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Chapter 38: Q22P (page 1182)

The wavelength associated with the cutoff frequency for silver is 325nm. Find the maximum kinetic energy of electrons ejected from a silver surface by ultraviolet light of wavelength 254nm.

Short Answer

Expert verified

The maximum kinetic energy is 1.07 eV.

Step by step solution

01

Identification of the given data:

The given data is listed below.

The wavelength of silver is 位S=325nm

The wavelength of ultraviolet light is位U=254nm

02

Significance of the kinetic energy of a particle

The kinetic energy is a scalar and it is always positive or zero.

03

To determine the maximum kinetic energy of electrons ejected from a silver surface by ultraviolet light

The value of hc is define by,

hc = 1240 eV. nm

Now, kinetic energy is given by-

Kmax=Ephoton-蠒=hc位U-hc位S

Substitute known values in the above equation.

Kmax=1240eV路nm254nm-1240eV路nm325nm=1.07eV

Hence, themaximum kinetic energy of electrons ejected from a silver surface by ultraviolet light is 1.07 eV.

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Most popular questions from this chapter

In an old-fashioned television set, electrons are accelerated through a potential difference of 25.0kV. What is the de Broglie wavelength of such electrons? (Relativity is not needed.)

What are

(a) the Compton shift 螖位,

(b) the fractional Compton shift螖位位 , and

(c) the change螖E in photon energy for light of wavelength 位=590鈥�nmscattering from a free, initially stationary electron if the scattering is at to the direction of the incident beam? What are

(d) 螖位,

(e) 螖位位, and

(f) 螖Efor90鈭� scattering for photon energy 50.0 keV (x-ray range)?

Assuming that your surface temperature is98.6掳鈥塅and that you are an ideal blackbody radiator (you are close), find

(a) the wavelength at which your spectral radiancy is maximum,

(b) the power at which you emit thermal radiation in a wavelength range of 1.00鈥�nmat that wavelength, from a surface area of4.00鈥塩尘2, and

(c) the corresponding rate at which you emit photons from that area. Using a wavelength of500鈥�nm (in the visible range),

(d) recalculate the power and

(e) the rate of photon emission. (As you have noticed, you do not visibly glow in the dark.)

In about 1916, R. A. Millikan found the following stopping potential data for lithium in his photoelectric experiments:

Wavelength (nm)

433.9

404.7

365.0

312.5

253.5

Stopping potential (V)

0.55

0.73

1.09

1.67

2.57

Use these data to make a plot like Fig. 38-2 (which is for sodium) and then use the plot to find (a) the Planck constant and (b) the work function for lithium.

Question: An electron moves through a region of the uniform electric potential of -200Vwith a (total) energy of 500eV. What are its (a) kinetic energy (in electron-volts), (b) momentum, (c) speed, (d) de Broglie wavelength, and (e) angular wave number?
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