91Ó°ÊÓ

1. The velocity of the boat relative to water is$v_{bw}=14km/h$

2. The velocity of water relative to the ground is$v_{wg}=-9.0km/h$

The velocity of the child relative to the boat is$v_{cb}=-6.0km/h$

The term "relative motion" refers to the comparison of the relative accelerations and velocities of two rigid bodies. The boat is traveling along positive x-direction relative to water, and the water is flowing relative to the ground. Hence, according to the relative motion concept, we can find the boat’s velocity relative to the ground.

Formula:

$$\begin{gathered} v_{bg}=v_{bw}+v_{wg} \\ {v}_{cb}=v_{cb}+c_{bg} \end{gathered}$$

According to the equation of relative motion,

$$\begin{gathered} v_{bg}=v_{bw}+v_{wg} \\ =\left(14km/h\right)+\left(-9.0km/h\right) \\ =5.00km/h \end{gathered}$$

The magnitude of the boat’s velocity with respect to ground is $5.00km/h$.

The direction of the boat’s velocity with respect to the ground is positive that is upstream.

According to the relative motion,

$$\begin{gathered} v_{cg}=v_{cb}+v_{bg} \\ =\left(-6.0km/h\right)+\left(5.0km/h\right) \\ =-1.0km/h \end{gathered}$$

So, the magnitude of the child’s velocity with respect to the ground is $1.0km/h$

The direction of the child’s velocity with respect to the ground$v_{cg}$ is negative that is downstream.