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Chapter 42: Q7Q (page 1301)

The nuclide244Pu(Z=94)is an alpha-emitter. Into which of the following nuclides does it decay:240Np(Z=93),240U(Z=92),248Cm(Z=96)or244Am(Z=95)?

Short Answer

Expert verified

The nuclide 244Pu(Z=94)will decay into 240U(Z=92)through the alpha decay process.

Step by step solution

01

The given data

The nuclide 244Pu(Z=94)is an alpha-emitter.

02

Understanding the concept of alpha decay  

Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and thereby transforms or 'decays' into a different atomic nucleus, with a mass number that is reduced by four and an atomic number that is reduced by two.

03

Calculation of the product nuclide

Alpha decay of aZAnuclide can be given as:

role="math" localid="1661572189065" zAM鈫�z-2A-4N+24He(伪-particle)

The nuclide244Pu(Z=94)undergoes an alpha decay that can be given using the concept as:94244Pu鈫�92A-4N+24He(伪-particle)

Hence, plutonium-244 decays into uranium-240 240U(Z=92).

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Most popular questions from this chapter

A neutron star is a stellar object whose density is about that of nuclear matter,2脳1017kg/m3 . Suppose that the Sun were to collapse and become such a star without losing any of its present mass. What would be its radius?

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