91影视

Length of track 1,$L_1=1\mathrm{km}=1000\mathrm{m}$,

Time taken by runner 1,$t_1=2\min ,27.95\sec$

Time taken by runner 2, $t_2=2\min ,28.15\sec$

Speed may be defined as the rate of change of distance with time. The speed of runner 1, when multiplied by the time taken by runner 2, gives the actual length of track 2 to conclude that runner 1 is faster.

The equation for the speed is given as follows:

$\mathrm{Speed}=\frac{\mathrm{Distance}}{\mathrm{Time}}$

Time taken by runner 1 is calculated as follows:

$\begin{array}{c}{t}_1=2脳60+27.95\\ =147.95\mathrm{s}\end{array}$

Time taken by runner 2 is calculated as follows:

$\begin{array}{c}{t}_2=2脳60+28.15\\ =148.15\mathrm{s}\end{array}$

The speed of runner 1 is calculated as follows:

$\begin{array}{c}{v}_1=\frac{L_1}{t_1}\\ =\frac{1000\mathrm{m}}{147.95\mathrm{s}}\\ =6.759\mathrm{m}/\mathrm{s}\end{array}$

Now, the distance covered by runner 2 with this speed is calculated as follows:

role="math" localid="1651842941901" $\begin{array}{c}{L}_2=v_1脳t_2\\ =6.759\mathrm{m}/\mathrm{s}脳148.15\mathrm{s}\\ =1001.35\mathrm{m}\end{array}$

So, the value of $L_2-L_1$is as follows:

$\begin{array}{c}{L}_2-L_1=1001.35\mathrm{m}-1000\mathrm{m}\\ =1.35\mathrm{m}\end{array}$

Thus, the value of $L_2-L_1$to conclude that runner 1 is faster is less than 1.35 m