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Chapter 38: Q6P (page 1181)


What is the photon energy for yellow light from a highway sodium lamp at a wavelength of 589 nm?

Short Answer

Expert verified

The photon energy of the light is 2.1 eV.

Step by step solution

01

Describe the expression of energy of the photon

The energy of a photon of wavelength 位is given by,

E=hc位鈥︹��. (1)

Here, h is Planck鈥檚 constant, and c is the speed of light.

02

Determine the photon energy for yellow light from a highway sodium lamp

Substitute the below values in eq 1.

位=589nmh=6.626脳10-34J.sc=3脳108m/s

Therefore, the photon energy of the light is 2.1 eV.

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Most popular questions from this chapter

Question: An electron moves through a region of the uniform electric potential of -200Vwith a (total) energy of 500eV. What are its (a) kinetic energy (in electron-volts), (b) momentum, (c) speed, (d) de Broglie wavelength, and (e) angular wave number?

What is the wavelength of (a) a photon with energy 1.00eV, (b) an electron with energy 1.00eV, (c) a photon of energy 1.00GeV, and (d) an electron with energy 1.00GeV?

Gamma rays of photon energy 0.511 MeV are directed vonto an aluminium target and are scattered in various directions by loosely bound electrons there.

(a) What is the wavelength of the incident gamma rays?

(b) What is the wavelength of gamma rays scattered at 90鈭�to the incident beam?

(c) What is the photon energy of the rays scattered in this direction?

Show that when a photon of energy Eis scattered from a free electron at rest, the maximum kinetic energy of the recoiling electron is given by

E=E2E+mc2/2

Question: For the arrangement of Figs. 38-14 and 38-15 , electrons in the incident beam in region 1 have energy E=800eV and the potential step has a height of U1=600eV. What is the angular wave number in (a) region 1 and (b) region 2 ? (c) What is the reflection coefficient? (d) If the incident beam sends 500脳105electrons against the potential step, approximately how many will be reflected?

Fig 38-14

Fig 38-15
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