91Ó°ÊÓ

The position of the particle, ${}^{\mathbf{y}\mathbf{}\mathbf{=}\mathbf{}\left(2.0cm\right)\mathbf{s}\mathbf{i}\mathbf{n}\left(\frac{\mathrm{Ï€³Ù}}{4}\right)}$

The average velocity of an object is the ratio of total displacement to the total time.

Instantaneous velocity is the time rate of change of displacement at the given instant

Average acceleration is the change in velocity for a particular time interval whereas instantaneous acceleration is the time rate of change of velocity at a given instant of time.

The expression for the average velocity is given as follows:

${\mathit{v}}_{\mathbf{a}\mathbf{v}\mathbf{g}}\mathbf{=}\frac{\mathbf{Δ³\ae }}{\mathbf{Δ³Ù}}$ … (i)

Here, ${}^{\mathbf{Δ}\mathbf{x}}$is the net displacement and ${}^{\mathbf{Δ}\mathbf{t}}$is the time interval.

The expression for the instantaneous velocity is given as follows:

$\mathit{v}\mathbf{=}\frac{\mathbf{d}\mathbf{x}}{\mathbf{d}\mathbf{t}}$ … (ii)

The expression for the average acceleration is given as follows:

$a_{\mathbf{avg}}\mathbf{=}\frac{\mathbf{Δ\pm ¹}}{\mathbf{Δ³Ù}}$ … (iii)

The expression for the instantaneous acceleration is given as follows:

$\mathit{a}\mathbf{=}\frac{\mathbf{dv}}{\mathbf{dt}}$ … (iv)

The position of the particle at ${}^{\mathbf{t}\mathbf{=}\mathbf{}\mathbf{0}\mathbf{}\mathbf{s}}$is,

$$\begin{gathered} \mathit{y}\mathbf{=}\left(2.0cm\right)\mathit{s}\mathit{i}\mathit{n}\left(\frac{\mathrm{π}×0}{4}\right) \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{0}\mathbf{}\mathit{c}\mathit{m} \end{gathered}$$

The position of the particle at ${}^{\mathbf{t}\mathbf{=}\mathbf{}\mathbf{2}\mathbf{}\mathbf{s}}$is,

$$\begin{gathered} \mathit{y}\mathbf{=}\mathbf{(}\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{cm}\mathbf{)}\mathit{s}\mathit{i}\mathit{n}\mathbf{\left(}\frac{\mathbf{π}\mathbf{×}\mathbf{2}}{\mathbf{4}}\mathbf{\right)} \\ \mathbf{}\mathbf{}\mathbf{=}\mathbf{(}\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{cm}\mathbf{)}\mathit{s}\mathit{i}\mathit{n}\mathbf{\left(}\frac{\mathbf{π}}{\mathbf{2}}\mathbf{\right)} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{}\mathit{c}\mathit{m} \end{gathered}$$

Using equation (i), the average velocity is calculated as follows:

$$\begin{gathered} {\mathbf{v}}_{\mathbf{avg}}\mathbf{=}\frac{\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{cm}\mathbf{-}\mathbf{0}\mathbf{}\mathbf{c}\mathbf{}\mathbf{m}}{\mathbf{2}\mathbf{}\mathbf{s}\mathbf{-}\mathbf{0}\mathbf{}\mathbf{s}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{cm}\mathbf{/}\mathbf{s} \end{gathered}$$

Thus, the average velocity of the particle between ${}^{\mathbf{t}\mathbf{=}\mathbf{0}}$and ${}^{\mathbf{t}\mathbf{=}\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{}\mathit{s}}$is role="math" localid="1654752865421" ${}^{\mathbf{1}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{cm}\mathbf{/}\mathbf{s}}$.

Using equation (ii), the instantaneous velocity is,

$$\begin{gathered} \mathbf{v}\mathbf{=}\frac{\mathbf{d}}{\mathbf{dt}}\left(\left(2.0\mathrm{cm}\right)\sin \left(\frac{\mathrm{Ï€³Ù}}{4}\right)\right) \\ \mathbf{v}\mathbf{=}\left(\frac{\mathrm{Ï€}}{2}\mathrm{cm}\right)\mathbf{cos}\left(\frac{\mathrm{Ï€³Ù}}{4}\right) \end{gathered}$$

At ${}^{\mathbf{t}\mathbf{=}\mathbf{0}\mathbf{}\mathbf{s}}$the instantaneous velocity is,

$$\begin{gathered} \mathbf{v}\mathbf{=}\mathbf{\left(}\frac{\mathbf{π}}{\mathbf{2}}\mathbf{\right)}\mathbf{cos}\mathbf{\left(}\mathbf{0}\mathbf{\right)}\mathbf{} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{57}\mathbf{}\mathbf{cm}\mathbf{/}\mathbf{s} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{≈}\mathbf{1}\mathbf{.}\mathbf{6}\mathbf{}\mathbf{cm}\mathbf{/}\mathbf{s} \end{gathered}$$

Atthe instantaneous velocity is,

role="math" localid="1654753296911" $$\begin{gathered} \mathbf{v}\mathbf{=}\mathbf{\left(}\frac{\mathbf{Ï€}}{\mathbf{2}}\mathbf{\right)}\mathbf{cos}\mathbf{\left(}\frac{\mathbf{Ï€³Ù}}{\mathbf{2}}\mathbf{\right)} \\ \mathbf{}\mathbf{=}\mathbf{}\mathbf{0}\mathbf{}\mathbf{cm}\mathbf{/}\mathbf{s} \end{gathered}$$

At ${}^{\mathbf{t}\mathbf{=}\mathbf{}\mathbf{2}\mathbf{}\mathbf{s}}$the instantaneous velocity is,

Therefore, the instantaneous velocity of the particle at ${}^{\mathbf{t}\mathbf{}\mathbf{=}\mathbf{o}\mathbf{,}\mathbf{}\mathbf{t}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{s}\mathbf{}\mathbf{a}\mathbf{n}\mathbf{d}\mathbf{}\mathbf{t}\mathbf{=}\mathbf{}\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{s}}$is ${}^{\mathbf{1}\mathbf{.}\mathbf{6}\mathbf{}\mathbf{cm}\mathbf{/}\mathbf{s}}$, ${}^{\mathbf{1}\mathbf{.}\mathbf{1}\mathbf{}\mathbf{cm}\mathbf{/}\mathbf{s}}$and ${}^{\mathbf{0}\mathbf{}\mathbf{cm}\mathbf{/}\mathbf{s}}$respectively.

Using equation (iii), the average acceleration is calculated as follows:

$$\begin{gathered} {\mathbf{a}}_{\mathbf{avg}}\mathbf{=}\frac{\mathbf{v}\left(2.0s\right)\mathbf{-}\mathbf{v}\left(0s\right)}{\mathbf{Δ³Ù}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\frac{\mathbf{0}\mathbf{}\mathbf{cm}\mathbf{/}{\mathbf{s}}^{\mathbf{2}}\mathbf{}\mathbf{-}\mathbf{1}\mathbf{.}\mathbf{57}\mathbf{}\mathbf{cm}\mathbf{/}{\mathbf{s}}^{\mathbf{2}}}{\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{s}\mathbf{}\mathbf{-}\mathbf{}\mathbf{0}\mathbf{}\mathbf{s}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{}\mathbf{-}\mathbf{0}\mathbf{.}\mathbf{79}\mathbf{}\mathbf{cm}\mathbf{/}{\mathbf{s}}^{\mathbf{2}} \end{gathered}$$

Thus, the average acceleration of the particle between${}^{\mathbf{t}\mathbf{=}\mathbf{}\mathbf{0}}$ and ${}^{\mathbf{t}\mathbf{=}\mathbf{}\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{s}}$is${}^{\mathbf{-}\mathbf{0}\mathbf{.}\mathbf{79}\mathbf{}\mathbf{c}\mathbf{m}\mathbf{/}{\mathbf{s}}^{\mathbf{2}}}$

Using equation (iv), the instantaneous acceleration is,

$$\begin{gathered} \mathit{a}\mathbf{=}\frac{\mathbf{d}}{\mathbf{d}\mathbf{t}}\left\{\left(\frac{\mathrm{Ï€}}{2}cm\right)sin\left(\frac{\mathrm{Ï€}}{4}\right)\right\} \\ \mathit{a}\mathbf{=}\mathbf{-}\left(\frac{{\mathrm{Ï€}}^2}{8}cm\right)\mathit{s}\mathit{i}\mathit{n}\left(\frac{\mathrm{Ï€}}{4}\right) \end{gathered}$$

Att= 0 s, the instantaneous acceleration is,

$$\begin{gathered} \mathbf{a}\mathbf{=}\mathbf{-}\mathbf{\left(}\frac{{\mathbf{Ï€}}^{\mathbf{2}}}{\mathbf{8}}\mathbf{cm}\mathbf{\right)}\mathbf{sin}\mathbf{\left(}\mathbf{0}\mathbf{\right)} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{0}\mathbf{}\mathbf{cm}\mathbf{/}{\mathbf{s}}^{\mathbf{2}} \end{gathered}$$

Att= 1 s, the instantaneous acceleration is,

$$\begin{gathered} \mathbf{a}\mathbf{=}\mathbf{-}\mathbf{\left(}\frac{{\mathbf{Ï€}}^{\mathbf{2}}}{\mathbf{8}}\mathbf{cm}\mathbf{\right)}\mathbf{sin}\mathbf{\left(}\frac{\mathbf{Ï€}}{\mathbf{4}}\mathbf{\right)} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{-}\mathbf{0}\mathbf{.}\mathbf{87}\mathbf{}\mathbf{cm}\mathbf{/}{\mathbf{s}}^{\mathbf{2}} \end{gathered}$$

Att= 2 s, the instantaneous acceleration is,

$$\begin{gathered} \mathbf{a}\mathbf{=}\mathbf{-}\mathbf{\left(}\frac{{\mathbf{Ï€}}^{\mathbf{2}}}{\mathbf{8}}\mathbf{cm}\mathbf{\right)}\mathbf{sin}\mathbf{\left(}\frac{\mathbf{Ï€}}{2}\mathbf{\right)} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{-}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{2}\mathbf{}\mathbf{cm}\mathbf{/}{\mathbf{s}}^{\mathbf{2}} \end{gathered}$$

Thus, the instantaneous acceleration of the particle at ${}^{\mathbf{t}\mathbf{=}\mathbf{0}\mathbf{}}$, ${}^{\mathbf{t}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{s}}$and ${}^{\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{s}}$is ${}^{\mathbf{0}\mathbf{}\mathbf{cm}\mathbf{/}{\mathbf{s}}^{\mathbf{2}}\mathbf{,}\mathbf{}\mathbf{-}\mathbf{0}\mathbf{.}\mathbf{87}\mathbf{}\mathbf{cm}\mathbf{/}{\mathbf{s}}^{\mathbf{2}}}$and ${}^{\mathbf{-}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{2}\mathbf{}\mathbf{cm}\mathbf{/}{\mathbf{s}}^{\mathbf{2}}}$respectively.