/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q9Q In Fig 2-22, a cream tangerine i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Fig 2-22, a cream tangerine is thrown directly upward past three evenly spaced windows of equal heights. Rank the windows according to (a) the average speed of the cream tangerine while passing them (b) the time the cream tangerine takes to pass them, (c) the magnitude of the acceleration of cream tangerine while passing them and (d) the changein the speed of cream tangerine during the passage, greatest first.

Short Answer

Expert verified

(a) The descending order of windows according to the average speed of the cream tangerine while passing them is as,3,2,1

(b) The descending order of windows according to the time the cream tangerine takes while passing them is as, 1,,2,3

(c) The descending order of windows according to the acceleration of the cream tangerine while passing them is as, the acceleration while passing all windows is the same.

(d) The descending order of windows according to the change in the speed of the cream tangerine while passing them is as, 1,2,3

Step by step solution

01

Given information

Evenly spaced windows in figure 2.22.

02

Constant Acceleration

The problem deals with the constant acceleration which is the rate of change of velocity with respect to time. When the velocity of an object changes at a constant rate, this rate is called constant acceleration.

03

(a) To rank the windows according to the average speed

As an object moves upwards, its speed goes on decreasing. This means the distance covered in unit time goes on decreasing. So, the descending order of windows according to the average speed of the cream tangerine while passing them is 3,2,1 .

04

(b) To rank the windows according to the time

As an object moves upwards, its speed goes on decreasing. This means the time required to cover a unit distance goes on increasing. So, the descending order of windows according to the time the cream tangerine takes while passing them is 1,2,3

05

(c) To rank the windows according to the magnitude of the acceleration

The only force acting on the tangerine is the force due to gravity (neglecting air resistance). So, its acceleration is constant, equal to -g. Thus, the acceleration while passing all windows is the same.

06

(d) To rank the windows according to the change in speed ∆v

v=a∆tIn this case, a is constant and equal to –g. As the tangerine moves upwards, its speed goes on decreasing, and the time required to cover a unit distance goes on increasing. The descending order of windows according to the change in the speed of the cream tangerine while passing them is then 1,2,3 .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: A proton moves along theaxis according to the equation x = 50t + 10t2 , where xis in meters and tis in seconds. Calculate (a) the average velocity of the proton during the first 3.0 sof its motion, (b) the instantaneous velocity of the proton at t = 3.0 s, and (c) the instantaneous acceleration of the proton at t = 3.0 s . (d) Graph xversus tand indicate how the answer to (a) can be obtained from the plot. (e) Indicate the answer to (b) on the graph. (f) Plotvversus tand indicate on it the answer to (c).

Figure shows a red car and a green car that move toward each other. The other figure is a graph of their motion, showing their positionsxg0=270mand xr035m=-at time t=0.The green car has a constant speed of 20.0 m/sand the red car begins from rest. What is the acceleration magnitude of the red car?


You drive on Interstate 10 from San Antonio to Houston, half the time at 55km/hand other half at90km/h. What is your average speed (a) from San Antonio to Houston? (b) from Houston back to San Antonio? (c) for the entire trip? (d) What is your average velocity for the entire trip? (e) Sketch x vs tfor (a), assuming the motion is all in positive x direction. Indicate how the average velocity can be found on the sketch.

A certain elevator cab has a horizontal run of 190 mand a maximum speed of 305 m/min, and it accelerates from rest and then back to rest at1.22m/s2. (a) How far does the cab move while accelerating to full speed from rest? (b)How long does it take to make the nonstop 190 mrun, starting and ending at rest?

Question:Compute your average velocity in following two cases: (a) You walk 73.2 mat a speed of 1.22 m/sand then run 73.2at a speed of 3.05m/salong a straight track. (b) You walk for1 minat a speed of 1.22m/sand then run for1 min at3.05m/salong a straight track. (c) Graph x versus t for both cases and indicate how the average velocity is found on the graph.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.