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Chapter 38: Q2P (page 1181)

How fast must an electron move to have a kinetic energy equal to the photon energy of sodium light at wavelength 590 nm?

Short Answer

Expert verified

The speed of the electron is 8.6脳105m/s.

Step by step solution

01

Describe the expression for the kinetic energy of the electron and energy of the photon

The expression for kinetic energy of the electron is given by,

K=12mv2

Here, m is the mass of an electron, and v is the speed of the electron.

Combine the above two equations.

E=hc位

Here, h is the Planck鈥檚 constant, c is the speed of the light, and 位is the wavelength.

02

Determine the speed of the electron

The energy of the photon is equal to the kinetic energy of the electron.

鈥︹�� (1)

Substitute below values in equation 1.

m=9.1脳10-3Kg位=590nmh=6.626脳10-34J/sc=3脳108m/s

Therefore, the speed of the electron is8.6脳105m/s

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Most popular questions from this chapter

X rays of wavelength 0.0100 nm are directed in the positive direction of an axis onto a target containing loosely bound electrons. For Compton scattering from one of those electrons, at an angle of 180掳,what are (a) the Compton shift, (b) the corresponding change in photon energy, (c) the kinetic energy of the recoiling electron, and (d) the angle between the positive direction of the axis and the electron鈥檚 direction of motion?

Figure 38-24 shows an electron moving through several regions where uniform electric potentials V have been set up. Rank the three regions according to the de Broglie wavelength of the electron there, greatest first.

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