earth system is zero at the bottom of the hill, what is the value of U just before the slide? (b) How much energy is transferred to thermal energy during the slide? (c) What is the kinetic energy of the rock as it reaches the bottom of the hill? (d) What is its speed then?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.