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For Equationx=xmcos(Ó¬t+Ï•), suppose the amplitudexmis given by

xm=Fm[m2(Ӭd2−Ӭ2)2+b2Ӭd2]1/2

whereFmis the (constant) amplitude of the external oscillating force exerted on the spring by the rigid support in Figure below. At resonance,

  1. what is the amplitude of the oscillating object?
  2. what is the velocity amplitude of the oscillating object?

Short Answer

Expert verified
  1. The amplitude of oscillation at resonance,
    xm=FmbÓ¬
  2. The velocity amplitude of oscillation at resonance,
    vm=Fmb

Step by step solution

01

Given

The amplitude is given as-

xm=Fm[m2(Ӭd2−Ӭ2)2+b2Ӭd2]12

02

Understanding the concept

Use the condition of resonancefor damped oscillation in the given equation to get the required derivation for amplitude and velocity amplitude.

Formulae:

vm=Ó¬xmÓ¬d=Ó¬

03

(a) Calculate the amplitude of the oscillating object

The given equation of amplitude is

xm=Fm[m2(Ӭd2−Ӭ2)2+b2Ӭd2]12

Also, the condition for resonance is

Ó¬d=Ó¬

Using this equation in the above equation of amplitude, we get

xm=Fm[0+b2Ó¬d2]12xm=FmbÓ¬

04

(b) Calculate the velocity amplitude of the oscillating object

The equation for velocity amplitude is

vm=Ó¬xm

Hence,

vm=Ӭ×FmbӬvm=Fmb

The velocity amplitude for the oscillating object is vm=Fmb.

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