/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q25P The current world-record motorcy... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The current world-record motorcycle jump is 77.0m, set by Jason Renie. Assume that he left the take-off ramp at12.0° to the horizontal and that the take-off and landing heights are the same. Neglecting air drag, determine his take-off speed.

Short Answer

Expert verified

The take-off speed of the Jason Renie’ is v0=43.1m/s

Step by step solution

01

Given information

Projection angle with horizontal is∆=120

Range is given as R=77.0m

02

To understand the concept

This problem deals with the horizontal range of the particle which is nothing but the horizontal distance from the launch point at which the particle returns to the launch height. Using the formula for the range of the particle, take -off speed of the Jason Renie’s motorcycle can be found.

Formula:

The particle’s horizontal range can be given as,

R=v02gsin2∆ (i)

Where v0is the initial velocity of the particle.

03

To find the take-off speed 

Using equation (i) the take-off speed can be written as,

v0=Rgsin2∆

v0=77.0m9.8m/s2sin2(12.0°)

Thus, the take=off speed is v0=43.1m/s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Curtain of death.A large metallic asteroid strikes Earth and quickly digs a crater into the rocky material below ground level by launching rocks upward and outward. The following table gives five pairs of launch speeds and angles (from the horizontal) for such rocks, based on a model of crater formation. (Other rocks, with intermediate speeds and angles, are also launched.) Suppose that you are at x=20 kmwhen the asteroid strikes the ground at time t=0nd position x=0(Fig. 4-52). (a) At t=20 s, what are the xand y coordinates of the rocks headed in your direction from launches A through E? (b) Plot these coordinates and then sketch a curve through the points to include rocks with intermediate launch speeds and angles.The curve should indicate what you would see as you look up into the approaching rocks.

A suspicious-looking man runs as fast as he can along a moving sidewalk from one end to the other, taking 2.50s. Then security agents appear, and the man runs as fast as he can back along the sidewalk to his starting point, taking 10.0s. What is the ratio of the man’s running speed to the sidewalk’s speed?

A plane flies 483kmeast from city A to city B in45minand then966Kmsouth from city B to city C in1,5h. For the total trip, what are the (a)magnitude and(b)direction of the plane’s displacement, the(c)magnitude and(d)direction of the average velocity, and(e)it’s average speed?

A woman who can row a boat at 6.4 km/hin still water faces a long, straight river with a width of 6.4 km and a current of 3.2 km/h.i^ Letpoint directly across the river andj^point directly downstream. If she rows in a straight line to a point directly opposite her starting position, (a) at what angle toi^must she point the boat and (b) how long will she take? (c) How long will she take if, instead, she rowsdownthe river and then back to her starting point? (d) How long if she rows 3.2 kmupthe river and then back to her starting point? (e) At what angle toi^should she point the boat if she wants to cross the river in the shortest possible time? (f) How long is that shortest time?

In basketball, hang is an illusion in which a player seems to weaken the gravitational acceleration while in mid-air. The illusion depends much on a skilled player’s ability to rapidly shift the ball between hands during the flight, but it might also be supported by the longer horizontal distance the player travels in the upper part of the jump than in the lower part. If a player jumps with an initial speed ofvo=7.00m/sat an angle of θo=35.0°, what percent of the jump’s range does the player spend in the upper half of the jump (between maximum height and half maximum height)?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.