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The Sun is approximately an ideal blackbody radiator with surface temperature of 5800 K.

(a) Find the wavelength at which its spectral radiancy is maximum and

(b) identify the type of magnetic wave corresponding to that wavelength.

(c) As we shall discuss in chapter 44, the universe is approximately an ideal blackbody radiator with radiation emitted when atoms first formed. Today the spectral radiancy of that radiation peaks at a wavelength of 1.06 mm (in the microwave region). What is the corresponding temperature of the universe?

Short Answer

Expert verified

Thus, (a) the wavelength of spectral radiancy is maximum at 0.0388 n³¾.

(b) the wavelength is 1.24 â¶Ä‹n³¾.

(c) the wavelength of neutron is 9.06×10−13 m.

Step by step solution

01

(a) The wavelength of spectral radiancy is maximum.

Use the value hc=1240​e³Õâ‹…nmformula then it gives;

λ=hp=h2meK=hc2mec2K=12402(511000)(1000)=0.0388 n³¾

Hence, the wavelength of spectral radiancy is maximum at 0.0388 n³¾.

02

(b) The type of magnetic wave corresponding to the wavelength.

A photon’s de Broglie wavelength is equal to its familiar wave relationship value. Use the value hc=1240​e³Õâ‹…nmgives:

λ=hcE=1240eV⋅ nm1.00 keV=1.24 â¶Ä‹n³¾

Hence, the wavelength is 1.24 â¶Ä‹n³¾.

03

(c) The corresponding temperature of universe.

The neutron mass equals to 1.675×10−27kg. Using the conversion from electronvolts to Joules gives;

λ=h2mnK=−(6.63×10−34J⋅s)2(1.675×10−27kg)(1.6×10−16J)=9.06×10−13 m

Hence, the wavelength of neutron is 9.06×10−13 m.

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